char lastChar(const char *str){     char last;     //loop over the string and go uptill end of the string \0     while(*str !='\0'){         str++; // increment pointer         last = *str;  //store the current character to the last variable     }          return last; //last character is returned }

Question 1: break phrase Problem statement Breaking a string into two parts based on a delimiter has applications. For example, given an email address, breaking it based on the delimiter "@" gives you the two parts, the mail server's domain name and email username. Another example would be separating a phone number into the area code and the rest. Given a phrase of string and a delimiter string (shorter than the phrase but may be longer than length 1), write a C++ function named break_string to break the phrase into two parts and return the parts as a C++ std::pair object (left part goes to the "first" and right part goes to the "second"). Do the following Write your algorithm as code comments. I recommend to follow UMPIRE technique Implement your function

3. int count(10); while(count >= 0) { count -= 2; std::cout << count << endl;

C++ PLEASE!!       // FILE: simplestring.h// CLASS PROVIDED: string (a sequence of characters)//// CONSTRUCTOR for the string class:// string(const char str[ ] = "") -- default argument is the empty string.// Precondition: str is an ordinary null-terminated string.// Postcondition: The string contains the sequence of chars from str.//// CONSTANT MEMBER FUNCTIONS for the string class:// size_t length( ) const// Postcondition: The return value is the number of characters in the// string.//// char operator [ ](size_t position) const// Precondition: position < length( ).// Postcondition: The value returned is the character at the specified// position of the string. A string's positions start from 0 at the start// of the sequence and go up to length( )-1 at the right end.//// MODIFICATION MEMBER FUNCTIONS for the string class:// void operator +=(const string& addend)// Postcondition: addend has been catenated to the end of the string.//// void operator +=(const char addend[ ])//…