For the following exercises, find the mass of the two-dimensional object that is centered at the origin. 253.A cone-shaped tank has a cross-sectional area that increases with its depth: A = ( π z r 2 h 2 ) / H 3 . Show that the work to empty it is half the work for a cylinder with the same height and base.
For the following exercises, find the mass of the two-dimensional object that is centered at the origin. 253.A cone-shaped tank has a cross-sectional area that increases with its depth: A = ( π z r 2 h 2 ) / H 3 . Show that the work to empty it is half the work for a cylinder with the same height and base.
For the following exercises, find the mass of the two-dimensional object that is centered at the origin.
253.A cone-shaped tank has a cross-sectional area that increases with its depth:
A
=
(
π
z
r
2
h
2
)
/
H
3
. Show that the work to empty it is half the work for a cylinder with the same height and base.
Locate the mass center of the homogeneous solid body whose volume is determined by revolving the shaded area through 360° about
the z-axis.
r
I
Answer: 7 =
315 mm
r = kz³
210 mm
mm
Find the centre of mass of the region of the shaded area as if revolved around the
x-axis, Xcm-
9
y = f(x) = 4√
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, subject and related others by exploring similar questions and additional content below.
Area Between The Curve Problem No 1 - Applications Of Definite Integration - Diploma Maths II; Author: Ekeeda;https://www.youtube.com/watch?v=q3ZU0GnGaxA;License: Standard YouTube License, CC-BY