EBK ORGANIC CHEMISTRY-PRINT COMPANION (
4th Edition
ISBN: 9781119776741
Author: Klein
Publisher: WILEY CONS
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Chapter 2.5, Problem 11PTS
Interpretation Introduction
Interpretation: All the lone pairs associated to nitrogen atoms for the following compound should be drawn.
Concept Introduction The unshared pair of electrons are said to be lone pairs of electrons that are present in an atom of a compound.
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Depending on the protein under study, the bond angle of a drug molecule can become critical to successfully deactivating a viral protein. For this reason, chemists are frequently concerned with the 3D shape of their molecules and their bond angles.
The oxygen atom shown in the structure has a tetrahedral electronic geometry, meaning we would predict that it would have 109.5° bond angles. However, the actual structure, the bond angles are smaller than 109.5°. Explain why this compression occurs. Make sure to discuss what’s happening around/what groups are present around the oxygen atom.
2. From the models of SF4, BrF3, and XeF4, deduce whether different atom arrangement, called
geometrical isomers, are possible; if so, sketch them below. Indicate the preferred geometry
for each case and suggest a reason for your choice. Indicate which structures have dipole
moments and show their direction,
Preferred
Molecular
Compound
Electron
Dipole
Reason
Geometry
Moment
(Polarity) geometry
SF4
BRF3
XeF4
3. Using the Lewis structure predict the geometrical structures of the following ions and state
the hybridization of the central atom.
Ion
Electron Geometry
Molecular
Formal Charge
Central Atom
Geometry
of Central
Hybridization
Atom
CO32-
NO3-
BF4
) Bean hexene is an odor compound used in cosmetics and cleaners. It is also known as leguminal. Its formula is:
CH3CH2CHCHCH2CH2OCHCH2CH3
|
OCH3
Please draw a Lewis structure for this compound with CORRECT GEOMETRY (use dashes and wedges!)
Label all pi bonds in the molecule (if there are any)
Indicate the bond angles for the red highlighted section of the molecule. (hint: you may want to keep the main carbon chain in-plane with the page for clarity)
For this question, you don’t need to draw out the orbitals.
Chapter 2 Solutions
EBK ORGANIC CHEMISTRY-PRINT COMPANION (
Ch. 2.1 - Prob. 1LTSCh. 2.1 - Prob. 3ATSCh. 2.2 - Prob. 2LTSCh. 2.2 - Prob. 4PTSCh. 2.2 - Prob. 6ATSCh. 2.4 - Prob. 3LTSCh. 2.4 - Prob. 9ATSCh. 2.5 - Prob. 4LTSCh. 2.5 - Prob. 11PTSCh. 2.9 - Prob. 6LTS
Ch. 2.9 - Prob. 15PTSCh. 2.9 - Prob. 16PTSCh. 2.10 - Prob. 18CCCh. 2.10 - Prob. 19CCCh. 2.10 - Prob. 20CCCh. 2.10 - Prob. 21CCCh. 2.10 - Prob. 22CCCh. 2.10 - Prob. 23CCCh. 2.10 - Prob. 24CCCh. 2.10 - Prob. 25CCCh. 2 - Prob. 34PPCh. 2 - Prob. 35PPCh. 2 - Prob. 36PPCh. 2 - Prob. 37PPCh. 2 - Prob. 38PPCh. 2 - Prob. 40PPCh. 2 - Prob. 42PPCh. 2 - Prob. 43PPCh. 2 - Prob. 44PPCh. 2 - Prob. 45PPCh. 2 - Prob. 46PPCh. 2 - Prob. 47PPCh. 2 - Prob. 48PPCh. 2 - Prob. 49PPCh. 2 - Prob. 50PPCh. 2 - Prob. 67ASP
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