GENERAL CHEMISTRY(LL)-W/MASTERINGCHEM.
11th Edition
ISBN: 9780134566030
Author: Petrucci
Publisher: PEARSON
expand_more
expand_more
format_list_bulleted
Question
Chapter 24, Problem 50IAE
Interpretation Introduction
Interpretation:
The statement is to be verified by assuming the value of total metal ion concentrations for free EDTA.
Concept introduction:
Precipitation is defined as the formation of insoluble solid from the liquid solution. When two more soluble salts react in solution and comes with the solid insoluble product is called as precipitate.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
EXAMPLE: Chromium(III) is slow to react with EDTA (H4Y) and
is therefore determined by back-titration. A pharmaceutical
preparation containing chromium(III) is analyzed by treating a
2.63g sample with 5mL of (0.0103M) EDTA. Following reaction,
the unreacted EDTA is back-titrated with 1.32mL of (0.0112M) zinc
solution. What is the percent chromium chloride in the
pharmaceutical preparation?
An alloy containing Ni, Fe and Cr was analyzed by a complexation titration using EDTA as titrant. A 0.7176 g sample of the alloy was dissolved in HNO3 and diluted to 250 mL in a flask. A 50.00 mL aliquot of the sample, treated with pyrophosphate to mask Fe and Cr, required 26.14 mL of 0.05831 M EDTA to reach the murexide endpoint. A second 50.00 mL aliquot was treated with hexamethylenetetramine to mask Cr and titration with 0.05831 M EDTA required 35.43 mL to reach the murexide endpoint. Finally, a third 50.00 mL aliquot was treated with 50.00 mL of 0.05831 M EDTA and titrated back to the murexide endpoint with 6.21 mL of 0.06316 M Cu(II). the weight percentages of Ni, Fe and Cr in the alloy.
Iron(III) is best determined by addition of excess EDTA, followed by back-titration with
a metal ion that reacts rapidly with EDTA. A 700.0-mg sample is dissolved, 20.00 mL of
0.0500M EDTA is added, and the excess EDTA is titrated with 5.08 mL of 0.0420M
copper(lI). Calculate the percentage of Fe,O, in the sample.
Chapter 24 Solutions
GENERAL CHEMISTRY(LL)-W/MASTERINGCHEM.
Ch. 24 - Prob. 1ECh. 24 - Prob. 2ECh. 24 - Prob. 3ECh. 24 - Write appropriate formulas for the following. a....Ch. 24 - Prob. 5ECh. 24 - Prob. 6ECh. 24 - Prob. 7ECh. 24 - Prob. 8ECh. 24 - Prob. 9ECh. 24 - Prob. 10E
Ch. 24 - Prob. 11ECh. 24 - Prob. 12ECh. 24 - If A, B, C, and D are four different ligands, a....Ch. 24 - Prob. 14ECh. 24 - Prob. 15ECh. 24 - The structures of four complex ions are given....Ch. 24 - Prob. 17ECh. 24 - Prob. 18ECh. 24 - Prob. 19ECh. 24 - In contrast to the case of Co2+ considered in...Ch. 24 - Prob. 21ECh. 24 - Prob. 22ECh. 24 - Prob. 23ECh. 24 - Prob. 24ECh. 24 - Prob. 25ECh. 24 - Prob. 26ECh. 24 - Prob. 27ECh. 24 - Prob. 28ECh. 24 - Prob. 29ECh. 24 - Prob. 30ECh. 24 - Prob. 31ECh. 24 - Prob. 32ECh. 24 - Prob. 33ECh. 24 - Prob. 34ECh. 24 - Prob. 35ECh. 24 - Prob. 36ECh. 24 - Prob. 37ECh. 24 - Draw dashed and solid wedge diagrams of...Ch. 24 - Prob. 39IAECh. 24 - Prob. 40IAECh. 24 - Prob. 41IAECh. 24 - Prob. 42IAECh. 24 - Prob. 43IAECh. 24 - Prob. 44IAECh. 24 - Prob. 45IAECh. 24 - Prob. 46IAECh. 24 - Prob. 47IAECh. 24 - Prob. 48IAECh. 24 - Prob. 49IAECh. 24 - Prob. 50IAECh. 24 - Prob. 51IAECh. 24 - Prob. 52IAECh. 24 - Prob. 53IAECh. 24 - Prob. 54IAECh. 24 - The compound CoCl22H2O4NH2 may be one of the...Ch. 24 - Prob. 56IAECh. 24 - Provide a valence bond description of the bonding...Ch. 24 - Prob. 58IAECh. 24 - Prob. 59IAECh. 24 - Prob. 60IAECh. 24 - Prob. 61IAECh. 24 - Prob. 62IAECh. 24 - The graph that follows represents the molar...Ch. 24 - Prob. 64FPCh. 24 - Prob. 65FPCh. 24 - The crystal field stabilization energy (CFSE) can...Ch. 24 - In your own words, describe the following terms or...Ch. 24 - Briefly describe each of the following ideas,...Ch. 24 - Prob. 69SAECh. 24 - The oxidation state of Ni in the complex ion...Ch. 24 - Prob. 71SAECh. 24 - Prob. 72SAECh. 24 - Prob. 73SAECh. 24 - Prob. 74SAECh. 24 - Prob. 75SAECh. 24 - The most soluble of the following solids in...Ch. 24 - Prob. 77SAECh. 24 - Write appropriate formulas for the following...Ch. 24 - Prob. 79SAECh. 24 - Prob. 80SAECh. 24 - Prob. 81SAECh. 24 - Prob. 82SAECh. 24 - Prob. 83SAECh. 24 - Prob. 84SAE
Knowledge Booster
Similar questions
- Use the formation constant of [Au(CN)2] in Appendix K to determine the equilibrium concentration of Au+(aq) in a solution that is 0.0071 M CN and 1.1 104 M [Au(CN)2]. Is it reasonable to conclude that 100% of the gold in solution is present as the [Au(CN)2] complex ion? Explain.arrow_forwardTo analyze the amount of iron (Fe; Mw = 55.85 g/mol) contained in an ore sample, the sample was digested with acid and diluted to 50 mL with water. This solution was then treated with 25.00 mL of 0.2922 M EDTA. The excess EDTA was back titrated with 6.47 mL of 0.0843 M Zn2+ to reach the equivalence point. How many grams of Fe contained in the ore sample?arrow_forwardA 0.9352g sample of ore containing Fe³+, Al³+ and Sr²+ was dissolved and made up to 500.00 mL. The analysis of metals was performed using complexation volumetry. Initially, an aliquot of 50.00 mL had its pH adjusted to 1.0 and titrated with a standard 0.03145 mol/L EDTA solution, requiring 6.95 mL to reach the end point. Subsequently, another 25.00 mL aliquot was buffered at pH=5 and titrated with the same EDTA solution, requiring 6.24 mL to reach the end point. Finally, a third aliquot of 25.00 mL was titrated at pH=11, requiring 11.10 mL of the same EDTA solution to complete the titration. Given the molar masses: Fe=55.845 g/mol; Al-26.982 g/mol and Sr-87.620 g/mol. a) Determine the percentage of each of the metals in the sample. b) Explain why the change in pH allows the determination of the three ions in this sample.arrow_forward
- Explain briefly1. In measuring the cell potential of a galvanic cell, what does a negative voltage imply?2. Why is a buffer solution important in the determination of total hardness by EDTA titration? 3. For soda ash samples containing NaOH, Na2CO3, and NaHCO3, why is a NaOH and NaHCO3 mixture not possible?arrow_forward4. The cadmium and lead ions in a 50.00 mL sample required 40.09 mL of a 0.005000 M EDTA for titration. A 75.00 mL portion of the same sample was made basic and treated with excess KCN masking the cadmium as Cd(CN),?. This solution required 21.42 mL of the EDTA for titration. Calculate the concentration of Cd2* and Pb2* in the sample ppm and in M.arrow_forwardThe amount of chloride in a brine solution is determined by the Volhard method. 15 mL 0.1182 M standard AgNO3 solution was added to 10 mL of the solution. Excess silver was back titrated with 0.101 M standard KSCN solution and 2.38 mL KSCN was spent to reach the turning point where the red Fe (SCN) 2+ complex was formed. Which of the following is the chloride concentration in the brine solution in g / L? (Cl: 35.5 g / mol) A. 5.44B. 8.63C. 2.89D. 7.89arrow_forward
- Which of the following salts does NOT cause permanent hardness? A FeCl, B CaCl, © Ca(HCO,), (НСО ,), D MgSO 4arrow_forwardChromel is an alloy composed of nickel, iron, and chromium. A 0.6392-g sample was dissolved and diluted to 250.0 mL. When a 50.00-mL aliquot of 0.05173 M EDTA was mixed with an equal volume of the diluted sample, all three ions were chelated, and a 5.15-mL back-titration with 0.06139 M copper(II) was required. The chromium in a second 50.0-mL aliquot was masked through the addition of hexamethylenetetramine; titration of the Fe and Ni required 34.27 mL of 0.05173 M EDTA. Iron and chromium were masked with pyrophosphate in a third 50.0-mL aliquot, and the nickel was titrated with 24.31 mL of the EDTA solution. Calculate the percentages of nickel, chromium, and iron in the alloy. Percentage of nickel = % Percentage of iron = Percentage of chromium = % 10arrow_forwardA 50.00 mL solution containing Ni2+ and Fe2+ was treated EDTA to bind all the metal ions. After back titration, the amount of EDTA used is 2.500 mmol. In another 50.00 mL solution was added pyrophosphate to mask the Fe2+ ions, and the solution required 25.00 mL of 0.04500 M EDTA. Calculate the ppm Fe (55.85 g/mol) in the solution.arrow_forward
- A Chemist collected a 0.4891-g sample of an ore for Fe determination by a redox titration with K2Cr2O7.The ore was carefully crushed prior to weighing and dissolved in HCl and using a Jones reductor the ironin the sample was brought into the +2 oxidation state. After titration with diphenylamine sulfonic acid,itrequired 36.92 mL of 0.02153 M K2Cr2O7 to reach the end point. Show your solution why 77.86% is the iron content of the ore as %w/w Fe2O3.arrow_forward1.Solution of EDTA is particularly valuable as titrants because the reagent combines with metal ions in a 1:1 ratio regardless of the charge on the cation. For example, Fe(ll) and Fe(lll), complexes are formed with EDTA with great stability. The formation constants for the Fe(ll)-EDTA chelate, and Fe(lll)-EDTA chelate are 2.1 × 1014 and 1.3 × 1025, respectively. a) For each ion complex mentioned above, write the equations of reactions for complex formation and expression for the complex formation constant. b) Calculate the concentration of Fe3+ in a solution that was prepared by mixing 50.0 mL of 0.200 M Fe3+ with 200,0 m of 0.0100 M EDTA. The mixture was buffered to a pH of 11.00. (Given the value of a, = 0.85 at pH 11.00)arrow_forwardA Chemist collected a 0.4891-g sample of an ore for Fe determination by a redox titration with K2Cr2O7.The ore was carefully crushed prior to weighing and dissolved in HCl and using a Jones reductor the ironin the sample was brought into the +2 oxidation state. After titration with diphenylamine sulfonic acid,itrequired 36.92 mL of 0.02153 M K2Cr2O7 to reach the end point. Calculate the iron content of the ore as%w/w Fe2O3arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Chemistry & Chemical ReactivityChemistryISBN:9781337399074Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage Learning
Chemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage Learning
Chemistry & Chemical Reactivity
Chemistry
ISBN:9781337399074
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:Cengage Learning
Chemistry: Principles and Reactions
Chemistry
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:Cengage Learning