General Physics, 2nd Edition
General Physics, 2nd Edition
2nd Edition
ISBN: 9780471522782
Author: Morton M. Sternheim
Publisher: WILEY
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Chapter 24, Problem 29E

(a)

To determine

Where the image is formed by the objective.

(a)

Expert Solution
Check Mark

Answer to Problem 29E

The image formed by the objective is 0.133 m from the objective.

Explanation of Solution

The image formed by the objective is real and inside the focal length of the ocular.

Write the thin lens formula

    1s+1s'=1f        (I)

Here, s is the distance of the object, s' is the distance of the image and f is the focal length.

To find the image distance from ocular lens,

Substitute 0.03 m for f2, 0.25 for s2' in equation (I) to find the value of s2

1s2+1(s2')=1f21s2=1f2+1s2'=10.03 m+10.25 m=(33.33+4) m1

Solving further,

s2=0.027 m

From Figure 24.19, the distance between the lenses,

d=s1'+s2

Here, s1' is the image distance from the objective.

s1'=ds2

Substitute 0.027 m for s2 and 0.16 m for d in the above equation to find the value of s1'

s1'=(0.16 m)(0.027 m)=0.133 m

Conclusion:

The image formed by the objective is 0.133 m from the objective.

(b)

To determine

The distance between the specimen and the objective lens.

(b)

Expert Solution
Check Mark

Answer to Problem 29E

The distance between the specimen and the objective lens is 0.00412 m.

Explanation of Solution

To solve for s1:

Substitute 0.133 m for s1' and 0.004 m for f1 in equation (I) to find the value of s1

1s1+1s1'=1f11s1=1f1+1s1'=10.004 m+10.133 m=(2507.518) m1

Solving further,

s1=0.00412 m

Conclusion:

Thus, the distance between the specimen and the objective lens is 0.00412 m.

(c)

To determine

The magnification of the microscope.

(c)

Expert Solution
Check Mark

Answer to Problem 29E

The magnification of the microscope is 277.83.

Explanation of Solution

Write the expression to find the magnification of the microscope

    M=s1'×0.25 mf1f2

Here, M is the magnification, f1 is the focal length of the objective and f2 is the focal length of the ocular.

Substitute 0.133 m for s1', 0.004 m for f1 and 0.03 m for f2 in the above equation to find the value of M

M=(0.133 m)×0.25 m(0.004 m)(0.03 m)=277.83

The negative sign indicates the image is inverted.

Conclusion:

Thus, the magnification of the microscope is 277.83.

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Chapter 24 Solutions

General Physics, 2nd Edition

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