a. Answer m ∠ V T P = 90 ° Explanation Given information: The four angles of the figure PQRS are right angles. ∠ V T R is a right angle. m ∠ Q S R = 60 . Calculation: From the figure it is observed that, ∠ V T P and ∠ V T R are supplementary angles. m ∠ V T P + m ∠ V T R = 180 ° ⇒ m ∠ V T P + 90 ° = 180 ° [ ∠ V T R is right angle] ⇒ m ∠ V T P = 180 ° − 90 ° ⇒ m ∠ V T P = 90 ° Thus, m ∠ V T P = 90 ° b. To determine To find: The measure of the angle m ∠ X S Y . Answer m ∠ X S Y = 60 ° Explanation Given information: The four angles of the figure PQRS are right angles. ∠ V T R is a right angle. m ∠ Q S R = 60 . Calculation: From the figure it is observed that, ∠ Q S R and ∠ X S Y are vertically opposite angles. Then, m ∠ X S Y = m ∠ Q S R [ ∵ Vertically opposite angles are congruent] ⇒ m ∠ X S Y = 60 ° [ ∵ m ∠ Q S R = 60 ° ] Thus, m ∠ X S Y = 60 ° c. To determine To find: The measure of the angle m ∠ R S X . Answer m ∠ R S X = 120 ° Explanation Given information: The four angles of the figure PQRS are right angles. ∠ V T R is a right angle. m ∠ Q S R = 60 . Calculation: From the figure it is observed that, ∠ Q S R and ∠ R S X are supplementary angles. m ∠ Q S R + m ∠ R S X = 180 ° ⇒ 60 ° + m ∠ R S X = 180 ° [ m ∠ Q S R = 60 ° ] ⇒ m ∠ R S X = 180 ° − 60 ° ⇒ m ∠ R S X = 120 ° Thus, m ∠ R S X = 120 ° d. To determine To find: The measure of the angle m ∠ P S Y . Answer m ∠ P S Y = 90 ° Explanation Given information: The four angles of the figure PQRS are right angles. ∠ V T R is a right angle. m ∠ Q S R = 60 . Calculation: From the figure it is observed that, ∠ P S R and ∠ P S Y are supplementary angles. m ∠ P S R + m ∠ P S Y = 180 ° ⇒ 90 ° + m ∠ P S Y = 180 ° [ m ∠ P S R = 90 ° ] ⇒ m ∠ P S Y = 180 ° − 90 ° ⇒ m ∠ P S Y = 90 ° Thus, m ∠ P S Y = 90 °

McDougal Littell Jurgensen Geometry: Student Edition Geometry

5th Edition

ISBN: 9780395977279

Author: Ray C. Jurgensen, Richard G. Brown, John W. Jurgensen

Publisher: Houghton Mifflin Company College Division

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Question

Chapter 2.4, Problem 20CE

To determine

To find: The measure of the angle m∠VTP .

Expert Solution

Answer to Problem 20CE

m∠VTP=90°

Explanation of Solution

Given information:

The four angles of the figure PQRS are right angles. ∠VTR is a right angle. m∠QSR=60 .

McDougal Littell Jurgensen Geometry: Student Edition Geometry, Chapter 2.4, Problem 20CE , additional homework tip 1

Calculation:

From the figure it is observed that, ∠VTP and ∠VTR are supplementary angles.

m∠VTP+m∠VTR=180°⇒m∠VTP+90°=180° [∠VTR is right angle]⇒m∠VTP=180°−90°⇒m∠VTP=90°

Thus, m∠VTP=90°

To determine

To find: The measure of the angle m∠XSY .

Expert Solution

Answer to Problem 20CE

m∠XSY=60°

Explanation of Solution

Given information:

The four angles of the figure PQRS are right angles. ∠VTR is a right angle. m∠QSR=60 .

McDougal Littell Jurgensen Geometry: Student Edition Geometry, Chapter 2.4, Problem 20CE , additional homework tip 2

Calculation:

From the figure it is observed that, ∠QSR and ∠XSY are vertically opposite angles.

Then,

m∠XSY=m∠QSR [∵Vertically opposite angles are congruent]⇒m∠XSY=60° [∵m∠QSR=60°]

Thus, m∠XSY=60°

To determine

To find: The measure of the angle m∠RSX .

Expert Solution

Answer to Problem 20CE

m∠RSX=120°

Explanation of Solution

Given information:

The four angles of the figure PQRS are right angles. ∠VTR is a right angle. m∠QSR=60 .

McDougal Littell Jurgensen Geometry: Student Edition Geometry, Chapter 2.4, Problem 20CE , additional homework tip 3

Calculation:

From the figure it is observed that, ∠QSR and ∠RSX are supplementary angles.

m∠QSR+m∠RSX=180°⇒60°+m∠RSX=180° [m∠QSR=60°]⇒m∠RSX=180°−60°⇒m∠RSX=120°

Thus, m∠RSX=120°

To determine

To find: The measure of the angle m∠PSY .

Expert Solution

Answer to Problem 20CE

m∠PSY=90°

Explanation of Solution

Given information:

The four angles of the figure PQRS are right angles. ∠VTR is a right angle. m∠QSR=60 .

McDougal Littell Jurgensen Geometry: Student Edition Geometry, Chapter 2.4, Problem 20CE , additional homework tip 4

Calculation:

From the figure it is observed that, ∠PSR and ∠PSY are supplementary angles.

m∠PSR+m∠PSY=180°⇒90°+m∠PSY=180° [m∠PSR=90°]⇒m∠PSY=180°−90°⇒m∠PSY=90°

Thus, m∠PSY=90°

Chapter 2.4, Problem 19CE

Chapter 2.4, Problem 21CE

Chapter 2 Solutions

McDougal Littell Jurgensen Geometry: Student Edition Geometry

Ch. 2.1 - Prob. 1CE Ch. 2.1 - Prob. 2CE Ch. 2.1 - Prob. 3CE Ch. 2.1 - Prob. 4CE Ch. 2.1 - Prob. 5CE Ch. 2.1 - Prob. 6CE Ch. 2.1 - Prob. 7CE Ch. 2.1 - Prob. 8CE Ch. 2.1 - Prob. 9CE Ch. 2.1 - Prob. 10CE

Ch. 2.1 - Prob. 11CE Ch. 2.1 - Prob. 12CE Ch. 2.1 - Prob. 13CE Ch. 2.1 - Prob. 14CE Ch. 2.1 - Prob. 15CE Ch. 2.1 - Prob. 16CE Ch. 2.1 - Prob. 1WE Ch. 2.1 - Prob. 2WE Ch. 2.1 - Prob. 3WE Ch. 2.1 - Prob. 4WE Ch. 2.1 - Prob. 5WE Ch. 2.1 - Prob. 6WE Ch. 2.1 - Prob. 7WE Ch. 2.1 - Prob. 8WE Ch. 2.1 - Prob. 9WE Ch. 2.1 - Prob. 10WE Ch. 2.1 - Prob. 11WE Ch. 2.1 - Prob. 12WE Ch. 2.1 - Prob. 13WE Ch. 2.1 - Prob. 14WE Ch. 2.1 - Prob. 15WE Ch. 2.1 - Prob. 16WE Ch. 2.1 - Prob. 17WE Ch. 2.1 - Prob. 18WE Ch. 2.1 - Prob. 19WE Ch. 2.1 - Prob. 20WE Ch. 2.1 - Prob. 21WE Ch. 2.1 - Prob. 22WE Ch. 2.1 - Prob. 23WE Ch. 2.1 - Prob. 24WE Ch. 2.1 - Prob. 25WE Ch. 2.1 - Prob. 26WE Ch. 2.1 - Prob. 27WE Ch. 2.1 - Prob. 28WE Ch. 2.1 - Prob. 29WE Ch. 2.1 - Prob. 30WE Ch. 2.1 - Prob. 31WE Ch. 2.1 - Prob. 1MRE Ch. 2.1 - Prob. 2MRE Ch. 2.1 - Prob. 3MRE Ch. 2.1 - Prob. 4MRE Ch. 2.2 - Prob. 1CE Ch. 2.2 - Prob. 2CE Ch. 2.2 - Prob. 3CE Ch. 2.2 - Prob. 4CE Ch. 2.2 - Prob. 5CE Ch. 2.2 - Prob. 6CE Ch. 2.2 - Prob. 7CE Ch. 2.2 - Prob. 8CE Ch. 2.2 - Prob. 9CE Ch. 2.2 - Prob. 10CE Ch. 2.2 - Prob. 11CE Ch. 2.2 - Prob. 12CE Ch. 2.2 - Prob. 1WE Ch. 2.2 - Prob. 2WE Ch. 2.2 - Prob. 3WE Ch. 2.2 - Prob. 4WE Ch. 2.2 - Prob. 5WE Ch. 2.2 - Prob. 6WE Ch. 2.2 - Prob. 7WE Ch. 2.2 - Prob. 8WE Ch. 2.2 - Prob. 9WE Ch. 2.2 - Prob. 10WE Ch. 2.2 - Prob. 11WE Ch. 2.2 - Prob. 12WE Ch. 2.2 - Prob. 13WE Ch. 2.2 - Prob. 14WE Ch. 2.2 - Prob. 15WE Ch. 2.3 - Prob. 1CE Ch. 2.3 - Prob. 2CE Ch. 2.3 - Prob. 3CE Ch. 2.3 - Prob. 4CE Ch. 2.3 - Prob. 5CE Ch. 2.3 - Prob. 6CE Ch. 2.3 - Prob. 7CE Ch. 2.3 - Prob. 8CE Ch. 2.3 - Prob. 9CE Ch. 2.3 - Prob. 10CE Ch. 2.3 - Prob. 1WE Ch. 2.3 - Prob. 2WE Ch. 2.3 - Prob. 3WE Ch. 2.3 - Prob. 4WE Ch. 2.3 - Prob. 5WE Ch. 2.3 - Prob. 6WE Ch. 2.3 - Prob. 7WE Ch. 2.3 - Prob. 8WE Ch. 2.3 - Prob. 9WE Ch. 2.3 - Prob. 10WE Ch. 2.3 - Prob. 11WE Ch. 2.3 - Prob. 12WE Ch. 2.3 - Prob. 13WE Ch. 2.3 - Prob. 14WE Ch. 2.3 - Prob. 15WE Ch. 2.3 - Prob. 16WE Ch. 2.3 - Prob. 17WE Ch. 2.3 - Prob. 18WE Ch. 2.3 - Prob. 19WE Ch. 2.3 - Prob. 20WE Ch. 2.3 - Prob. 21WE Ch. 2.3 - Prob. 22WE Ch. 2.3 - Prob. 1E Ch. 2.3 - Prob. 2E Ch. 2.3 - Prob. 3E Ch. 2.3 - Prob. 1ST1 Ch. 2.3 - Prob. 2ST1 Ch. 2.3 - Prob. 3ST1 Ch. 2.3 - Prob. 4ST1 Ch. 2.3 - Prob. 5ST1 Ch. 2.3 - Prob. 6ST1 Ch. 2.3 - Prob. 7ST1 Ch. 2.3 - Prob. 8ST1 Ch. 2.4 - Prob. 1CE Ch. 2.4 - Prob. 2CE Ch. 2.4 - Prob. 3CE Ch. 2.4 - Prob. 4CE Ch. 2.4 - Prob. 5CE Ch. 2.4 - Prob. 6CE Ch. 2.4 - Prob. 7CE Ch. 2.4 - Prob. 8CE Ch. 2.4 - Prob. 9CE Ch. 2.4 - Prob. 10CE Ch. 2.4 - Prob. 11CE Ch. 2.4 - Prob. 12CE Ch. 2.4 - Prob. 13CE Ch. 2.4 - Prob. 14CE Ch. 2.4 - Prob. 15CE Ch. 2.4 - Prob. 16CE Ch. 2.4 - Prob. 17CE Ch. 2.4 - Prob. 18CE Ch. 2.4 - Prob. 19CE Ch. 2.4 - Prob. 20CE Ch. 2.4 - Prob. 21CE Ch. 2.4 - Prob. 1WE Ch. 2.4 - Prob. 2WE Ch. 2.4 - Prob. 3WE Ch. 2.4 - Prob. 4WE Ch. 2.4 - Prob. 5WE Ch. 2.4 - Prob. 6WE Ch. 2.4 - Prob. 7WE Ch. 2.4 - Prob. 8WE Ch. 2.4 - Prob. 9WE Ch. 2.4 - Prob. 10WE Ch. 2.4 - Prob. 11WE Ch. 2.4 - Prob. 12WE Ch. 2.4 - Prob. 13WE Ch. 2.4 - Prob. 14WE Ch. 2.4 - Prob. 15WE Ch. 2.4 - Prob. 16WE Ch. 2.4 - Prob. 17WE Ch. 2.4 - Prob. 18WE Ch. 2.4 - Prob. 19WE Ch. 2.4 - Prob. 20WE Ch. 2.4 - Prob. 21WE Ch. 2.4 - Prob. 22WE Ch. 2.4 - Prob. 23WE Ch. 2.4 - Prob. 24WE Ch. 2.4 - Prob. 25WE Ch. 2.4 - Prob. 26WE Ch. 2.4 - Prob. 27WE Ch. 2.4 - Prob. 28WE Ch. 2.4 - Prob. 29WE Ch. 2.4 - Prob. 30WE Ch. 2.4 - Prob. 31WE Ch. 2.4 - Prob. 32WE Ch. 2.4 - Prob. 33WE Ch. 2.4 - Prob. 34WE Ch. 2.4 - Prob. 35WE Ch. 2.4 - Prob. 1E Ch. 2.4 - Prob. 2E Ch. 2.4 - Prob. 3E Ch. 2.4 - Prob. 4E Ch. 2.5 - Prob. 1CE Ch. 2.5 - Prob. 2CE Ch. 2.5 - Prob. 3CE Ch. 2.5 - Prob. 4CE Ch. 2.5 - Prob. 5CE Ch. 2.5 - Prob. 6CE Ch. 2.5 - Prob. 7CE Ch. 2.5 - Prob. 8CE Ch. 2.5 - Prob. 9CE Ch. 2.5 - Prob. 10CE Ch. 2.5 - Prob. 11CE Ch. 2.5 - Prob. 1WE Ch. 2.5 - Prob. 2WE Ch. 2.5 - Prob. 3WE Ch. 2.5 - Prob. 4WE Ch. 2.5 - Prob. 5WE Ch. 2.5 - Prob. 6WE Ch. 2.5 - Prob. 7WE Ch. 2.5 - Prob. 8WE Ch. 2.5 - Prob. 9WE Ch. 2.5 - Prob. 10WE Ch. 2.5 - Prob. 11WE Ch. 2.5 - Prob. 12WE Ch. 2.5 - Prob. 13WE Ch. 2.5 - Prob. 14WE Ch. 2.5 - Prob. 15WE Ch. 2.5 - Prob. 16WE Ch. 2.5 - Prob. 17WE Ch. 2.5 - Prob. 18WE Ch. 2.5 - Prob. 19WE Ch. 2.5 - Prob. 20WE Ch. 2.5 - Prob. 21WE Ch. 2.5 - Prob. 22WE Ch. 2.5 - Prob. 23WE Ch. 2.5 - Prob. 24WE Ch. 2.5 - Prob. 25WE Ch. 2.5 - Prob. 26WE Ch. 2.5 - Prob. 27WE Ch. 2.5 - Prob. 28WE Ch. 2.5 - Prob. 29WE Ch. 2.5 - Prob. 1MRE Ch. 2.5 - Prob. 2MRE Ch. 2.5 - Prob. 3MRE Ch. 2.5 - Prob. 4MRE Ch. 2.5 - Prob. 5MRE Ch. 2.5 - Prob. 6MRE Ch. 2.5 - Prob. 7MRE Ch. 2.6 - Prob. 1CE Ch. 2.6 - Prob. 2CE Ch. 2.6 - Prob. 3CE Ch. 2.6 - Prob. 4CE Ch. 2.6 - Prob. 5CE Ch. 2.6 - Prob. 6CE Ch. 2.6 - Prob. 7CE Ch. 2.6 - Prob. 8CE Ch. 2.6 - Prob. 9CE Ch. 2.6 - Prob. 10CE Ch. 2.6 - Prob. 1WE Ch. 2.6 - Prob. 2WE Ch. 2.6 - Prob. 3WE Ch. 2.6 - Prob. 4WE Ch. 2.6 - Prob. 5WE Ch. 2.6 - Prob. 6WE Ch. 2.6 - Prob. 7WE Ch. 2.6 - Prob. 8WE Ch. 2.6 - Prob. 9WE Ch. 2.6 - Prob. 10WE Ch. 2.6 - Prob. 11WE Ch. 2.6 - Prob. 12WE Ch. 2.6 - Prob. 13WE Ch. 2.6 - Prob. 14WE Ch. 2.6 - Prob. 15WE Ch. 2.6 - Prob. 16WE Ch. 2.6 - Prob. 17WE Ch. 2.6 - Prob. 18WE Ch. 2.6 - Prob. 19WE Ch. 2.6 - Prob. 20WE Ch. 2.6 - Prob. 21WE Ch. 2.6 - Prob. 22WE Ch. 2.6 - Prob. 23WE Ch. 2.6 - Prob. 24WE Ch. 2.6 - Prob. 25WE Ch. 2.6 - Prob. 1ST2 Ch. 2.6 - Prob. 2ST2 Ch. 2.6 - Prob. 3ST2 Ch. 2.6 - Prob. 4ST2 Ch. 2.6 - Prob. 5ST2 Ch. 2.6 - Prob. 6ST2 Ch. 2.6 - Prob. 7ST2 Ch. 2.6 - Prob. 8ST2 Ch. 2.6 - Prob. 9ST2 Ch. 2.6 - Prob. 1E Ch. 2.6 - Prob. 2E Ch. 2.6 - Prob. 3E Ch. 2.6 - Prob. 4E Ch. 2.6 - Prob. 5E Ch. 2 - Prob. 1CR Ch. 2 - Prob. 2CR Ch. 2 - Prob. 3CR Ch. 2 - Prob. 4CR Ch. 2 - Prob. 5CR Ch. 2 - Prob. 6CR Ch. 2 - Prob. 7CR Ch. 2 - Prob. 8CR Ch. 2 - Prob. 9CR Ch. 2 - Prob. 10CR Ch. 2 - Prob. 11CR Ch. 2 - Prob. 12CR Ch. 2 - Prob. 13CR Ch. 2 - Prob. 14CR Ch. 2 - Prob. 15CR Ch. 2 - Prob. 16CR Ch. 2 - Prob. 17CR Ch. 2 - Prob. 18CR Ch. 2 - Prob. 19CR Ch. 2 - Prob. 20CR Ch. 2 - Prob. 1CT Ch. 2 - Prob. 2CT Ch. 2 - Prob. 3CT Ch. 2 - Prob. 4CT Ch. 2 - Prob. 5CT Ch. 2 - Prob. 6CT Ch. 2 - Prob. 7CT Ch. 2 - Prob. 8CT Ch. 2 - Prob. 9CT Ch. 2 - Prob. 10CT Ch. 2 - Prob. 11CT Ch. 2 - Prob. 12CT Ch. 2 - Prob. 1AR Ch. 2 - Prob. 2AR Ch. 2 - Prob. 3AR Ch. 2 - Prob. 4AR Ch. 2 - Prob. 5AR Ch. 2 - Prob. 6AR Ch. 2 - Prob. 7AR Ch. 2 - Prob. 8AR Ch. 2 - Prob. 9AR Ch. 2 - Prob. 10AR Ch. 2 - Prob. 11AR Ch. 2 - Prob. 12AR Ch. 2 - Prob. 13AR Ch. 2 - Prob. 14AR Ch. 2 - Prob. 15AR Ch. 2 - Prob. 16AR Ch. 2 - Prob. 17AR Ch. 2 - Prob. 18AR Ch. 2 - Prob. 1CUR Ch. 2 - Prob. 2CUR Ch. 2 - Prob. 3CUR Ch. 2 - Prob. 4CUR Ch. 2 - Prob. 5CUR Ch. 2 - Prob. 6CUR Ch. 2 - Prob. 7CUR Ch. 2 - Prob. 8CUR Ch. 2 - Prob. 9CUR Ch. 2 - Prob. 10CUR Ch. 2 - Prob. 11CUR Ch. 2 - Prob. 12CUR Ch. 2 - Prob. 13CUR Ch. 2 - Prob. 14CUR Ch. 2 - Prob. 15CUR Ch. 2 - Prob. 16CUR Ch. 2 - Prob. 17CUR Ch. 2 - Prob. 18CUR Ch. 2 - Prob. 19CUR Ch. 2 - Prob. 20CUR Ch. 2 - Prob. 21CUR Ch. 2 - Prob. 22CUR Ch. 2 - Prob. 23CUR Ch. 2 - Prob. 24CUR Ch. 2 - Prob. 25CUR

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The measure of the angle m ∠ V T P .

Videos

To find: The measure of the angle m∠VTP .

Answer to Problem 20CE

Explanation of Solution

To find: The measure of the angle m∠XSY .

Answer to Problem 20CE

Explanation of Solution

To find: The measure of the angle m∠RSX .

Answer to Problem 20CE

Explanation of Solution

To find: The measure of the angle m∠PSY .

Answer to Problem 20CE

Explanation of Solution

Chapter 2 Solutions

Additional Math Textbook Solutions