McDougal Littell Jurgensen Geometry: Student Edition Geometry
McDougal Littell Jurgensen Geometry: Student Edition Geometry
5th Edition
ISBN: 9780395977279
Author: Ray C. Jurgensen, Richard G. Brown, John W. Jurgensen
Publisher: Houghton Mifflin Company College Division
bartleby

Concept explainers

bartleby

Videos

Question
Book Icon
Chapter 2.3, Problem 12WE
To determine

To sketch :  A geometrical figure which is same as the one given below.

  McDougal Littell Jurgensen Geometry: Student Edition Geometry, Chapter 2.3, Problem 12WE , additional homework tip  1

Expert Solution
Check Mark

Explanation of Solution

Given information :  a geometricalfigure as shown:

  McDougal Littell Jurgensen Geometry: Student Edition Geometry, Chapter 2.3, Problem 12WE , additional homework tip  2

Graph :  Draw a line and mark points L and Nas vertex. Mark a point Msomewhere on line LN . Take a protractor and place its horizontal edge on LNand center on M . Measure PMN from the given figure. Start from zero on the right, read the scale on the protractor and mark the reading equal to PMN. Mark the point P and join MP and thus resulting figure is constructed as below,

  McDougal Littell Jurgensen Geometry: Student Edition Geometry, Chapter 2.3, Problem 12WE , additional homework tip  3

Interpretation :  The resulting figure is same as the given figure.

To determine

To sketch :  The angle bisectors of PMN and LMP by the use of a protractor. The angles PMN and LMP are shown in the figure below,

  McDougal Littell Jurgensen Geometry: Student Edition Geometry, Chapter 2.3, Problem 12WE , additional homework tip  4

Expert Solution
Check Mark

Explanation of Solution

Given information :  Given are two angles PMN and LMP as shown below, whose bisectors are to be constructed by the use of a protractor.

  McDougal Littell Jurgensen Geometry: Student Edition Geometry, Chapter 2.3, Problem 12WE , additional homework tip  5

Graph :  Take a protractor and place its horizontal edge on LNand center on M . Measure LMP from the given figure. Take half of the reading. Start from 1800 on the left, subtract 12 LMP from 1800 and mark O onthat value. MO is the angle bisector of LMPas shown below,

  McDougal Littell Jurgensen Geometry: Student Edition Geometry, Chapter 2.3, Problem 12WE , additional homework tip  6

Again, Measure PMN from the given figure. Start from zero on the right, read the scale on the protractor, take half of the reading of PMN , and mark that point as Q . MQ is the angle bisector of PMN as shown below,

  McDougal Littell Jurgensen Geometry: Student Edition Geometry, Chapter 2.3, Problem 12WE , additional homework tip  7

Thus the two angle bisectors are shown in the figure below.

InterpretationMQ and MO are the angle bisectors of angles PMNand LMP respectively.

To determine

To find :  The measure of OMQ which is formed by the angle bisectors of angles PMNand LMP by the use of a protractor.

  McDougal Littell Jurgensen Geometry: Student Edition Geometry, Chapter 2.3, Problem 12WE , additional homework tip  8

Expert Solution
Check Mark

Answer to Problem 12WE

The measurement of angle OMQ is 900 also shown below.

  McDougal Littell Jurgensen Geometry: Student Edition Geometry, Chapter 2.3, Problem 12WE , additional homework tip  9

Explanation of Solution

Given information :  Angle bisectors MQ and MO bisect PMNand LMP and OMQ is to be measured by a protractor.

  McDougal Littell Jurgensen Geometry: Student Edition Geometry, Chapter 2.3, Problem 12WE , additional homework tip  10

  Place the midpoint of the protractor on M. Align MQ with zero line of the protractor. Read the degrees where MO crosses the number scale the result will be OMQ = 900 .

To determine

To prove :  The measure of OMQwhich is formed by the angle bisectors of angles PMNand LMP is 900 without the use of a protractor.

  McDougal Littell Jurgensen Geometry: Student Edition Geometry, Chapter 2.3, Problem 12WE , additional homework tip  11

Expert Solution
Check Mark

Explanation of Solution

Given information :  Angle bisectors MQ and MO bisect PMNand LMPrespectively .

  McDougal Littell Jurgensen Geometry: Student Edition Geometry, Chapter 2.3, Problem 12WE , additional homework tip  12

Formula used :  Angles on a straight line sum up to 1800 .

An angle bisector is a line which cuts or divides an angle into two equal parts or angles.

Proof :  Angles on a straight line sum up to 1800 , so

  mPMN+mLMP= 1800mPMQ+mQMN+mLMO+mOMP= 1800

Now, MQ and MO bisect PMNand LMP respectively ,

So mPMQ=mQMN ; and mLMO=mOMP .

So, mPMQ+mQMN+mLMO+mOMP=1800 becomes

  2mPMQ+2mOMP=1800mPMQ+mOMP=900mOMQ=900

Hence it can be proved without a protractor that mOMQ=900 .

Chapter 2 Solutions

McDougal Littell Jurgensen Geometry: Student Edition Geometry

Ch. 2.1 - Prob. 11CECh. 2.1 - Prob. 12CECh. 2.1 - Prob. 13CECh. 2.1 - Prob. 14CECh. 2.1 - Prob. 15CECh. 2.1 - Prob. 16CECh. 2.1 - Prob. 1WECh. 2.1 - Prob. 2WECh. 2.1 - Prob. 3WECh. 2.1 - Prob. 4WECh. 2.1 - Prob. 5WECh. 2.1 - Prob. 6WECh. 2.1 - Prob. 7WECh. 2.1 - Prob. 8WECh. 2.1 - Prob. 9WECh. 2.1 - Prob. 10WECh. 2.1 - Prob. 11WECh. 2.1 - Prob. 12WECh. 2.1 - Prob. 13WECh. 2.1 - Prob. 14WECh. 2.1 - Prob. 15WECh. 2.1 - Prob. 16WECh. 2.1 - Prob. 17WECh. 2.1 - Prob. 18WECh. 2.1 - Prob. 19WECh. 2.1 - Prob. 20WECh. 2.1 - Prob. 21WECh. 2.1 - Prob. 22WECh. 2.1 - Prob. 23WECh. 2.1 - Prob. 24WECh. 2.1 - Prob. 25WECh. 2.1 - Prob. 26WECh. 2.1 - Prob. 27WECh. 2.1 - Prob. 28WECh. 2.1 - Prob. 29WECh. 2.1 - Prob. 30WECh. 2.1 - Prob. 31WECh. 2.1 - Prob. 1MRECh. 2.1 - Prob. 2MRECh. 2.1 - Prob. 3MRECh. 2.1 - Prob. 4MRECh. 2.2 - Prob. 1CECh. 2.2 - Prob. 2CECh. 2.2 - Prob. 3CECh. 2.2 - Prob. 4CECh. 2.2 - Prob. 5CECh. 2.2 - Prob. 6CECh. 2.2 - Prob. 7CECh. 2.2 - Prob. 8CECh. 2.2 - Prob. 9CECh. 2.2 - Prob. 10CECh. 2.2 - Prob. 11CECh. 2.2 - Prob. 12CECh. 2.2 - Prob. 1WECh. 2.2 - Prob. 2WECh. 2.2 - Prob. 3WECh. 2.2 - Prob. 4WECh. 2.2 - Prob. 5WECh. 2.2 - Prob. 6WECh. 2.2 - Prob. 7WECh. 2.2 - Prob. 8WECh. 2.2 - Prob. 9WECh. 2.2 - Prob. 10WECh. 2.2 - Prob. 11WECh. 2.2 - Prob. 12WECh. 2.2 - Prob. 13WECh. 2.2 - Prob. 14WECh. 2.2 - Prob. 15WECh. 2.3 - Prob. 1CECh. 2.3 - Prob. 2CECh. 2.3 - Prob. 3CECh. 2.3 - Prob. 4CECh. 2.3 - Prob. 5CECh. 2.3 - Prob. 6CECh. 2.3 - Prob. 7CECh. 2.3 - Prob. 8CECh. 2.3 - Prob. 9CECh. 2.3 - Prob. 10CECh. 2.3 - Prob. 1WECh. 2.3 - Prob. 2WECh. 2.3 - Prob. 3WECh. 2.3 - Prob. 4WECh. 2.3 - Prob. 5WECh. 2.3 - Prob. 6WECh. 2.3 - Prob. 7WECh. 2.3 - Prob. 8WECh. 2.3 - Prob. 9WECh. 2.3 - Prob. 10WECh. 2.3 - Prob. 11WECh. 2.3 - Prob. 12WECh. 2.3 - Prob. 13WECh. 2.3 - Prob. 14WECh. 2.3 - Prob. 15WECh. 2.3 - Prob. 16WECh. 2.3 - Prob. 17WECh. 2.3 - Prob. 18WECh. 2.3 - Prob. 19WECh. 2.3 - Prob. 20WECh. 2.3 - Prob. 21WECh. 2.3 - Prob. 22WECh. 2.3 - Prob. 1ECh. 2.3 - Prob. 2ECh. 2.3 - Prob. 3ECh. 2.3 - Prob. 1ST1Ch. 2.3 - Prob. 2ST1Ch. 2.3 - Prob. 3ST1Ch. 2.3 - Prob. 4ST1Ch. 2.3 - Prob. 5ST1Ch. 2.3 - Prob. 6ST1Ch. 2.3 - Prob. 7ST1Ch. 2.3 - Prob. 8ST1Ch. 2.4 - Prob. 1CECh. 2.4 - Prob. 2CECh. 2.4 - Prob. 3CECh. 2.4 - Prob. 4CECh. 2.4 - Prob. 5CECh. 2.4 - Prob. 6CECh. 2.4 - Prob. 7CECh. 2.4 - Prob. 8CECh. 2.4 - Prob. 9CECh. 2.4 - Prob. 10CECh. 2.4 - Prob. 11CECh. 2.4 - Prob. 12CECh. 2.4 - Prob. 13CECh. 2.4 - Prob. 14CECh. 2.4 - Prob. 15CECh. 2.4 - Prob. 16CECh. 2.4 - Prob. 17CECh. 2.4 - Prob. 18CECh. 2.4 - Prob. 19CECh. 2.4 - Prob. 20CECh. 2.4 - Prob. 21CECh. 2.4 - Prob. 1WECh. 2.4 - Prob. 2WECh. 2.4 - Prob. 3WECh. 2.4 - Prob. 4WECh. 2.4 - Prob. 5WECh. 2.4 - Prob. 6WECh. 2.4 - Prob. 7WECh. 2.4 - Prob. 8WECh. 2.4 - Prob. 9WECh. 2.4 - Prob. 10WECh. 2.4 - Prob. 11WECh. 2.4 - Prob. 12WECh. 2.4 - Prob. 13WECh. 2.4 - Prob. 14WECh. 2.4 - Prob. 15WECh. 2.4 - Prob. 16WECh. 2.4 - Prob. 17WECh. 2.4 - Prob. 18WECh. 2.4 - Prob. 19WECh. 2.4 - Prob. 20WECh. 2.4 - Prob. 21WECh. 2.4 - Prob. 22WECh. 2.4 - Prob. 23WECh. 2.4 - Prob. 24WECh. 2.4 - Prob. 25WECh. 2.4 - Prob. 26WECh. 2.4 - Prob. 27WECh. 2.4 - Prob. 28WECh. 2.4 - Prob. 29WECh. 2.4 - Prob. 30WECh. 2.4 - Prob. 31WECh. 2.4 - Prob. 32WECh. 2.4 - Prob. 33WECh. 2.4 - Prob. 34WECh. 2.4 - Prob. 35WECh. 2.4 - Prob. 1ECh. 2.4 - Prob. 2ECh. 2.4 - Prob. 3ECh. 2.4 - Prob. 4ECh. 2.5 - Prob. 1CECh. 2.5 - Prob. 2CECh. 2.5 - Prob. 3CECh. 2.5 - Prob. 4CECh. 2.5 - Prob. 5CECh. 2.5 - Prob. 6CECh. 2.5 - Prob. 7CECh. 2.5 - Prob. 8CECh. 2.5 - Prob. 9CECh. 2.5 - Prob. 10CECh. 2.5 - Prob. 11CECh. 2.5 - Prob. 1WECh. 2.5 - Prob. 2WECh. 2.5 - Prob. 3WECh. 2.5 - Prob. 4WECh. 2.5 - Prob. 5WECh. 2.5 - Prob. 6WECh. 2.5 - Prob. 7WECh. 2.5 - Prob. 8WECh. 2.5 - Prob. 9WECh. 2.5 - Prob. 10WECh. 2.5 - Prob. 11WECh. 2.5 - Prob. 12WECh. 2.5 - Prob. 13WECh. 2.5 - Prob. 14WECh. 2.5 - Prob. 15WECh. 2.5 - Prob. 16WECh. 2.5 - Prob. 17WECh. 2.5 - Prob. 18WECh. 2.5 - Prob. 19WECh. 2.5 - Prob. 20WECh. 2.5 - Prob. 21WECh. 2.5 - Prob. 22WECh. 2.5 - Prob. 23WECh. 2.5 - Prob. 24WECh. 2.5 - Prob. 25WECh. 2.5 - Prob. 26WECh. 2.5 - Prob. 27WECh. 2.5 - Prob. 28WECh. 2.5 - Prob. 29WECh. 2.5 - Prob. 1MRECh. 2.5 - Prob. 2MRECh. 2.5 - Prob. 3MRECh. 2.5 - Prob. 4MRECh. 2.5 - Prob. 5MRECh. 2.5 - Prob. 6MRECh. 2.5 - Prob. 7MRECh. 2.6 - Prob. 1CECh. 2.6 - Prob. 2CECh. 2.6 - Prob. 3CECh. 2.6 - Prob. 4CECh. 2.6 - Prob. 5CECh. 2.6 - Prob. 6CECh. 2.6 - Prob. 7CECh. 2.6 - Prob. 8CECh. 2.6 - Prob. 9CECh. 2.6 - Prob. 10CECh. 2.6 - Prob. 1WECh. 2.6 - Prob. 2WECh. 2.6 - Prob. 3WECh. 2.6 - Prob. 4WECh. 2.6 - Prob. 5WECh. 2.6 - Prob. 6WECh. 2.6 - Prob. 7WECh. 2.6 - Prob. 8WECh. 2.6 - Prob. 9WECh. 2.6 - Prob. 10WECh. 2.6 - Prob. 11WECh. 2.6 - Prob. 12WECh. 2.6 - Prob. 13WECh. 2.6 - Prob. 14WECh. 2.6 - Prob. 15WECh. 2.6 - Prob. 16WECh. 2.6 - Prob. 17WECh. 2.6 - Prob. 18WECh. 2.6 - Prob. 19WECh. 2.6 - Prob. 20WECh. 2.6 - Prob. 21WECh. 2.6 - Prob. 22WECh. 2.6 - Prob. 23WECh. 2.6 - Prob. 24WECh. 2.6 - Prob. 25WECh. 2.6 - Prob. 1ST2Ch. 2.6 - Prob. 2ST2Ch. 2.6 - Prob. 3ST2Ch. 2.6 - Prob. 4ST2Ch. 2.6 - Prob. 5ST2Ch. 2.6 - Prob. 6ST2Ch. 2.6 - Prob. 7ST2Ch. 2.6 - Prob. 8ST2Ch. 2.6 - Prob. 9ST2Ch. 2.6 - Prob. 1ECh. 2.6 - Prob. 2ECh. 2.6 - Prob. 3ECh. 2.6 - Prob. 4ECh. 2.6 - Prob. 5ECh. 2 - Prob. 1CRCh. 2 - Prob. 2CRCh. 2 - Prob. 3CRCh. 2 - Prob. 4CRCh. 2 - Prob. 5CRCh. 2 - Prob. 6CRCh. 2 - Prob. 7CRCh. 2 - Prob. 8CRCh. 2 - Prob. 9CRCh. 2 - Prob. 10CRCh. 2 - Prob. 11CRCh. 2 - Prob. 12CRCh. 2 - Prob. 13CRCh. 2 - Prob. 14CRCh. 2 - Prob. 15CRCh. 2 - Prob. 16CRCh. 2 - Prob. 17CRCh. 2 - Prob. 18CRCh. 2 - Prob. 19CRCh. 2 - Prob. 20CRCh. 2 - Prob. 1CTCh. 2 - Prob. 2CTCh. 2 - Prob. 3CTCh. 2 - Prob. 4CTCh. 2 - Prob. 5CTCh. 2 - Prob. 6CTCh. 2 - Prob. 7CTCh. 2 - Prob. 8CTCh. 2 - Prob. 9CTCh. 2 - Prob. 10CTCh. 2 - Prob. 11CTCh. 2 - Prob. 12CTCh. 2 - Prob. 1ARCh. 2 - Prob. 2ARCh. 2 - Prob. 3ARCh. 2 - Prob. 4ARCh. 2 - Prob. 5ARCh. 2 - Prob. 6ARCh. 2 - Prob. 7ARCh. 2 - Prob. 8ARCh. 2 - Prob. 9ARCh. 2 - Prob. 10ARCh. 2 - Prob. 11ARCh. 2 - Prob. 12ARCh. 2 - Prob. 13ARCh. 2 - Prob. 14ARCh. 2 - Prob. 15ARCh. 2 - Prob. 16ARCh. 2 - Prob. 17ARCh. 2 - Prob. 18ARCh. 2 - Prob. 1CURCh. 2 - Prob. 2CURCh. 2 - Prob. 3CURCh. 2 - Prob. 4CURCh. 2 - Prob. 5CURCh. 2 - Prob. 6CURCh. 2 - Prob. 7CURCh. 2 - Prob. 8CURCh. 2 - Prob. 9CURCh. 2 - Prob. 10CURCh. 2 - Prob. 11CURCh. 2 - Prob. 12CURCh. 2 - Prob. 13CURCh. 2 - Prob. 14CURCh. 2 - Prob. 15CURCh. 2 - Prob. 16CURCh. 2 - Prob. 17CURCh. 2 - Prob. 18CURCh. 2 - Prob. 19CURCh. 2 - Prob. 20CURCh. 2 - Prob. 21CURCh. 2 - Prob. 22CURCh. 2 - Prob. 23CURCh. 2 - Prob. 24CURCh. 2 - Prob. 25CUR

Additional Math Textbook Solutions

Find more solutions based on key concepts
Knowledge Booster
Background pattern image
Geometry
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, geometry and related others by exploring similar questions and additional content below.
Recommended textbooks for you
Text book image
Elementary Geometry For College Students, 7e
Geometry
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Cengage,
Text book image
Elementary Geometry for College Students
Geometry
ISBN:9781285195698
Author:Daniel C. Alexander, Geralyn M. Koeberlein
Publisher:Cengage Learning
Trigonometric Ratios; Author: The Organic Chemistry Tutor;https://www.youtube.com/watch?v=9-eHMMpQC2k;License: Standard YouTube License, CC-BY