Chapter 2, Problem 14CR

To determine

Measure of the given angle.

Answer to Problem 14CR

Measure of given angle will be ${60}^0$

Explanation of Solution

Given:

Supplementary angle is 4 times as large complimentary angle.

Let the given angle is x.

Then its supplementary angle will be, ${180}^0-x$

And complimentary angle will be, ${90}^0-x$

Now, according to given condition.

  $\begin{array}{l}4\left({90}^0-x\right)=\left({180}^0-x\right)\\ {360}^0-4x={180}^0-x\\ 3x={180}^0\\ x={60}^0\end{array}$

Therefore, measure of given angle will be ${60}^0$