3rd Edition

ISBN: 9781285607160

Author: Larson

Publisher: CENGAGE CO

Concept explainers

When it comes to calculus, limits are considered to be a very important topic of discussion. The main importance of limit lies in expressing the value of a function as it gets closer to a certain value. Also, limits can help you to understand other topic…

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Question

Chapter 2.2, Problem 116E

(a)

To determine

To identify : The degree of function as odd or even, the leading coefficient as positive or negative, then graph the function and the right and left hand behaviour.

(a)

Expert Solution

Explanation of Solution

Given: The function is f(x)=x3−2x2−x+1

According to the leading coefficient test, as x moves without bound to the left or to the right, the graph of the polynomial function f(x)=anxn+...+a1+a0 rises or falls in the following manner.

When n is odd, and the leading coefficient is positive, the graph falls to the left and rises to the right and if the leading coefficient is negative then the graph rises to the left and falls to the right.

When n is even then if the leading coefficient is positive the graph rises to the left and right and if the leading coefficient is negative then the graph falls to the left and right.

Now consider the function.

f(x)=x3−2x2−x+1

The degree of the function is 3 which is odd.

The leading coefficient of the function is 1 which is positive.

The degree of the function is odd and the leading coefficient is positive. So, the graph falls to the left and rises to the right side.

The graph of function is shown in figure below.

EBK PRECALCULUS W/LIMITS, Chapter 2.2, Problem 116E , additional homework tip 1

Figure (1)

(b)

To determine

To identify : The degree of function as odd or even, the leading coefficient as positive or negative, then graph the function and the right and left hand behaviour.

(b)

Expert Solution

Explanation of Solution

Given: The function is f(x)=2x5+2x2−5x+1

According to the leading coefficient test, as x moves without bound to the left or to the right, the graph of the polynomial function f(x)=anxn+...+a1+a0 rises or falls in the following manner.

When n is even then if the leading coefficient is positive the graph rises to the left and right and if the leading coefficient is negative then the graph falls to the left and right.

Now consider the function.

f(x)=2x5+2x2−5x+1

The degree of the function is 5 which is odd.

The leading coefficient of the function is 2 which is positive.

The degree of the function is odd and the leading coefficient is positive. So, the graph falls to the left and rises to the right side.

The graph of function is shown in figure below.

EBK PRECALCULUS W/LIMITS, Chapter 2.2, Problem 116E , additional homework tip 2

Figure (2)

(c)

To determine

To identify : The degree of function as odd or even, the leading coefficient as positive or negative, then graph the function and the right and left hand behaviour.

(c)

Expert Solution

Explanation of Solution

Given: The function is f(x)=−2x5−x2+5x+3

According to the leading coefficient test, as x moves without bound to the left or to the right, the graph of the polynomial function f(x)=anxn+...+a1+a0 rises or falls in the following manner.

When n is even then if the leading coefficient is positive the graph rises to the left and right and if the leading coefficient is negative then the graph falls to the left and right.

Now consider the function.

f(x)=−2x5−x2+5x+3

The degree of the function is 5 which is odd.

The leading coefficient of the function is −2 which is negative.

The degree of the function is odd and the leading coefficient is negative. So, the graph rises to the left and falls to the right side.

The graph of function is shown in figure below.

EBK PRECALCULUS W/LIMITS, Chapter 2.2, Problem 116E , additional homework tip 3

Figure (3)

(d)

To determine

To identify : The degree of function as odd or even, the leading coefficient as positive or negative, then graph the function and the right and left hand behaviour.

(d)

Expert Solution

Explanation of Solution

Given: The function is f(x)=−x3+5x−2

According to the leading coefficient test, as x moves without bound to the left or to the right, the graph of the polynomial function f(x)=anxn+...+a1+a0 rises or falls in the following manner.

When n is even then if the leading coefficient is positive the graph rises to the left and right and if the leading coefficient is negative then the graph falls to the left and right.

Now consider the function.

f(x)=−x3+5x−2

The degree of the function is 3 which is odd.

The leading coefficient of the function is −1 which is negative.

The degree of the function is odd and the leading coefficient is negative. So, the graph rises to the left and falls to the right side.

The graph of function is shown in figure below.

EBK PRECALCULUS W/LIMITS, Chapter 2.2, Problem 116E , additional homework tip 4

Figure (4)

(e)

To determine

To identify : The degree of function as odd or even, the leading coefficient as positive or negative, then graph the function and the right and left hand behaviour.

(e)

Expert Solution

Explanation of Solution

Given: The function is f(x)=2x2+3x−4

According to the leading coefficient test, as x moves without bound to the left or to the right, the graph of the polynomial function f(x)=anxn+...+a1+a0 rises or falls in the following manner.

When n is even then if the leading coefficient is positive the graph rises to the left and right and if the leading coefficient is negative then the graph falls to the left and right.

Now consider the function.

f(x)=2x2+3x−4

The degree of the function is 2 which is even.

The leading coefficient of the function is 2 which is positive.

The degree of the function is even and the leading coefficient is positive. So the graph rises to the left and right.

The graph of function is shown in figure below.

EBK PRECALCULUS W/LIMITS, Chapter 2.2, Problem 116E , additional homework tip 5

Figure (5)

(f)

To determine

To identify : The degree of function as odd or even, the leading coefficient as positive or negative, then graph the function and the right and left hand behaviour.

(f)

Expert Solution

Explanation of Solution

Given: The function is f(x)=x4−3x2+2x−1

According to the leading coefficient test, as x moves without bound to the left or to the right, the graph of the polynomial function f(x)=anxn+...+a1+a0 rises or falls in the following manner.

When n is even then if the leading coefficient is positive the graph rises to the left and right and if the leading coefficient is negative then the graph falls to the left and right.

Now consider the function.

f(x)=x4−3x2+2x−1

The degree of the function is 4 which is even.

The leading coefficient of the function is 1 which is positive.

The degree of the function is even and the leading coefficient is positive. So the graph rises to the left and right.

The graph of function is shown in figure below.

EBK PRECALCULUS W/LIMITS, Chapter 2.2, Problem 116E , additional homework tip 6

Figure (6)

(g)

To determine

To identify : The degree of function as odd or even, the leading coefficient as positive or negative, then graph the function and the right and left hand behaviour.

(g)

Expert Solution

Explanation of Solution

Given: The function is f(x)=x2+3x+2

According to the leading coefficient test, as x moves without bound to the left or to the right, the graph of the polynomial function f(x)=anxn+...+a1+a0 rises or falls in the following manner.

When n is even then if the leading coefficient is positive the graph rises to the left and right and if the leading coefficient is negative then the graph falls to the left and right.

Now consider the function.

f(x)=x2+3x+2

The degree of the function is 2 which is even.

The leading coefficient of the function is 1 which is positive.

The degree of the function is even and the leading coefficient is positive. So the graph rises to the left and right.

The graph of function is shown in figure below.

EBK PRECALCULUS W/LIMITS, Chapter 2.2, Problem 116E , additional homework tip 7

Figure (7)

Chapter 2.2, Problem 115E

Chapter 2.2, Problem 117E

Chapter 2 Solutions

EBK PRECALCULUS W/LIMITS

Ch. 2.1 - Prob. 1E Ch. 2.1 - Prob. 2E Ch. 2.1 - Prob. 3E Ch. 2.1 - Prob. 4E Ch. 2.1 - Prob. 5E Ch. 2.1 - Prob. 6E Ch. 2.1 - Prob. 7E Ch. 2.1 - Prob. 8E Ch. 2.1 - Prob. 9E Ch. 2.1 - Prob. 10E

Ch. 2.1 - Prob. 11E Ch. 2.1 - Prob. 12E Ch. 2.1 - Prob. 13E Ch. 2.1 - Prob. 14E Ch. 2.1 - Prob. 15E Ch. 2.1 - Prob. 16E Ch. 2.1 - Prob. 17E Ch. 2.1 - Prob. 18E Ch. 2.1 - Prob. 19E Ch. 2.1 - Prob. 20E Ch. 2.1 - Prob. 21E Ch. 2.1 - Prob. 22E Ch. 2.1 - Prob. 23E Ch. 2.1 - Prob. 24E Ch. 2.1 - Prob. 25E Ch. 2.1 - Prob. 26E Ch. 2.1 - Prob. 27E Ch. 2.1 - Prob. 28E Ch. 2.1 - Prob. 29E Ch. 2.1 - Prob. 30E Ch. 2.1 - Prob. 31E Ch. 2.1 - Prob. 32E Ch. 2.1 - Prob. 33E Ch. 2.1 - Prob. 34E Ch. 2.1 - Prob. 35E Ch. 2.1 - Prob. 36E Ch. 2.1 - Prob. 37E Ch. 2.1 - Prob. 38E Ch. 2.1 - Prob. 39E Ch. 2.1 - Prob. 40E Ch. 2.1 - Prob. 41E Ch. 2.1 - Prob. 42E Ch. 2.1 - Prob. 43E Ch. 2.1 - Prob. 44E Ch. 2.1 - Prob. 45E Ch. 2.1 - Prob. 46E Ch. 2.1 - Prob. 47E Ch. 2.1 - Prob. 48E Ch. 2.1 - Prob. 49E Ch. 2.1 - Prob. 50E Ch. 2.1 - Prob. 51E Ch. 2.1 - Prob. 52E Ch. 2.1 - Prob. 53E Ch. 2.1 - Prob. 54E Ch. 2.1 - Prob. 55E Ch. 2.1 - Prob. 56E Ch. 2.1 - Prob. 57E Ch. 2.1 - Prob. 58E Ch. 2.1 - Prob. 59E Ch. 2.1 - Prob. 60E Ch. 2.1 - 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Prob. 54E Ch. 2.5 - Prob. 55E Ch. 2.5 - Prob. 56E Ch. 2.5 - Prob. 57E Ch. 2.5 - Prob. 58E Ch. 2.5 - Prob. 59E Ch. 2.5 - Prob. 60E Ch. 2.5 - Prob. 61E Ch. 2.5 - Prob. 62E Ch. 2.5 - Prob. 63E Ch. 2.5 - Prob. 64E Ch. 2.5 - Prob. 65E Ch. 2.5 - Prob. 66E Ch. 2.5 - Prob. 67E Ch. 2.5 - Prob. 68E Ch. 2.5 - Prob. 69E Ch. 2.5 - Prob. 70E Ch. 2.5 - Prob. 71E Ch. 2.5 - Prob. 72E Ch. 2.5 - Prob. 73E Ch. 2.5 - Prob. 74E Ch. 2.5 - Prob. 75E Ch. 2.5 - Prob. 76E Ch. 2.5 - Prob. 77E Ch. 2.5 - Prob. 78E Ch. 2.5 - Prob. 79E Ch. 2.5 - Prob. 80E Ch. 2.5 - Prob. 81E Ch. 2.5 - Prob. 82E Ch. 2.5 - Prob. 83E Ch. 2.5 - Prob. 84E Ch. 2.5 - Prob. 85E Ch. 2.5 - Prob. 86E Ch. 2.5 - Prob. 87E Ch. 2.5 - Prob. 88E Ch. 2.5 - Prob. 89E Ch. 2.5 - Prob. 90E Ch. 2.5 - Prob. 91E Ch. 2.5 - Prob. 92E Ch. 2.5 - Prob. 93E Ch. 2.5 - Prob. 94E Ch. 2.5 - Prob. 95E Ch. 2.5 - Prob. 96E Ch. 2.5 - Prob. 97E Ch. 2.5 - Prob. 98E Ch. 2.5 - Prob. 99E Ch. 2.5 - Prob. 100E Ch. 2.5 - Prob. 101E Ch. 2.5 - Prob. 102E Ch. 2.5 - Prob. 103E Ch. 2.5 - Prob. 104E Ch. 2.5 - Prob. 105E Ch. 2.5 - Prob. 106E Ch. 2.5 - Prob. 107E Ch. 2.5 - Prob. 108E Ch. 2.5 - Prob. 109E Ch. 2.5 - Prob. 110E Ch. 2.5 - Prob. 111E Ch. 2.5 - Prob. 112E Ch. 2.5 - Prob. 113E Ch. 2.5 - Prob. 114E Ch. 2.5 - Prob. 115E Ch. 2.5 - Prob. 116E Ch. 2.5 - Prob. 117E Ch. 2.5 - Prob. 118E Ch. 2.5 - Prob. 119E Ch. 2.5 - Prob. 120E Ch. 2.5 - Prob. 121E Ch. 2.5 - Prob. 122E Ch. 2.5 - Prob. 123E Ch. 2.5 - Prob. 124E Ch. 2.5 - Prob. 125E Ch. 2.5 - Prob. 126E Ch. 2.5 - Prob. 127E Ch. 2.5 - Prob. 128E Ch. 2.5 - Prob. 129E Ch. 2.5 - Prob. 130E Ch. 2.5 - Prob. 131E Ch. 2.6 - Prob. 1E Ch. 2.6 - Prob. 2E Ch. 2.6 - Prob. 3E Ch. 2.6 - Prob. 4E Ch. 2.6 - Prob. 5E Ch. 2.6 - Prob. 6E Ch. 2.6 - Prob. 7E Ch. 2.6 - Prob. 8E Ch. 2.6 - Prob. 9E Ch. 2.6 - Prob. 10E Ch. 2.6 - Prob. 11E Ch. 2.6 - Prob. 12E Ch. 2.6 - Prob. 13E Ch. 2.6 - Prob. 14E Ch. 2.6 - Prob. 15E Ch. 2.6 - Prob. 16E Ch. 2.6 - Prob. 17E Ch. 2.6 - Prob. 18E Ch. 2.6 - Prob. 19E Ch. 2.6 - Prob. 20E Ch. 2.6 - Prob. 21E Ch. 2.6 - Prob. 22E Ch. 2.6 - Prob. 23E Ch. 2.6 - Prob. 24E Ch. 2.6 - Prob. 25E Ch. 2.6 - Prob. 26E Ch. 2.6 - Prob. 27E Ch. 2.6 - Prob. 28E Ch. 2.6 - Prob. 29E Ch. 2.6 - Prob. 30E Ch. 2.6 - Prob. 31E Ch. 2.6 - Prob. 32E Ch. 2.6 - Prob. 33E Ch. 2.6 - Prob. 34E Ch. 2.6 - Prob. 35E Ch. 2.6 - Prob. 36E Ch. 2.6 - Prob. 37E Ch. 2.6 - Prob. 38E Ch. 2.6 - Prob. 39E Ch. 2.6 - Prob. 40E Ch. 2.6 - Prob. 41E Ch. 2.6 - Prob. 42E Ch. 2.6 - Prob. 43E Ch. 2.6 - Prob. 44E Ch. 2.6 - Prob. 45E Ch. 2.6 - Prob. 46E Ch. 2.6 - Prob. 47E Ch. 2.6 - Prob. 48E Ch. 2.6 - Prob. 49E Ch. 2.6 - Prob. 50E Ch. 2.6 - Prob. 51E Ch. 2.6 - Prob. 52E Ch. 2.6 - Prob. 53E Ch. 2.6 - Prob. 54E Ch. 2.6 - Prob. 55E Ch. 2.6 - Prob. 56E Ch. 2.6 - Prob. 57E Ch. 2.6 - Prob. 58E Ch. 2.6 - Prob. 59E Ch. 2.6 - Prob. 60E Ch. 2.6 - Prob. 61E Ch. 2.6 - Prob. 62E Ch. 2.6 - Prob. 63E Ch. 2.6 - Prob. 64E Ch. 2.6 - Prob. 65E Ch. 2.6 - Prob. 66E Ch. 2.6 - Prob. 67E Ch. 2.6 - Prob. 68E Ch. 2.6 - Prob. 69E Ch. 2.6 - Prob. 70E Ch. 2.6 - Prob. 71E Ch. 2.6 - Prob. 72E Ch. 2.6 - Prob. 73E Ch. 2.6 - Prob. 74E Ch. 2.6 - Prob. 75E Ch. 2.6 - Prob. 76E Ch. 2.6 - Prob. 77E Ch. 2.6 - Prob. 78E Ch. 2.6 - Prob. 79E Ch. 2.6 - Prob. 80E Ch. 2.6 - Prob. 81E Ch. 2.6 - Prob. 82E Ch. 2.7 - Prob. 1E Ch. 2.7 - Prob. 2E Ch. 2.7 - Prob. 3E Ch. 2.7 - Prob. 4E Ch. 2.7 - Prob. 5E Ch. 2.7 - Prob. 6E Ch. 2.7 - Prob. 7E Ch. 2.7 - Prob. 8E Ch. 2.7 - Prob. 9E Ch. 2.7 - Prob. 10E Ch. 2.7 - Prob. 11E Ch. 2.7 - Prob. 12E Ch. 2.7 - Prob. 13E Ch. 2.7 - Prob. 14E Ch. 2.7 - Prob. 15E Ch. 2.7 - Prob. 16E Ch. 2.7 - Prob. 17E Ch. 2.7 - Prob. 18E Ch. 2.7 - Prob. 19E Ch. 2.7 - Prob. 20E Ch. 2.7 - Prob. 21E Ch. 2.7 - Prob. 22E Ch. 2.7 - Prob. 23E Ch. 2.7 - Prob. 24E Ch. 2.7 - Prob. 25E Ch. 2.7 - Prob. 26E Ch. 2.7 - Prob. 27E Ch. 2.7 - Prob. 28E Ch. 2.7 - Prob. 29E Ch. 2.7 - Prob. 30E Ch. 2.7 - Prob. 31E Ch. 2.7 - Prob. 32E Ch. 2.7 - Prob. 33E Ch. 2.7 - Prob. 34E Ch. 2.7 - Prob. 35E Ch. 2.7 - Prob. 36E Ch. 2.7 - Prob. 37E Ch. 2.7 - Prob. 38E Ch. 2.7 - Prob. 39E Ch. 2.7 - Prob. 40E Ch. 2.7 - Prob. 41E Ch. 2.7 - Prob. 42E Ch. 2.7 - Prob. 43E Ch. 2.7 - Prob. 44E Ch. 2.7 - Prob. 45E Ch. 2.7 - Prob. 46E Ch. 2.7 - Prob. 47E Ch. 2.7 - Prob. 48E Ch. 2.7 - Prob. 49E Ch. 2.7 - Prob. 50E Ch. 2.7 - Prob. 51E Ch. 2.7 - Prob. 52E Ch. 2.7 - Prob. 53E Ch. 2.7 - Prob. 54E Ch. 2.7 - Prob. 55E Ch. 2.7 - Prob. 56E Ch. 2.7 - Prob. 57E Ch. 2.7 - Prob. 58E Ch. 2.7 - Prob. 59E Ch. 2.7 - Prob. 60E Ch. 2.7 - Prob. 61E Ch. 2.7 - Prob. 62E Ch. 2.7 - Prob. 63E Ch. 2.7 - Prob. 64E Ch. 2.7 - Prob. 65E Ch. 2.7 - Prob. 66E Ch. 2.7 - Prob. 67E Ch. 2.7 - Prob. 68E Ch. 2.7 - Prob. 69E Ch. 2.7 - Prob. 70E Ch. 2.7 - Prob. 71E Ch. 2.7 - Prob. 72E Ch. 2.7 - Prob. 73E Ch. 2.7 - Prob. 74E Ch. 2.7 - Prob. 75E Ch. 2.7 - Prob. 76E Ch. 2.7 - Prob. 77E Ch. 2.7 - Prob. 78E Ch. 2.7 - Prob. 79E Ch. 2.7 - Prob. 80E Ch. 2.7 - Prob. 81E Ch. 2.7 - Prob. 82E Ch. 2.7 - Prob. 83E Ch. 2.7 - Prob. 84E Ch. 2.7 - Prob. 85E Ch. 2.7 - Prob. 86E Ch. 2.7 - Prob. 87E Ch. 2.7 - Prob. 88E Ch. 2.7 - Prob. 89E Ch. 2.7 - Prob. 90E Ch. 2 - Prob. 1RE Ch. 2 - Prob. 2RE Ch. 2 - Prob. 3RE Ch. 2 - Prob. 4RE Ch. 2 - Prob. 5RE Ch. 2 - Prob. 6RE Ch. 2 - Prob. 7RE Ch. 2 - Prob. 8RE Ch. 2 - Prob. 9RE Ch. 2 - Prob. 10RE Ch. 2 - Prob. 11RE Ch. 2 - Prob. 12RE Ch. 2 - Prob. 13RE Ch. 2 - Prob. 14RE Ch. 2 - Prob. 15RE Ch. 2 - Prob. 16RE Ch. 2 - Prob. 17RE Ch. 2 - Prob. 18RE Ch. 2 - Prob. 19RE Ch. 2 - Prob. 20RE Ch. 2 - Prob. 21RE Ch. 2 - Prob. 22RE Ch. 2 - Prob. 23RE Ch. 2 - Prob. 24RE Ch. 2 - Prob. 25RE Ch. 2 - Prob. 26RE Ch. 2 - Prob. 27RE Ch. 2 - Prob. 28RE Ch. 2 - Prob. 29RE Ch. 2 - Prob. 30RE Ch. 2 - Prob. 31RE Ch. 2 - Prob. 32RE Ch. 2 - Prob. 33RE Ch. 2 - Prob. 34RE Ch. 2 - Prob. 35RE Ch. 2 - Prob. 36RE Ch. 2 - Prob. 37RE Ch. 2 - Prob. 38RE Ch. 2 - Prob. 39RE Ch. 2 - Prob. 40RE Ch. 2 - Prob. 41RE Ch. 2 - Prob. 42RE Ch. 2 - Prob. 43RE Ch. 2 - Prob. 44RE Ch. 2 - Prob. 45RE Ch. 2 - Prob. 46RE Ch. 2 - Prob. 47RE Ch. 2 - Prob. 48RE Ch. 2 - Prob. 49RE Ch. 2 - Prob. 50RE Ch. 2 - Prob. 51RE Ch. 2 - Prob. 52RE Ch. 2 - Prob. 53RE Ch. 2 - Prob. 54RE Ch. 2 - Prob. 55RE Ch. 2 - Prob. 56RE Ch. 2 - Prob. 57RE Ch. 2 - Prob. 58RE Ch. 2 - Prob. 59RE Ch. 2 - Prob. 60RE Ch. 2 - Prob. 61RE Ch. 2 - Prob. 62RE Ch. 2 - Prob. 63RE Ch. 2 - Prob. 64RE Ch. 2 - Prob. 65RE Ch. 2 - Prob. 66RE Ch. 2 - Prob. 1CT Ch. 2 - Prob. 2CT Ch. 2 - Prob. 3CT Ch. 2 - Prob. 4CT Ch. 2 - Prob. 5CT Ch. 2 - Prob. 6CT Ch. 2 - Prob. 7CT Ch. 2 - Prob. 8CT Ch. 2 - Prob. 9CT Ch. 2 - Prob. 10CT Ch. 2 - Prob. 11CT Ch. 2 - Prob. 12CT Ch. 2 - Prob. 13CT Ch. 2 - Prob. 14CT Ch. 2 - Prob. 15CT Ch. 2 - Prob. 16CT Ch. 2 - Prob. 17CT Ch. 2 - Prob. 18CT Ch. 2 - Prob. 1PS Ch. 2 - Prob. 2PS Ch. 2 - Prob. 3PS Ch. 2 - Prob. 4PS Ch. 2 - Prob. 5PS Ch. 2 - Prob. 6PS Ch. 2 - Prob. 7PS Ch. 2 - Prob. 8PS Ch. 2 - Prob. 9PS Ch. 2 - Prob. 10PS Ch. 2 - Prob. 11PS Ch. 2 - Prob. 12PS Ch. 2 - Prob. 13PS

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