Chapter 21, Problem 73A

To determine

Potential difference between the plates.

Answer to Problem 73A

  $\Delta V=50\text{V}$

Explanation of Solution

Given:

The given figure is,

  

Charge, $q=2.4\text{C}$

Work done on charge, $W=120\text{J}$

Formula Used:

The work done is given as,

  $W=q\Delta V$

Where, $W$ is work done, $q$ is charge and $\Delta V$ is potential difference.

Calculation:

On substituting the given values in above relation,

  $\begin{array}{c}120=\left(2.4\right)\times \Delta V\\ \Delta V=\frac{120}{2.4}\text{V}\\ =50\text{V}\end{array}$

Conclusion:

Therefore, the potential difference between the plates is $\Delta V=50\text{V}$ .