Chapter 21, Problem 65A

(a)

To determine

To Draw: Arrow to represent force on charge Z.

Explanation of Solution

Given:

Three charges are equidistance from each other.

These charges are:

$\begin{array}{l}{q}_X=+1.0\times {10}^{-6}\text{C}\\ q_Y=+2.0\times {10}^{-6}\text{C}\end{array}$

$q_Z$ is small negative charge.

Calculation:

The force between the two similar nature charges is repulsive and between two dissimilar charges is attractive.

Charge X and Y would attract charge Z towards themselves. Thus, the arrow representing force on charge on Z is shown as follows:

Conclusion:

The direction of force on a negatively charged particle would be opposite to the direction of the electric field.

(b)

To determine

To Draw: Arrow to represent force on charge Z.

Explanation of Solution

Given:

Three charges are equidistance from each other.

These charges are:

$\begin{array}{l}{q}_X=+1.0\times {10}^{-6}\text{C}\\ q_Y=+2.0\times {10}^{-6}\text{C}\end{array}$

$q_Z$ is small positive charge.

Calculation:

The force between the two similar nature charges is repulsive and between two dissimilar charges is attractive. Charge X and Y would repel charge Z away from themselves. Thus, the arrow representing force on charge on Z is shown as follows:

Conclusion:

The direction of force on a negatively charged particle would be opposite to the direction of the electric field.