Chapter 21, Problem 2STP

To determine

To Choose: The correct option.

Answer to Problem 2STP

Option D

Explanation of Solution

Given:

Test charge, $q=+8.7\mu \text{C}$

Electrostatic force, $F=8.1\times {10}^{-6}\text{N,}\text{24}°\text{N}\text{of E}$

Formula Used:

Electric field strength can be obtained by:

$E=\frac{F}{q}$

Here, F is the electrostatic force and q is the test charge.

The direction of electric field is along the direction of the force for the positive test charge and opposite for the negative test charge.

Calculation:

Substitute the values and solve for strength of the electric field:

$\begin{array}{c}E=\frac{F}{q}\\ =\frac{8.1\times {10}^{-6}\text{N}}{8.7\times {10}^{-6}}\\ \text{=9}\text{.3}\times {\text{10}}^{-1}\text{N/C}\end{array}$

The direction of the electric field at the location of the positive test charge is would be same: $\text{24}°\text{N}\text{of E}$

Conclusion:

Thus, option D is correct.