Organic Chemistry (6th Edition)
Organic Chemistry (6th Edition)
6th Edition
ISBN: 9781260119107
Author: Janice Gorzynski Smith
Publisher: McGraw Hill Education
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Chapter 21, Problem 37P
Interpretation Introduction

Interpretation: The reason as to why the pKa of the Ha protons in 1-acteylcyclohexane higher than the pKa of the Hb protons is to be identified.

Concept introduction: The more easily an acid loses proton, the more it will be acidic. In case of organic compounds, various factors help to determine the strength of acidity. Acidic strength can be measured by a factor known as pKa. The lower the value of pKa, the stronger is the acid. Numerically, pKa is the negative base 10 logarithm of the acid dissociation constant.

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PQ-3. What is the major product of this reaction? (A) CN H (B) CN O CN CN H (D) HCN OH CN
Given that pKa for phenol is 9.95 and pKą for the ammonium ion is 9.24, will the following reaction be favorable? (Will the products be favored at equilibrium?) OH + NH3 phenol pKa = 9.95 ammonia phenoxide ion ammonium ion pKa = 9.24
Given that pKa for phenol is 9.95 and pKa for the ammonium ion is 9.24, will the following reaction be favorable? (Will the products be favored at equilibrium?) HO + NH3 phenoxide ion phenol pKa = 9.95 ammonia ammonium ion pKa = 9.24

Chapter 21 Solutions

Organic Chemistry (6th Edition)

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