PEARSON ETEXT ENGINEERING MECH & STATS
PEARSON ETEXT ENGINEERING MECH & STATS
15th Edition
ISBN: 9780137514724
Author: HIBBELER
Publisher: PEARSON
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Chapter 21, Problem 23P
To determine

Show that if the angular momentum of a body is determined with respect to an arbitrary point, then HA=(ρG/A×mvG)+HG .

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The 100-kg beam BD shown in Fig.17-13a is supported by two rods having negligible mass. Determine the force developed in each rod if at the instant = 30°, w = 6 rad/s. A 0.5 m -0 = 30° B 0.4 m- co G 0.4 m n (G) ► (ac)₁ TB 30° 30° 4 0.4 m -0.4 m 981 N TD 30° (b) Alo 0.5 m al α (c) w = 6 rad/s a B
Q-4) The rod, having a weight of 16N and a length of 2.5m, contains a joint at O which is 0.5m distant from point B. The other end of the rod is attached to a 2,5 m- 0,5 m spring that is compressed by 4cm A with Ks= 250N/cm. At this moment the rod is horizontal. When released; calculate it's angular velocity (passing by the vertical position) and reaction forces at the joint 0.
The 21-kg uniform thin hollow square plate is pinned at point O, and its side L = 0.5 m. If it is subjected to the constant moment M = 78 N·m and is released from rest from the position as shown, determine its angular velocity W (in rad/s) when it has rotated 45°. Please pay attention: the numbers may change since they are randomized. Your answer must include 2 places after the decimal point. Take g = 9.81 m/s². L Your Answer: Answer
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Ch 2 - 2.2.2 Forced Undamped Oscillation; Author: Benjamin Drew;https://www.youtube.com/watch?v=6Tb7Rx-bCWE;License: Standard youtube license