Calculate the class width for the data on count of three-syllable words in advertising copy of magazine advertisements.

Question

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Answer 1

Question

Chapter 2.1, Problem 20P

a.

To determine

Calculate the class width for the data on count of three-syllable words in advertising copy of magazine advertisements.

a.

Expert Solution

Answer to Problem 20P

The class width is calculated as 6.

Explanation of Solution

Calculation:

From the given data set, the largest data point is 43 and the smallest data point is 0.

Class Width:

The class width is calculated as follows:

$Class width=(Largest data point−Smallest data point)Number of classes=(43−0)8=5.37≈6$

b.

To determine

Create a table for frequency distribution with class limits, class boundaries, midpoints, frequencies, relative frequencies, and cumulative frequencies.

b.

Expert Solution

Answer to Problem 20P

The class limits for a frequency table with 8 classes using class width 6 are 0-5, 6-11, 12-17, 18-23, 24-29, 30-35, 36-41, and 42-47.

Explanation of Solution

Class limits:

Class limits are the maximum and minimum values in the class interval

Class Boundaries:

A class boundary is the midpoint between the upper limit of one class and the lower limit of the next class where the upper limit of the preceding class interval and the lower limit of the next class interval will be equal. The upper class boundary is calculated by adding 0.5 to the upper class limit and the lower class boundary is calculated by subtracting 0.5 from the lower class limit.

Midpoint:

The midpoint is calculated as given below:

$Midpoint=(Lower class limit+Upper class limit)2$

Frequency:

Frequency is the number of data points that fall under each class.

Cumulative frequency:

Cumulative frequency is calculated by adding each frequency to the sum of preceding frequencies.

Relative Frequency:

Relative frequency is the ratio of frequency by the total number of data values.

The class width is 6. Hence, the lower class limit for the second class 6 is calculated by adding 6 to 0. Following this pattern, all the lower class limits are established. Then, the upper class limits are calculated.

The frequency distribution table is given below:

Class Limits	Class Boundaries	Midpoints	Frequency	Relative Frequency	Cumulative Frequency
0-5	0.5-5.5	2.5	13	$1355=0.24$	13
6-11	5.5-11.5	8.5	15	$1555=0.27$	28 (=15+13)
12-17	11.5-17.5	14.5	11	$1155=0.20$	39 (=11+28)
18-23	17.5-23.5	20.5	3	$355=0.05$	42 (=3+39)
24-29	23.5-29.5	26.5	6	$655=0.11$	48 (=6+42)
30-35	29.5-35.5	32.5	4	$455=0.07$	52 (=4+48)
36-41	35.5-41.5	38.5	2	$255=0.04$	54 (=2+52)
42-47	41.5-47.5	44.5	1	$155=0.02$	55 (=1+54)

c.

To determine

Create a histogram for the given data on count of three-syllable words in advertising copy of magazine advertisements.

c.

Expert Solution

Answer to Problem 20P

The frequency histogram for the data on count of three-syllable words in advertising copy of magazine advertisements is shown below:

Understandable Statistics: Concepts and Methods, Chapter 2.1, Problem 20P , additional homework tip 1

Explanation of Solution

Step-by-step procedure to draw the histogram using MINITAB software:

Choose Graph > Bar Chart.
From Bars represent, choose Values from a table.
Under One column of values, choose Simple. Click OK.
In Graph variables, enter the column of Frequency.
In Categorical variables, enter the column of Three-syllable Words.
Click OK.

Thus, the histogram for three-syllable word data is obtained.

d.

To determine

Construct a relative frequency histogram for the data on count of three-syllable words in advertising copy of magazine advertisements.

d.

Expert Solution

Answer to Problem 20P

The relative frequency histogram for the data on count of three-syllable words in advertising copy of magazine advertisements is shown below:

Understandable Statistics: Concepts and Methods, Chapter 2.1, Problem 20P , additional homework tip 2

Explanation of Solution

Step-by-step procedure to draw the histogram using MINITAB software:

Choose Graph > Bar Chart.
From Bars represent, choose Values from a table.
Under One column of values, choose Simple. Click OK.
In Graph variables, enter the column of Relative frequency.
In Categorical variables, enter the column of Three-syllable Words.
Click OK.

Thus, the relative frequency histogram for three-syllable word data is obtained.

e.

To determine

Identify the shape of distribution: uniform, mound shaped, symmetric, bimodal, skewed left, or skewed right.

e.

Expert Solution

Explanation of Solution

From the histogram, the distribution of count of three-syllable words in advertising copy of magazine advertisements is skewed to the right.

f.

To determine

Create an ogive curve for the given data on count of three-syllable words in advertising copy of magazine advertisements.

f.

Expert Solution

Answer to Problem 20P

An ogive curve for the count of three-syllable words in advertising copy of magazine advertisements is shown below:

Understandable Statistics: Concepts and Methods, Chapter 2.1, Problem 20P , additional homework tip 3

Explanation of Solution

Step-by-step procedure to draw the Ogive curve:

Draw X axis with data values ranging from -0.5 to 47.5.
Label the X axis as Number of Words.
Draw Y axis with data values Cumulative frequency ranging from.0 to 60.
Label the Y axis as Cumulative frequency.
Plot the cumulative frequencies
Join the points and draw an ogive curve.

Thus, an ogive curve for three-syllable word data is obtained.

g.

To determine

Identify the characteristics about the count of three-syllable words in advertising copy of magazine advertisements using the graphs.

g.

Expert Solution

Explanation of Solution

The data values of count of three-syllable words in advertising copy of magazine advertisements fall within 0 and 43.

The range of the data is given below:

$Range=(Largest value-Smallest value)=43−0=43$

The central value of the data is approximately 11.5.

From the histogram, it can be observed that the data is skewed to the right and there are no unusual observations in the data as not even one data point is far from the overall bulk of data.

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Answer 2

Question

Chapter 2.1, Problem 20P

a.

To determine

Calculate the class width for the data on count of three-syllable words in advertising copy of magazine advertisements.

a.

Expert Solution

Answer to Problem 20P

The class width is calculated as 6.

Explanation of Solution

Calculation:

From the given data set, the largest data point is 43 and the smallest data point is 0.

Class Width:

The class width is calculated as follows:

$Class width=(Largest data point−Smallest data point)Number of classes=(43−0)8=5.37≈6$

b.

To determine

Create a table for frequency distribution with class limits, class boundaries, midpoints, frequencies, relative frequencies, and cumulative frequencies.

b.

Expert Solution

Answer to Problem 20P

The class limits for a frequency table with 8 classes using class width 6 are 0-5, 6-11, 12-17, 18-23, 24-29, 30-35, 36-41, and 42-47.

Explanation of Solution

Class limits:

Class limits are the maximum and minimum values in the class interval

Class Boundaries:

A class boundary is the midpoint between the upper limit of one class and the lower limit of the next class where the upper limit of the preceding class interval and the lower limit of the next class interval will be equal. The upper class boundary is calculated by adding 0.5 to the upper class limit and the lower class boundary is calculated by subtracting 0.5 from the lower class limit.

Midpoint:

The midpoint is calculated as given below:

$Midpoint=(Lower class limit+Upper class limit)2$

Frequency:

Frequency is the number of data points that fall under each class.

Cumulative frequency:

Cumulative frequency is calculated by adding each frequency to the sum of preceding frequencies.

Relative Frequency:

Relative frequency is the ratio of frequency by the total number of data values.

The class width is 6. Hence, the lower class limit for the second class 6 is calculated by adding 6 to 0. Following this pattern, all the lower class limits are established. Then, the upper class limits are calculated.

The frequency distribution table is given below:

Class Limits	Class Boundaries	Midpoints	Frequency	Relative Frequency	Cumulative Frequency
0-5	0.5-5.5	2.5	13	$1355=0.24$	13
6-11	5.5-11.5	8.5	15	$1555=0.27$	28 (=15+13)
12-17	11.5-17.5	14.5	11	$1155=0.20$	39 (=11+28)
18-23	17.5-23.5	20.5	3	$355=0.05$	42 (=3+39)
24-29	23.5-29.5	26.5	6	$655=0.11$	48 (=6+42)
30-35	29.5-35.5	32.5	4	$455=0.07$	52 (=4+48)
36-41	35.5-41.5	38.5	2	$255=0.04$	54 (=2+52)
42-47	41.5-47.5	44.5	1	$155=0.02$	55 (=1+54)

c.

To determine

Create a histogram for the given data on count of three-syllable words in advertising copy of magazine advertisements.

c.

Expert Solution

Answer to Problem 20P

The frequency histogram for the data on count of three-syllable words in advertising copy of magazine advertisements is shown below:

Understandable Statistics: Concepts and Methods, Chapter 2.1, Problem 20P , additional homework tip 1

Explanation of Solution

Step-by-step procedure to draw the histogram using MINITAB software:

Choose Graph > Bar Chart.
From Bars represent, choose Values from a table.
Under One column of values, choose Simple. Click OK.
In Graph variables, enter the column of Frequency.
In Categorical variables, enter the column of Three-syllable Words.
Click OK.

Thus, the histogram for three-syllable word data is obtained.

d.

To determine

Construct a relative frequency histogram for the data on count of three-syllable words in advertising copy of magazine advertisements.

d.

Expert Solution

Answer to Problem 20P

The relative frequency histogram for the data on count of three-syllable words in advertising copy of magazine advertisements is shown below:

Understandable Statistics: Concepts and Methods, Chapter 2.1, Problem 20P , additional homework tip 2

Explanation of Solution

Step-by-step procedure to draw the histogram using MINITAB software:

Choose Graph > Bar Chart.
From Bars represent, choose Values from a table.
Under One column of values, choose Simple. Click OK.
In Graph variables, enter the column of Relative frequency.
In Categorical variables, enter the column of Three-syllable Words.
Click OK.

Thus, the relative frequency histogram for three-syllable word data is obtained.

e.

To determine

Identify the shape of distribution: uniform, mound shaped, symmetric, bimodal, skewed left, or skewed right.

e.

Expert Solution

Explanation of Solution

From the histogram, the distribution of count of three-syllable words in advertising copy of magazine advertisements is skewed to the right.

f.

To determine

Create an ogive curve for the given data on count of three-syllable words in advertising copy of magazine advertisements.

f.

Expert Solution

Answer to Problem 20P

An ogive curve for the count of three-syllable words in advertising copy of magazine advertisements is shown below:

Understandable Statistics: Concepts and Methods, Chapter 2.1, Problem 20P , additional homework tip 3

Explanation of Solution

Step-by-step procedure to draw the Ogive curve:

Draw X axis with data values ranging from -0.5 to 47.5.
Label the X axis as Number of Words.
Draw Y axis with data values Cumulative frequency ranging from.0 to 60.
Label the Y axis as Cumulative frequency.
Plot the cumulative frequencies
Join the points and draw an ogive curve.

Thus, an ogive curve for three-syllable word data is obtained.

g.

To determine

Identify the characteristics about the count of three-syllable words in advertising copy of magazine advertisements using the graphs.

g.

Expert Solution

Explanation of Solution

The data values of count of three-syllable words in advertising copy of magazine advertisements fall within 0 and 43.

The range of the data is given below:

$Range=(Largest value-Smallest value)=43−0=43$

The central value of the data is approximately 11.5.

From the histogram, it can be observed that the data is skewed to the right and there are no unusual observations in the data as not even one data point is far from the overall bulk of data.

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Answer 3

Question

Chapter 2.1, Problem 20P

a.

To determine

Calculate the class width for the data on count of three-syllable words in advertising copy of magazine advertisements.

a.

Expert Solution

Answer to Problem 20P

The class width is calculated as 6.

Explanation of Solution

Calculation:

From the given data set, the largest data point is 43 and the smallest data point is 0.

Class Width:

The class width is calculated as follows:

$Class width=(Largest data point−Smallest data point)Number of classes=(43−0)8=5.37≈6$

b.

To determine

Create a table for frequency distribution with class limits, class boundaries, midpoints, frequencies, relative frequencies, and cumulative frequencies.

b.

Expert Solution

Answer to Problem 20P

The class limits for a frequency table with 8 classes using class width 6 are 0-5, 6-11, 12-17, 18-23, 24-29, 30-35, 36-41, and 42-47.

Explanation of Solution

Class limits:

Class limits are the maximum and minimum values in the class interval

Class Boundaries:

A class boundary is the midpoint between the upper limit of one class and the lower limit of the next class where the upper limit of the preceding class interval and the lower limit of the next class interval will be equal. The upper class boundary is calculated by adding 0.5 to the upper class limit and the lower class boundary is calculated by subtracting 0.5 from the lower class limit.

Midpoint:

The midpoint is calculated as given below:

$Midpoint=(Lower class limit+Upper class limit)2$

Frequency:

Frequency is the number of data points that fall under each class.

Cumulative frequency:

Cumulative frequency is calculated by adding each frequency to the sum of preceding frequencies.

Relative Frequency:

Relative frequency is the ratio of frequency by the total number of data values.

The class width is 6. Hence, the lower class limit for the second class 6 is calculated by adding 6 to 0. Following this pattern, all the lower class limits are established. Then, the upper class limits are calculated.

The frequency distribution table is given below:

Class Limits	Class Boundaries	Midpoints	Frequency	Relative Frequency	Cumulative Frequency
0-5	0.5-5.5	2.5	13	$1355=0.24$	13
6-11	5.5-11.5	8.5	15	$1555=0.27$	28 (=15+13)
12-17	11.5-17.5	14.5	11	$1155=0.20$	39 (=11+28)
18-23	17.5-23.5	20.5	3	$355=0.05$	42 (=3+39)
24-29	23.5-29.5	26.5	6	$655=0.11$	48 (=6+42)
30-35	29.5-35.5	32.5	4	$455=0.07$	52 (=4+48)
36-41	35.5-41.5	38.5	2	$255=0.04$	54 (=2+52)
42-47	41.5-47.5	44.5	1	$155=0.02$	55 (=1+54)

c.

To determine

Create a histogram for the given data on count of three-syllable words in advertising copy of magazine advertisements.

c.

Expert Solution

Answer to Problem 20P

The frequency histogram for the data on count of three-syllable words in advertising copy of magazine advertisements is shown below:

Understandable Statistics: Concepts and Methods, Chapter 2.1, Problem 20P , additional homework tip 1

Explanation of Solution

Step-by-step procedure to draw the histogram using MINITAB software:

Choose Graph > Bar Chart.
From Bars represent, choose Values from a table.
Under One column of values, choose Simple. Click OK.
In Graph variables, enter the column of Frequency.
In Categorical variables, enter the column of Three-syllable Words.
Click OK.

Thus, the histogram for three-syllable word data is obtained.

d.

To determine

Construct a relative frequency histogram for the data on count of three-syllable words in advertising copy of magazine advertisements.

d.

Expert Solution

Answer to Problem 20P

The relative frequency histogram for the data on count of three-syllable words in advertising copy of magazine advertisements is shown below:

Understandable Statistics: Concepts and Methods, Chapter 2.1, Problem 20P , additional homework tip 2

Explanation of Solution

Step-by-step procedure to draw the histogram using MINITAB software:

Choose Graph > Bar Chart.
From Bars represent, choose Values from a table.
Under One column of values, choose Simple. Click OK.
In Graph variables, enter the column of Relative frequency.
In Categorical variables, enter the column of Three-syllable Words.
Click OK.

Thus, the relative frequency histogram for three-syllable word data is obtained.

e.

To determine

Identify the shape of distribution: uniform, mound shaped, symmetric, bimodal, skewed left, or skewed right.

e.

Expert Solution

Explanation of Solution

From the histogram, the distribution of count of three-syllable words in advertising copy of magazine advertisements is skewed to the right.

f.

To determine

Create an ogive curve for the given data on count of three-syllable words in advertising copy of magazine advertisements.

f.

Expert Solution

Answer to Problem 20P

An ogive curve for the count of three-syllable words in advertising copy of magazine advertisements is shown below:

Understandable Statistics: Concepts and Methods, Chapter 2.1, Problem 20P , additional homework tip 3

Explanation of Solution

Step-by-step procedure to draw the Ogive curve:

Draw X axis with data values ranging from -0.5 to 47.5.
Label the X axis as Number of Words.
Draw Y axis with data values Cumulative frequency ranging from.0 to 60.
Label the Y axis as Cumulative frequency.
Plot the cumulative frequencies
Join the points and draw an ogive curve.

Thus, an ogive curve for three-syllable word data is obtained.

g.

To determine

Identify the characteristics about the count of three-syllable words in advertising copy of magazine advertisements using the graphs.

g.

Expert Solution

Explanation of Solution

The data values of count of three-syllable words in advertising copy of magazine advertisements fall within 0 and 43.

The range of the data is given below:

$Range=(Largest value-Smallest value)=43−0=43$

The central value of the data is approximately 11.5.

From the histogram, it can be observed that the data is skewed to the right and there are no unusual observations in the data as not even one data point is far from the overall bulk of data.

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Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 4

Question

Chapter 2.1, Problem 20P

a.

To determine

Calculate the class width for the data on count of three-syllable words in advertising copy of magazine advertisements.

a.

Expert Solution

Answer to Problem 20P

The class width is calculated as 6.

Explanation of Solution

Calculation:

From the given data set, the largest data point is 43 and the smallest data point is 0.

Class Width:

The class width is calculated as follows:

$Class width=(Largest data point−Smallest data point)Number of classes=(43−0)8=5.37≈6$

b.

To determine

Create a table for frequency distribution with class limits, class boundaries, midpoints, frequencies, relative frequencies, and cumulative frequencies.

b.

Expert Solution

Answer to Problem 20P

The class limits for a frequency table with 8 classes using class width 6 are 0-5, 6-11, 12-17, 18-23, 24-29, 30-35, 36-41, and 42-47.

Explanation of Solution

Class limits:

Class limits are the maximum and minimum values in the class interval

Class Boundaries:

A class boundary is the midpoint between the upper limit of one class and the lower limit of the next class where the upper limit of the preceding class interval and the lower limit of the next class interval will be equal. The upper class boundary is calculated by adding 0.5 to the upper class limit and the lower class boundary is calculated by subtracting 0.5 from the lower class limit.

Midpoint:

The midpoint is calculated as given below:

$Midpoint=(Lower class limit+Upper class limit)2$

Frequency:

Frequency is the number of data points that fall under each class.

Cumulative frequency:

Cumulative frequency is calculated by adding each frequency to the sum of preceding frequencies.

Relative Frequency:

Relative frequency is the ratio of frequency by the total number of data values.

The class width is 6. Hence, the lower class limit for the second class 6 is calculated by adding 6 to 0. Following this pattern, all the lower class limits are established. Then, the upper class limits are calculated.

The frequency distribution table is given below:

Class Limits	Class Boundaries	Midpoints	Frequency	Relative Frequency	Cumulative Frequency
0-5	0.5-5.5	2.5	13	$1355=0.24$	13
6-11	5.5-11.5	8.5	15	$1555=0.27$	28 (=15+13)
12-17	11.5-17.5	14.5	11	$1155=0.20$	39 (=11+28)
18-23	17.5-23.5	20.5	3	$355=0.05$	42 (=3+39)
24-29	23.5-29.5	26.5	6	$655=0.11$	48 (=6+42)
30-35	29.5-35.5	32.5	4	$455=0.07$	52 (=4+48)
36-41	35.5-41.5	38.5	2	$255=0.04$	54 (=2+52)
42-47	41.5-47.5	44.5	1	$155=0.02$	55 (=1+54)

c.

To determine

Create a histogram for the given data on count of three-syllable words in advertising copy of magazine advertisements.

c.

Expert Solution

Answer to Problem 20P

The frequency histogram for the data on count of three-syllable words in advertising copy of magazine advertisements is shown below:

Understandable Statistics: Concepts and Methods, Chapter 2.1, Problem 20P , additional homework tip 1

Explanation of Solution

Step-by-step procedure to draw the histogram using MINITAB software:

Choose Graph > Bar Chart.
From Bars represent, choose Values from a table.
Under One column of values, choose Simple. Click OK.
In Graph variables, enter the column of Frequency.
In Categorical variables, enter the column of Three-syllable Words.
Click OK.

Thus, the histogram for three-syllable word data is obtained.

d.

To determine

Construct a relative frequency histogram for the data on count of three-syllable words in advertising copy of magazine advertisements.

d.

Expert Solution

Answer to Problem 20P

The relative frequency histogram for the data on count of three-syllable words in advertising copy of magazine advertisements is shown below:

Understandable Statistics: Concepts and Methods, Chapter 2.1, Problem 20P , additional homework tip 2

Explanation of Solution

Step-by-step procedure to draw the histogram using MINITAB software:

Choose Graph > Bar Chart.
From Bars represent, choose Values from a table.
Under One column of values, choose Simple. Click OK.
In Graph variables, enter the column of Relative frequency.
In Categorical variables, enter the column of Three-syllable Words.
Click OK.

Thus, the relative frequency histogram for three-syllable word data is obtained.

e.

To determine

Identify the shape of distribution: uniform, mound shaped, symmetric, bimodal, skewed left, or skewed right.

e.

Expert Solution

Explanation of Solution

From the histogram, the distribution of count of three-syllable words in advertising copy of magazine advertisements is skewed to the right.

f.

To determine

Create an ogive curve for the given data on count of three-syllable words in advertising copy of magazine advertisements.

f.

Expert Solution

Answer to Problem 20P

An ogive curve for the count of three-syllable words in advertising copy of magazine advertisements is shown below:

Understandable Statistics: Concepts and Methods, Chapter 2.1, Problem 20P , additional homework tip 3

Explanation of Solution

Step-by-step procedure to draw the Ogive curve:

Draw X axis with data values ranging from -0.5 to 47.5.
Label the X axis as Number of Words.
Draw Y axis with data values Cumulative frequency ranging from.0 to 60.
Label the Y axis as Cumulative frequency.
Plot the cumulative frequencies
Join the points and draw an ogive curve.

Thus, an ogive curve for three-syllable word data is obtained.

g.

To determine

Identify the characteristics about the count of three-syllable words in advertising copy of magazine advertisements using the graphs.

g.

Expert Solution

Explanation of Solution

The data values of count of three-syllable words in advertising copy of magazine advertisements fall within 0 and 43.

The range of the data is given below:

$Range=(Largest value-Smallest value)=43−0=43$

The central value of the data is approximately 11.5.

From the histogram, it can be observed that the data is skewed to the right and there are no unusual observations in the data as not even one data point is far from the overall bulk of data.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 5

Chapter 2.1, Problem 20P

a.

To determine

Calculate the class width for the data on count of three-syllable words in advertising copy of magazine advertisements.

a.

Expert Solution

Answer to Problem 20P

The class width is calculated as 6.

Explanation of Solution

Calculation:

From the given data set, the largest data point is 43 and the smallest data point is 0.

Class Width:

The class width is calculated as follows:

$Class width=(Largest data point−Smallest data point)Number of classes=(43−0)8=5.37≈6$

b.

To determine

Create a table for frequency distribution with class limits, class boundaries, midpoints, frequencies, relative frequencies, and cumulative frequencies.

b.

Expert Solution

Answer to Problem 20P

The class limits for a frequency table with 8 classes using class width 6 are 0-5, 6-11, 12-17, 18-23, 24-29, 30-35, 36-41, and 42-47.

Explanation of Solution

Class limits:

Class limits are the maximum and minimum values in the class interval

Class Boundaries:

A class boundary is the midpoint between the upper limit of one class and the lower limit of the next class where the upper limit of the preceding class interval and the lower limit of the next class interval will be equal. The upper class boundary is calculated by adding 0.5 to the upper class limit and the lower class boundary is calculated by subtracting 0.5 from the lower class limit.

Midpoint:

The midpoint is calculated as given below:

$Midpoint=(Lower class limit+Upper class limit)2$

Frequency:

Frequency is the number of data points that fall under each class.

Cumulative frequency:

Cumulative frequency is calculated by adding each frequency to the sum of preceding frequencies.

Relative Frequency:

Relative frequency is the ratio of frequency by the total number of data values.

The class width is 6. Hence, the lower class limit for the second class 6 is calculated by adding 6 to 0. Following this pattern, all the lower class limits are established. Then, the upper class limits are calculated.

The frequency distribution table is given below:

Class Limits	Class Boundaries	Midpoints	Frequency	Relative Frequency	Cumulative Frequency
0-5	0.5-5.5	2.5	13	$1355=0.24$	13
6-11	5.5-11.5	8.5	15	$1555=0.27$	28 (=15+13)
12-17	11.5-17.5	14.5	11	$1155=0.20$	39 (=11+28)
18-23	17.5-23.5	20.5	3	$355=0.05$	42 (=3+39)
24-29	23.5-29.5	26.5	6	$655=0.11$	48 (=6+42)
30-35	29.5-35.5	32.5	4	$455=0.07$	52 (=4+48)
36-41	35.5-41.5	38.5	2	$255=0.04$	54 (=2+52)
42-47	41.5-47.5	44.5	1	$155=0.02$	55 (=1+54)

c.

To determine

Create a histogram for the given data on count of three-syllable words in advertising copy of magazine advertisements.

c.

Expert Solution

Answer to Problem 20P

The frequency histogram for the data on count of three-syllable words in advertising copy of magazine advertisements is shown below:

Understandable Statistics: Concepts and Methods, Chapter 2.1, Problem 20P , additional homework tip 1

Explanation of Solution

Step-by-step procedure to draw the histogram using MINITAB software:

Choose Graph > Bar Chart.
From Bars represent, choose Values from a table.
Under One column of values, choose Simple. Click OK.
In Graph variables, enter the column of Frequency.
In Categorical variables, enter the column of Three-syllable Words.
Click OK.

Thus, the histogram for three-syllable word data is obtained.

d.

To determine

Construct a relative frequency histogram for the data on count of three-syllable words in advertising copy of magazine advertisements.

d.

Expert Solution

Answer to Problem 20P

The relative frequency histogram for the data on count of three-syllable words in advertising copy of magazine advertisements is shown below:

Understandable Statistics: Concepts and Methods, Chapter 2.1, Problem 20P , additional homework tip 2

Explanation of Solution

Step-by-step procedure to draw the histogram using MINITAB software:

Choose Graph > Bar Chart.
From Bars represent, choose Values from a table.
Under One column of values, choose Simple. Click OK.
In Graph variables, enter the column of Relative frequency.
In Categorical variables, enter the column of Three-syllable Words.
Click OK.

Thus, the relative frequency histogram for three-syllable word data is obtained.

e.

To determine

Identify the shape of distribution: uniform, mound shaped, symmetric, bimodal, skewed left, or skewed right.

e.

Expert Solution

Explanation of Solution

From the histogram, the distribution of count of three-syllable words in advertising copy of magazine advertisements is skewed to the right.

f.

To determine

Create an ogive curve for the given data on count of three-syllable words in advertising copy of magazine advertisements.

f.

Expert Solution

Answer to Problem 20P

An ogive curve for the count of three-syllable words in advertising copy of magazine advertisements is shown below:

Understandable Statistics: Concepts and Methods, Chapter 2.1, Problem 20P , additional homework tip 3

Explanation of Solution

Step-by-step procedure to draw the Ogive curve:

Draw X axis with data values ranging from -0.5 to 47.5.
Label the X axis as Number of Words.
Draw Y axis with data values Cumulative frequency ranging from.0 to 60.
Label the Y axis as Cumulative frequency.
Plot the cumulative frequencies
Join the points and draw an ogive curve.

Thus, an ogive curve for three-syllable word data is obtained.

g.

To determine

Identify the characteristics about the count of three-syllable words in advertising copy of magazine advertisements using the graphs.

g.

Expert Solution

Explanation of Solution

The data values of count of three-syllable words in advertising copy of magazine advertisements fall within 0 and 43.

The range of the data is given below:

$Range=(Largest value-Smallest value)=43−0=43$

The central value of the data is approximately 11.5.

From the histogram, it can be observed that the data is skewed to the right and there are no unusual observations in the data as not even one data point is far from the overall bulk of data.

Answer 6

Chapter 2.1, Problem 20P

a.

To determine

Calculate the class width for the data on count of three-syllable words in advertising copy of magazine advertisements.

a.

Expert Solution

Answer to Problem 20P

The class width is calculated as 6.

Explanation of Solution

Calculation:

From the given data set, the largest data point is 43 and the smallest data point is 0.

Class Width:

The class width is calculated as follows:

$Class width=(Largest data point−Smallest data point)Number of classes=(43−0)8=5.37≈6$

Answer 7

Chapter 2.1, Problem 20P

a.

To determine

Calculate the class width for the data on count of three-syllable words in advertising copy of magazine advertisements.

Answer 8

a.

Expert Solution

Answer to Problem 20P

The class width is calculated as 6.

Answer 9

a.

Expert Solution

Answer 10

a.

Expert Solution

Answer 11

Expert Solution

Answer 12

Explanation of Solution

Calculation:

From the given data set, the largest data point is 43 and the smallest data point is 0.

Class Width:

The class width is calculated as follows:

$Class width=(Largest data point−Smallest data point)Number of classes=(43−0)8=5.37≈6$

Answer 13

b.

To determine

Create a table for frequency distribution with class limits, class boundaries, midpoints, frequencies, relative frequencies, and cumulative frequencies.

b.

Expert Solution

Answer to Problem 20P

The class limits for a frequency table with 8 classes using class width 6 are 0-5, 6-11, 12-17, 18-23, 24-29, 30-35, 36-41, and 42-47.

Explanation of Solution

Class limits:

Class limits are the maximum and minimum values in the class interval

Class Boundaries:

A class boundary is the midpoint between the upper limit of one class and the lower limit of the next class where the upper limit of the preceding class interval and the lower limit of the next class interval will be equal. The upper class boundary is calculated by adding 0.5 to the upper class limit and the lower class boundary is calculated by subtracting 0.5 from the lower class limit.

Midpoint:

The midpoint is calculated as given below:

$Midpoint=(Lower class limit+Upper class limit)2$

Frequency:

Frequency is the number of data points that fall under each class.

Cumulative frequency:

Cumulative frequency is calculated by adding each frequency to the sum of preceding frequencies.

Relative Frequency:

Relative frequency is the ratio of frequency by the total number of data values.

The class width is 6. Hence, the lower class limit for the second class 6 is calculated by adding 6 to 0. Following this pattern, all the lower class limits are established. Then, the upper class limits are calculated.

The frequency distribution table is given below:

Class Limits	Class Boundaries	Midpoints	Frequency	Relative Frequency	Cumulative Frequency
0-5	0.5-5.5	2.5	13	$1355=0.24$	13
6-11	5.5-11.5	8.5	15	$1555=0.27$	28 (=15+13)
12-17	11.5-17.5	14.5	11	$1155=0.20$	39 (=11+28)
18-23	17.5-23.5	20.5	3	$355=0.05$	42 (=3+39)
24-29	23.5-29.5	26.5	6	$655=0.11$	48 (=6+42)
30-35	29.5-35.5	32.5	4	$455=0.07$	52 (=4+48)
36-41	35.5-41.5	38.5	2	$255=0.04$	54 (=2+52)
42-47	41.5-47.5	44.5	1	$155=0.02$	55 (=1+54)

Answer 14

b.

To determine

Create a table for frequency distribution with class limits, class boundaries, midpoints, frequencies, relative frequencies, and cumulative frequencies.

Answer 15

b.

Expert Solution

Answer to Problem 20P

The class limits for a frequency table with 8 classes using class width 6 are 0-5, 6-11, 12-17, 18-23, 24-29, 30-35, 36-41, and 42-47.

Answer 16

b.

Expert Solution

Answer 17

b.

Expert Solution

Answer 18

Expert Solution

Answer 19

Explanation of Solution

Class limits:

Class limits are the maximum and minimum values in the class interval

Class Boundaries:

A class boundary is the midpoint between the upper limit of one class and the lower limit of the next class where the upper limit of the preceding class interval and the lower limit of the next class interval will be equal. The upper class boundary is calculated by adding 0.5 to the upper class limit and the lower class boundary is calculated by subtracting 0.5 from the lower class limit.

Midpoint:

The midpoint is calculated as given below:

$Midpoint=(Lower class limit+Upper class limit)2$

Frequency:

Frequency is the number of data points that fall under each class.

Cumulative frequency:

Cumulative frequency is calculated by adding each frequency to the sum of preceding frequencies.

Relative Frequency:

Relative frequency is the ratio of frequency by the total number of data values.

The class width is 6. Hence, the lower class limit for the second class 6 is calculated by adding 6 to 0. Following this pattern, all the lower class limits are established. Then, the upper class limits are calculated.

The frequency distribution table is given below:

Class Limits	Class Boundaries	Midpoints	Frequency	Relative Frequency	Cumulative Frequency
0-5	0.5-5.5	2.5	13	$1355=0.24$	13
6-11	5.5-11.5	8.5	15	$1555=0.27$	28 (=15+13)
12-17	11.5-17.5	14.5	11	$1155=0.20$	39 (=11+28)
18-23	17.5-23.5	20.5	3	$355=0.05$	42 (=3+39)
24-29	23.5-29.5	26.5	6	$655=0.11$	48 (=6+42)
30-35	29.5-35.5	32.5	4	$455=0.07$	52 (=4+48)
36-41	35.5-41.5	38.5	2	$255=0.04$	54 (=2+52)
42-47	41.5-47.5	44.5	1	$155=0.02$	55 (=1+54)

Answer 20

c.

To determine

Create a histogram for the given data on count of three-syllable words in advertising copy of magazine advertisements.

c.

Expert Solution

Answer to Problem 20P

The frequency histogram for the data on count of three-syllable words in advertising copy of magazine advertisements is shown below:

Understandable Statistics: Concepts and Methods, Chapter 2.1, Problem 20P , additional homework tip 1

Explanation of Solution

Step-by-step procedure to draw the histogram using MINITAB software:

Choose Graph > Bar Chart.
From Bars represent, choose Values from a table.
Under One column of values, choose Simple. Click OK.
In Graph variables, enter the column of Frequency.
In Categorical variables, enter the column of Three-syllable Words.
Click OK.

Thus, the histogram for three-syllable word data is obtained.

Answer 21

c.

To determine

Create a histogram for the given data on count of three-syllable words in advertising copy of magazine advertisements.

Answer 22

c.

Expert Solution

Answer to Problem 20P

The frequency histogram for the data on count of three-syllable words in advertising copy of magazine advertisements is shown below:

Understandable Statistics: Concepts and Methods, Chapter 2.1, Problem 20P , additional homework tip 1

Answer 23

c.

Expert Solution

Answer 24

c.

Expert Solution

Answer 25

Expert Solution

Answer 26

Explanation of Solution

Step-by-step procedure to draw the histogram using MINITAB software:

Choose Graph > Bar Chart.
From Bars represent, choose Values from a table.
Under One column of values, choose Simple. Click OK.
In Graph variables, enter the column of Frequency.
In Categorical variables, enter the column of Three-syllable Words.
Click OK.

Thus, the histogram for three-syllable word data is obtained.

Answer 27

d.

To determine

Construct a relative frequency histogram for the data on count of three-syllable words in advertising copy of magazine advertisements.

d.

Expert Solution

Answer to Problem 20P

The relative frequency histogram for the data on count of three-syllable words in advertising copy of magazine advertisements is shown below:

Understandable Statistics: Concepts and Methods, Chapter 2.1, Problem 20P , additional homework tip 2

Explanation of Solution

Step-by-step procedure to draw the histogram using MINITAB software:

Choose Graph > Bar Chart.
From Bars represent, choose Values from a table.
Under One column of values, choose Simple. Click OK.
In Graph variables, enter the column of Relative frequency.
In Categorical variables, enter the column of Three-syllable Words.
Click OK.

Thus, the relative frequency histogram for three-syllable word data is obtained.

Answer 28

d.

To determine

Construct a relative frequency histogram for the data on count of three-syllable words in advertising copy of magazine advertisements.

Answer 29

d.

Expert Solution

Answer to Problem 20P

The relative frequency histogram for the data on count of three-syllable words in advertising copy of magazine advertisements is shown below:

Understandable Statistics: Concepts and Methods, Chapter 2.1, Problem 20P , additional homework tip 2

Answer 30

d.

Expert Solution

Answer 31

d.

Expert Solution

Answer 32

Expert Solution

Answer 33

Explanation of Solution

Step-by-step procedure to draw the histogram using MINITAB software:

Choose Graph > Bar Chart.
From Bars represent, choose Values from a table.
Under One column of values, choose Simple. Click OK.
In Graph variables, enter the column of Relative frequency.
In Categorical variables, enter the column of Three-syllable Words.
Click OK.

Thus, the relative frequency histogram for three-syllable word data is obtained.

Answer 34

e.

To determine

Identify the shape of distribution: uniform, mound shaped, symmetric, bimodal, skewed left, or skewed right.

e.

Expert Solution

Explanation of Solution

From the histogram, the distribution of count of three-syllable words in advertising copy of magazine advertisements is skewed to the right.

Answer 35

e.

To determine

Identify the shape of distribution: uniform, mound shaped, symmetric, bimodal, skewed left, or skewed right.

Answer 36

e.

Expert Solution

Explanation of Solution

From the histogram, the distribution of count of three-syllable words in advertising copy of magazine advertisements is skewed to the right.

Answer 37

e.

Expert Solution

Answer 38

e.

Expert Solution

Answer 39

Expert Solution

Answer 40

f.

To determine

Create an ogive curve for the given data on count of three-syllable words in advertising copy of magazine advertisements.

f.

Expert Solution

Answer to Problem 20P

An ogive curve for the count of three-syllable words in advertising copy of magazine advertisements is shown below:

Understandable Statistics: Concepts and Methods, Chapter 2.1, Problem 20P , additional homework tip 3

Explanation of Solution

Step-by-step procedure to draw the Ogive curve:

Draw X axis with data values ranging from -0.5 to 47.5.
Label the X axis as Number of Words.
Draw Y axis with data values Cumulative frequency ranging from.0 to 60.
Label the Y axis as Cumulative frequency.
Plot the cumulative frequencies
Join the points and draw an ogive curve.

Thus, an ogive curve for three-syllable word data is obtained.

Answer 41

f.

To determine

Create an ogive curve for the given data on count of three-syllable words in advertising copy of magazine advertisements.

Answer 42

f.

Expert Solution

Answer to Problem 20P

An ogive curve for the count of three-syllable words in advertising copy of magazine advertisements is shown below:

Understandable Statistics: Concepts and Methods, Chapter 2.1, Problem 20P , additional homework tip 3

Answer 43

f.

Expert Solution

Answer 44

f.

Expert Solution

Answer 45

Expert Solution

Answer 46

Explanation of Solution

Step-by-step procedure to draw the Ogive curve:

Draw X axis with data values ranging from -0.5 to 47.5.
Label the X axis as Number of Words.
Draw Y axis with data values Cumulative frequency ranging from.0 to 60.
Label the Y axis as Cumulative frequency.
Plot the cumulative frequencies
Join the points and draw an ogive curve.

Thus, an ogive curve for three-syllable word data is obtained.

Answer 47

g.

To determine

Identify the characteristics about the count of three-syllable words in advertising copy of magazine advertisements using the graphs.

g.

Expert Solution

Explanation of Solution

The data values of count of three-syllable words in advertising copy of magazine advertisements fall within 0 and 43.

The range of the data is given below:

$Range=(Largest value-Smallest value)=43−0=43$

The central value of the data is approximately 11.5.

From the histogram, it can be observed that the data is skewed to the right and there are no unusual observations in the data as not even one data point is far from the overall bulk of data.

Answer 48

g.

To determine

Identify the characteristics about the count of three-syllable words in advertising copy of magazine advertisements using the graphs.

Answer 49

g.

Expert Solution

Explanation of Solution

The data values of count of three-syllable words in advertising copy of magazine advertisements fall within 0 and 43.

The range of the data is given below:

$Range=(Largest value-Smallest value)=43−0=43$

The central value of the data is approximately 11.5.

From the histogram, it can be observed that the data is skewed to the right and there are no unusual observations in the data as not even one data point is far from the overall bulk of data.

Answer 50

g.

Expert Solution

Answer 51

g.

Expert Solution

Answer 52

Expert Solution

Answer 53

Ch. 2.1 - Statistical Literacy What is the difference...Ch. 2.1 - Statistical Literacy A data set has values ranging...Ch. 2.1 - Statistical Literacy A data set has values ranging...Ch. 2.1 - Prob. 4P Ch. 2.1 - Basic Computation: Class Limits A data set with...Ch. 2.1 - Prob. 6P Ch. 2.1 - Interpretation You are manager of a specialty...Ch. 2.1 - Prob. 8P Ch. 2.1 - Critical Thinking Look at the histogram in Figure...Ch. 2.1 - Critical Thinking The following data represent...

Calculate the class width for the data on count of three-syllable words in advertising copy of magazine advertisements.

Videos

Calculate the class width for the data on count of three-syllable words in advertising copy of magazine advertisements.

Answer to Problem 20P

Explanation of Solution

Create a table for frequency distribution with class limits, class boundaries, midpoints, frequencies, relative frequencies, and cumulative frequencies.

Answer to Problem 20P

Explanation of Solution

Create a histogram for the given data on count of three-syllable words in advertising copy of magazine advertisements.

Answer to Problem 20P

Explanation of Solution

Construct a relative frequency histogram for the data on count of three-syllable words in advertising copy of magazine advertisements.

Answer to Problem 20P

Explanation of Solution

Identify the shape of distribution: uniform, mound shaped, symmetric, bimodal, skewed left, or skewed right.

Explanation of Solution

Create an ogive curve for the given data on count of three-syllable words in advertising copy of magazine advertisements.

Answer to Problem 20P

Explanation of Solution

Identify the characteristics about the count of three-syllable words in advertising copy of magazine advertisements using the graphs.

Explanation of Solution

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