Essentials of Genetics (9th Edition) - Standalone book
9th Edition
ISBN: 9780134047799
Author: William S. Klug, Michael R. Cummings, Charlotte A. Spencer, Michael A. Palladino
Publisher: PEARSON
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Chapter 21, Problem 18PDQ
In a population of tomato plants, mean fruit weight is 60 g and (h2) is 0.3. Predict the mean weight of the progeny if tomato plants whose fruit averaged 80 g were selected from the original population and interbred.
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In a population of tomato plants, mean fruit weight is 60 g and h2 is 0.3. Predict the mean weight of the progeny if tomato plants whose fruit averaged 80 g were selected from the original population and interbred.
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The phenotypic data below are the shoot lengths of 25 F1 and 25 F2 rice plants atseedling stage, produced from the cross of IR29 and Hasawi rice varieties. The mean lengths of the shoot from IR29 and Hasawi are 23.1 cm and 46.7 cm, respectively. Tabulate and plot the frequency distributions of the F1 and F2 generations. From each distribution calculate the mean, the variance,and the standard error of the mean. What is the main difference between F1 and F2 distributions?
Formulas needed:Range (R) = maximum – minimum (Use the same no. of decimal places as original data.)No. of phenotypic classes (K) = 1 + 3.3logn (Round up answer to an integer. Number may still be increased or decreased as needed.)n = total no. of valuesClass interval (CI) = R/K (Use the same no. of decimal places as original data.)
Chapter 21 Solutions
Essentials of Genetics (9th Edition) - Standalone book
Ch. 21 -
CASE STUDY | A genetic flip of the coin
On July...Ch. 21 - CASE STUDY|A genetic flip of the coin On July 11,...Ch. 21 -
CASE STUDY|A genetic flip of the coin
On July...Ch. 21 - HOW DO WE KNOW?
1. In this chapter, we focused on...Ch. 21 - Review the Chapter Concepts list on page 422....Ch. 21 -
3. Define the following: (a) polygenic, (b)...Ch. 21 - A dark-red strain and a white strain of wheat are...Ch. 21 - Height in humans depends on the additive action of...Ch. 21 -
6. An inbred strain of plants has a mean height...Ch. 21 - Prob. 7PDQ
Ch. 21 - In the following table, average differences of...Ch. 21 - What kind of heritability estimates (broad sense...Ch. 21 - List as many human traits as you can that are...Ch. 21 - Corn plants from a test plot are measured, and the...Ch. 21 -
12. The following variances were calculated for...Ch. 21 - The mean and variance of plant height of two...Ch. 21 - A hypothetical study investigated the vitamin A...Ch. 21 - In a herd of dairy cows the narrow-sense...Ch. 21 - In an assessment of learning in Drosophila, flies...Ch. 21 - Suppose you want to develop a population of...Ch. 21 -
18. In a population of tomato plants, mean fruit...Ch. 21 - In a population of 100 inbred, genotypically...Ch. 21 - In a cross between a strain of large guinea pigs...Ch. 21 - While most quantitative traits display continuous...
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- The phenotypic data below are the shoot lengths of 25 F1 and 25 F2 rice plants at seedling stage, produced from the cross of IR29 and Hasawi rice varieties. The mean lengths of the shoot from IR29 and Hasawi are 23.1 cm and 46.7 cm, respectively. Tabulate and plot the frequency distributions of the F1 and F2 generations. Use the formulas below in the computations. From each distribution calculate the mean, the variance, and the standard error of the mean. Round off answers to two decimal places. What is the main difference between F1 and F2 distributions?arrow_forwardThe mean and standard deviation of plant height from two rice plants (P1 and P2) and their progeny (F1 and F2) and a backcross generation (P1 x F1) are shown below. Interpret the CV results from each population.arrow_forwardGive only typing answer with explanation and conclusion to all parts Two true-breeding varieties of maize, one 11 cm high and the other 47 cm high were crossed and the resultant F1 hybrids were then crossed to generate the F2 . In the F2 there were a total of 13,923 plants with a continuous variation in heights between the two extremes and with only 3 plants as large as 47 cm high and 5 plants of 11 cm high. a) How many i) genes and ii) how many alleles are involved in determining height in this plant? b) What is the contribution of each dominant allele to the phenotype in cm?arrow_forward
- a. 1 dominant allele will contribute 120/10 = 12 cm to the base height of the plant.b. The height of the parent plant 1 Genotype of the parent plant 1 – D1D1D2D2D3D3d4d4d5d5 The height of the parent plant 2 Genotype of the parent plant 2 – d1d1d2d2d3d3D4D4D5D5Contributing alleles – D4D4D5D5. The height of the plant without any contributing alleles would be 80 cm. The plant with genotype d1d1d2d2d3d3D4D4D5D5 has 4 contributing allele each of which contributes 12 cm to the base. Hence, the height of the plant with genotype d1d1d2d2d3d3D4D4D5D5 would be 80 + 12 + 12 + 12 + 12 = 128 cm. c. Parents – D1D1D2D2D3D3d4d4d5d5 × d1d1d2d2d3d3D4D4D5D5 Gametes – D1D2D3d4d5 × d1d2d3D4D5 F1 generation – D1d1D2d2D3d3D4d4D5d5 The height of the plants of F1 generation = 80 + 12 + 12 + 12 + 12 + 12 = 140 cm Hence, Genotype of the F1 = D1d1D2d2D3d3D4d4D5d5 Phenotype of…arrow_forwardIn a certain plant, the seed traits are as follows: Color: white (W) is dominant over yellow (w)Shape: disk (D) is dominant over sphere (d)Seed coat: thick (T) is dominant over thin (t) -If the parent plant is a triple heterozygote, what is its phenotype? Analyzing the phenotypes of the offspring, the alleles of the gametes were determined as: 85 wDt 390 WDT 27 WDt 81 WdT5 wDT 374 wdt 30 wdT 8 Wdt-Try to construct a genetic map using the three-point crossarrow_forwardA horticulturist runs a test cross with an offspring (F1 generation) purple plant from Question 8. The phenotypic frequencies of the resulting offspring are 50% white and 50% purple. What is the true genotype of this offspring (F1 generation) purple plant?arrow_forward
- The narrow-sense heritability (hN2) for potato weight in a starting population of potato plants is 0.42, and the mean weight is 1.4 pounds. If a breeder crossed plants with average potato weights of 1.9 and 2.1 pounds,respectively, what is the predicted average weight of potatoes fromthe offspring?arrow_forwardA wide-ranging survey of Nicotonia growing in its natural environment recorded a variation in corolla length ranging from 12mm to 47mm with a variance of 36.5. Subsequently, collected seeds were grown in a greenhouse and it was found that the range was now very much lower with most plants having similar corolla lengths and the variance was now only 8.4. After the plants had grown to maturity and formed seed, seeds were collected from plants with either the shortest and or the longest corollas in the population and planted separately in the greenhouse. When flowers were formed it was found that the variance of the plants with the shortest flowers was now 4.2 while that of the flowers from the longest seeds had become 13.7 Calculate the values for heritability in the different groups of plants and explain why this difference may arise.arrow_forwardA wide-ranging survey of Nicotonia growing in its natural environment recorded a variation in corolla length ranging from 12mm to 47mm with a variance of 36.5. Subsequently, collected seeds were grown in a greenhouse and it was found that the range was now very much lower with most plants having similar corolla lengths and the variance was now only 8.4. After the plants had grown to maturity and formed seed, seeds were collected from plants with either the shortest and or the longest corollas in the population and planted separately in the greenhouse. When flowers were formed it was found that the variance of the plants with the shortest flowers was now 4.2 while that of the flowers from the longest seeds had become 13.7 So，Calculate the new values for heritability in the different groups of plants and explain why this difference may arise.arrow_forward
- A wide-ranging survey of Nicotonia growing in its natural environment recorded a variation in corolla length ranging from 12mm to 47mm with a variance of 36.5. Subsequently, collected seeds were grown in a greenhouse and it was found that the range was now very much lower with most plants having similar corolla lengths and the variance was now only 8.4. After the plants had grown to maturity and formed seed, seeds were collected from plants with either the shortest and or the longest corollas in the population and planted separately in the greenhouse. When flowers were formed it was found that the variance of the plants with the shortest flowers was now 4.2 while that of the flowers from the longest seeds had become 13.7 Thus, calculate the new values for heritability in the different groups of plants and explain why this difference may arise.arrow_forwardIn garden peas, long stems are dominant to short stems, and yellow seeds are dominant to green seeds. 100 long/yellow pea plants, all of which had one short/green parent, are interbred (bred to each other). 1600 progeny result. Please answer the following questions about these progeny. a. Assuming that these two genes are unlinked, about how many long/green pea plants would you expect to find among the offspring? b. What ratio of yellow to green seed color would you expect among the offspring? c. What would you expect the overall phenotypic ratio among the 1600 offspring to be (taking into consideration both traits)?arrow_forwardIn garden peas, long stems are dominant to short stems, and yellow seeds are dominant to green seeds. 100 long/yellow pea plants, all of which had one short/green parent, are interbred (bred to each other). 1600 progeny result. Please answer the following questions about these progeny. a. Assuming that these two genes are unlinked, about how many long/green pea plants would you expect to find among the offspring? b. What ratio of yellow to green seed color would you expect among the offspring? c. What would you expect the overall phenotypic ratio among the 1600 offspring to be (taking intoarrow_forward
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