(a)
Interpretation: The oxidation number of nitrogen in the species is to be calculated.
Concept Introduction: The charge that an atom seems to have when forming ionic connections with other heteroatoms is known as an
(a)
Answer to Problem 76A
The oxidation number of
Explanation of Solution
The given species is
The oxidation number of hydrogen is
The oxidation number of oxygen is
Since the species is neutral, the sum of the oxidation number of each element is equal to zero.
Let
The oxidation number of
(b)
Interpretation: The oxidation number of nitrogen in the species is to be calculated.
Concept Introduction: The charge that an atom seems to have when forming ionic connections with other heteroatoms is known as an atom's oxidation number.
(b)
Answer to Problem 76A
The oxidation number of
Explanation of Solution
The given species is
The oxidation number of hydrogen is
Since the species is neutral, the sum of the oxidation number of each element is equal to zero.
Let
The oxidation number of
(c)
Interpretation: The oxidation number of nitrogen in the species is to be calculated.
Concept Introduction: The charge that an atom seems to have when forming ionic connections with other heteroatoms is known as an atom's oxidation number.
(c)
Answer to Problem 76A
The oxidation number of
Explanation of Solution
The given species is
The oxidation number of oxygen is
Since the species is neutral, the sum of the oxidation number of each element is equal to zero.
Let
The oxidation number of
(d)
Interpretation: The oxidation number of nitrogen in the species is to be calculated.
Concept Introduction: The charge that an atom seems to have when forming ionic connections with other heteroatoms is known as an atom's oxidation number.
(d)
Answer to Problem 76A
The oxidation number of
Explanation of Solution
The given species is
The oxidation number of oxygen is
Since the species has a charge, the sum of the oxidation number of each element is equal to the charge
Let
The oxidation number of
(e)
Interpretation: The oxidation number of nitrogen in the species is to be calculated.
Concept Introduction: The charge that an atom seems to have when forming ionic connections with other heteroatoms is known as an atom's oxidation number.
(e)
Answer to Problem 76A
The oxidation number of
Explanation of Solution
The given species is
The oxidation number of oxygen is
Since the species is neutral, the sum of the oxidation number of each element is equal to zero.
Let
The oxidation number of
(f)
Interpretation: The oxidation number of nitrogen in the species is to be calculated.
Concept Introduction: The charge that an atom seems to have when forming ionic connections with other heteroatoms is known as an atom's oxidation number.
(f)
Answer to Problem 76A
The oxidation number of
Explanation of Solution
The given species is
The oxidation number of hydrogen is
The oxidation number of chlorine is
Since the species is neutral, the sum of the oxidation number of each element is equal to zero.
Let
The oxidation number of
(g)
Interpretation: The oxidation number of nitrogen in the species is to be calculated.
Concept Introduction: The charge that an atom seems to have when forming ionic connections with other heteroatoms is known as an atom's oxidation number.
(g)
Answer to Problem 76A
The oxidation number of
Explanation of Solution
The given species is
The oxidation number of oxygen is
Since the species is neutral, the sum of the oxidation number of each element is equal to zero.
Let
The oxidation number of
(h)
Interpretation: The oxidation number of nitrogen in the species is to be calculated.
Concept Introduction: The charge that an atom seems to have when forming ionic connections with other heteroatoms is known as an atom's oxidation number.
(h)
Answer to Problem 76A
The oxidation number of
Explanation of Solution
The given species is
The oxidation number of oxygen is
Since the species is neutral, the sum of the oxidation number of each element is equal to zero.
Let
The oxidation number of
Chapter 20 Solutions
Chemistry 2012 Student Edition (hard Cover) Grade 11
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