Concept explainers
An unknown compound A (molecular formula
in
Want to see the full answer?
Check out a sample textbook solutionChapter 20 Solutions
Organic Chemistry
- When compound A (C5H12O) is treated with HBr, it forms compound B (C5H11Br). The 1H NMR spectrum of compound A has a 1H singlet, a 3H doublet, a 6H doublet, and two 1H multiplets. The 1H NMR spectrum of compound B has a 6H singlet, a 3H triplet, and a 2H quartet. Identify compounds A and B.arrow_forwardCompound X has the molecular formula C10H12O. The IR spectrum of X has a strong band near 1710 cm-1. Compound X forms a phenyhydrazone, but gives a negative Tollens’ test and a positive iodoform test. What is the structure of the compound?arrow_forwardIdentify products A and B from the given 1H NMR data. Treatment of acetone [(CH3)2C=O] with dilute aqueous base forms B. Compound B exhibits four singlets in its 1H NMR spectrum at 1.3 (6 H), 2.2 (3 H), 2.5 (2 H), and 3.8 (1H) ppm. What is the structure of B?arrow_forward
- Identify the structure of compound C (molecular formula C11H15NO2), which has an IR absorption at 1699 cm−1 and the 1H NMR spectrum shown below.arrow_forwardCompound A has molecular formula C8H8O. Its 1H-NMR spectrum shows a singlet of integral 3 at 2.58 ppm and a multiplet of integral 5 at 7.84 ppm. Its 13C-NMR shows six signals. The IR spectrum of A shows a noteworthy stretch at 1698 cm-1. - Identify Compound A, explaining your reasoning Compound A is treated with a mixture of nitric and sulfuric acids to generate Compound B. The 1H-NMR spectrum of B shows three singlets, one at 2.52 pm of integral 3, one at 6.67 ppm of integral 1, and one at 7.94 ppm of integral 2. The 13C-NMR spectrum of B shows six signals. - Identify compound B, explaining your reasoning Compound B is treated with methylmagnesium bromide and then aqueous acid to generate compound C. The 1H-NMR spectrum of C shows four singlets, one at 1.42 ppm of integral 6, one at 2.3 ppm of integral 1, one at 8.52 ppm of integral 2, and one at 8.97 ppm of integral 1. The 13C-NMR spectrum of C shows six signals. The IR spectrum of C shows a noteworthy broad stretch at 3326 cm-1. -…arrow_forwardIdentify the structure of compound C (molecular formula C11H15NO2),which has an IR absorption at 1699 cm−1 and the 1H NMR spectrumshown below.arrow_forward
- A solution of acetone [(CH3)2C=O] in ethanol (CH3CH2OH) in the presence of a trace of acid was allowed to stand for several days, and a new compound of molecular formula C7H16O2 was formed. The IR spectrum showed only one major peak in the functional group region around 3000 cm−1, and the 1H NMR spectrum is given here. What is the structure of the product?arrow_forwardPropose a structure of compound C (molecular formula C10H12O) consistent with the following data. C is partly responsible for the odor and flavor of raspberries. Compound C: IR absorption at 1717 cm–1arrow_forwardAn unknown compound C (molecular formula C4H8O3) exhibits IR absorptions at 3600–2500 and 1734 cm–1, as well as the following 1H NMR spectrum. What is the structure of C?arrow_forward
- Three isomeric compounds, A, B, and C, all have molecular formula C8H11N. The 1H NMR and IR spectral data of A, B, and C are given below. What are their structures?arrow_forwardAn unknown compound A of molecular formula C10H18O reacts with H2SO4 to form two compounds (B and C)of molecular formula C10H16. B and C both react with H2 in the presence of Pd-C to form decalin. Ozonolysis of B forms D, and ozonolysis of C forms a diketone E of molecular formula C10H16O2. Identify the structures of compounds A, B, C, and E.arrow_forwardAn unknown compound has a molecular formula of C4H6O2. Its IR spectrum shows absorptions at 3095, 1762, 1254, and 1118 cm -1. It exhibits the following signals in its 1H NMR spectrum (ppm): 2.12 (singlet,3H), 4.55 (doublets of doublets, 1H), 4.85 (doublet of doublets, 1H), 7.25 (doublets of doublets, 1H); and the following signals in its 13C NMR spectrum (ppm): 20.8, 100.4, 141.2, 168.0. Draw the structure of the unknown compoundarrow_forward