Chapter 2, Problem P22P

Program Plan Intro

Given Information:

For distributing a file,

F= 15 Gbits = 15 * 1024 Mbits

The upload rate of server (u_s = 30 Mbps)

Download rate (d_i) = 2 Mbps

The formula for calculating the minimum distribution time for client-server distribution is:

$D_{cs}=max\left\{NF/u_s,F/d_{min}\right\}$

The formula for calculating the minimum distribution time for P2P distribution is:

$D_{p2p}=max\{F/u_s,F/d_{\min },NF/(u_s+{\displaystyle \sum _{i=1}^N{u}_i)\}}$