MICROLEECTRONIC E BOOKS
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Chapter 2, Problem D2.99P
To determine
The expected output range of an amplifier.
The location of an additional resistor that is added to compensate the bias current.
New range of possible outputs.
Location and value of compensating resistor that is added when the amplifier operates with a source of
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Design an inverting amplifier to provide a closed-loop voltage gain of Ay -22 V/v.
The maximum input voltage signal is 30 mV with a source resistance in the range of 1 kl <
R, <3 kN. The variable source resistance should introduce a difference in the gain no more
than a 2% of the gain factor. What is the range in output voltage?
Figure Q1 shows the circuit diagram of a "Logarithmic Amplifier". In this
circuit the feedback resistor of a normal inverting amplifier is replaced by a
silicon diode. Since the current flowing through the diode increases
exponentially with the voltage across the diode, the voltage across the diode
will be proportional to the logarithm current flowing through it. Hence the
output of the circuit is proportional to the logarithm of the input voltage.
Q1
D1
RIN
A1
VOUT
RM
Figure Q1
The current flowing through a diode is given by the Shockley Diode Equation:
=.
where
I, is the current flowing through the diode
q is the charge on the electron (given at the back of the examination sheet)
Vp is the voltage across the diode
K, is Boltzmann's constant (given at the back of the examination sheet)
T is room temperature (given at the back of the examination sheet)
Given that I,>>I; an approximate expression for V, as a function of I, is
An amplifier has voltage gain with the feedback of 100. If the gain
without feedback changes by 40% and the gain with feedback should not
vary more than 8%, the values of open-loop gain and feedback ratio will
be respectively given by
(a) 500 and 1.8%
(b) 50000 and 0.8%
(c) 500 and 0.8%
(d) 5000 and 1.8%
Chapter 2 Solutions
MICROLEECTRONIC E BOOKS
Ch. 2.1 - Prob. 2.1ECh. 2.2 - Prob. D2.4ECh. 2.2 - Prob. 2.5ECh. 2.2 - Prob. D2.8ECh. 2.3 - Prob. 2.10ECh. 2.3 - Prob. D2.11ECh. 2.3 - Prob. 2.12ECh. 2.3 - Prob. 2.13ECh. 2.3 - Prob. 2.14ECh. 2.4 - Prob. 2.15E
Ch. 2.4 - Prob. D2.16ECh. 2.4 - Prob. 2.17ECh. 2.5 - Prob. D2.19ECh. 2.5 - Prob. D2.20ECh. 2.6 - Prob. 2.21ECh. 2.6 - Prob. 2.22ECh. 2.6 - Prob. 2.23ECh. 2.6 - Prob. 2.24ECh. 2.6 - Prob. 2.25ECh. 2.7 - Prob. 2.26ECh. 2.7 - Prob. 2.27ECh. 2.7 - Prob. 2.28ECh. 2.8 - Prob. 2.29ECh. 2 - Prob. 2.1PCh. 2 - Prob. 2.2PCh. 2 - Prob. 2.3PCh. 2 - Prob. 2.4PCh. 2 - Prob. 2.7PCh. 2 - Prob. 2.8PCh. 2 - Prob. 2.10PCh. 2 - Prob. 2.11PCh. 2 - Prob. 2.12PCh. 2 - Prob. 2.16PCh. 2 - Prob. 2.17PCh. 2 - Prob. 2.19PCh. 2 - Prob. 2.23PCh. 2 - Prob. 2.24PCh. 2 - Prob. 2.25PCh. 2 - Prob. 2.26PCh. 2 - Prob. D2.27PCh. 2 - Prob. 2.28PCh. 2 - Prob. 2.32PCh. 2 - Prob. 2.33PCh. 2 - Prob. 2.34PCh. 2 - Prob. D2.35PCh. 2 - Prob. D2.36PCh. 2 - Prob. D2.37PCh. 2 - Prob. 2.39PCh. 2 - Prob. D2.42PCh. 2 - Prob. D2.43PCh. 2 - Prob. 2.44PCh. 2 - Prob. D2.46PCh. 2 - Prob. D2.47PCh. 2 - Prob. D2.48PCh. 2 - Prob. D2.49PCh. 2 - Prob. 2.50PCh. 2 - Prob. 2.51PCh. 2 - Prob. D2.53PCh. 2 - Prob. 2.54PCh. 2 - Prob. D2.59PCh. 2 - Prob. 2.60PCh. 2 - Prob. 2.65PCh. 2 - Prob. 2.66PCh. 2 - Prob. 2.67PCh. 2 - Prob. 2.68PCh. 2 - Prob. D2.69PCh. 2 - Prob. 2.70PCh. 2 - Prob. 2.76PCh. 2 - Prob. 2.77PCh. 2 - Prob. 2.80PCh. 2 - Prob. 2.81PCh. 2 - Prob. 2.89PCh. 2 - Prob. D2.92PCh. 2 - Prob. D2.93PCh. 2 - Prob. 2.94PCh. 2 - Prob. D2.99PCh. 2 - Prob. 2.104PCh. 2 - Prob. 2.106PCh. 2 - Prob. 2.114PCh. 2 - Prob. D2.117PCh. 2 - Prob. 2.119PCh. 2 - Prob. 2.121PCh. 2 - Prob. 2.123PCh. 2 - Prob. 2.124PCh. 2 - Prob. 2.126PCh. 2 - Prob. D2.127P
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