MICROLEECTRONIC E BOOKS
null Edition
ISBN: 9780190853532
Author: SEDRA
Publisher: OXF
expand_more
expand_more
format_list_bulleted
Concept explainers
Question
Chapter 2, Problem 2.3P
To determine
The measured value of the voltage at the positive terminal and the actual gain of the amplifier.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
Q2) Why is there a difference between the theoretical
and practical values of voltage gain in an inverting and
non-inverting Op amplifier?
For the given four statements below, which of the following are true about an
operational amplifier?
i. When the input voltage applied at the non-inverting terminal of an op-amp,
the amplified output voltage becomes 180° out of phase with the input.
ii. When the input voltage applied at the inverting terminal of an op-amp, the
amplified output voltage becomes in-phase with the input.
iii. When the input voltage applied at the inverting terminal of an op-amp, the
amplified output becomes 180° out of phase with the input.
iv. When the input voltage applied at the non-inverting terminal of an op-amp,
the amplified output becomes in-phase with the input.
O i and iv
O i and i
O i and iv
O i and ii
The following Operational Amplifier circuit is given. Analyze the circuit
carefully to identify the functions (i.e., OP-AMP configurations) of each OP-Amps.
Calculate the first stage output voltage Vx and then the output voltage at the output of
the second stage Vo . Determine the currents I0, IF, and IX . Finally, determine the
power absorbed by the resistor R7. The resistors: R2 = R4 =100KW. R1 = R3 = 10W,
R5 = 10W, R6 = 90 KW. and R5 = 10W. The load resistor R7 = 10KW. The current
source; I1 = 100μA and V2 = 1V.
Chapter 2 Solutions
MICROLEECTRONIC E BOOKS
Ch. 2.1 - Prob. 2.1ECh. 2.2 - Prob. D2.4ECh. 2.2 - Prob. 2.5ECh. 2.2 - Prob. D2.8ECh. 2.3 - Prob. 2.10ECh. 2.3 - Prob. D2.11ECh. 2.3 - Prob. 2.12ECh. 2.3 - Prob. 2.13ECh. 2.3 - Prob. 2.14ECh. 2.4 - Prob. 2.15E
Ch. 2.4 - Prob. D2.16ECh. 2.4 - Prob. 2.17ECh. 2.5 - Prob. D2.19ECh. 2.5 - Prob. D2.20ECh. 2.6 - Prob. 2.21ECh. 2.6 - Prob. 2.22ECh. 2.6 - Prob. 2.23ECh. 2.6 - Prob. 2.24ECh. 2.6 - Prob. 2.25ECh. 2.7 - Prob. 2.26ECh. 2.7 - Prob. 2.27ECh. 2.7 - Prob. 2.28ECh. 2.8 - Prob. 2.29ECh. 2 - Prob. 2.1PCh. 2 - Prob. 2.2PCh. 2 - Prob. 2.3PCh. 2 - Prob. 2.4PCh. 2 - Prob. 2.7PCh. 2 - Prob. 2.8PCh. 2 - Prob. 2.10PCh. 2 - Prob. 2.11PCh. 2 - Prob. 2.12PCh. 2 - Prob. 2.16PCh. 2 - Prob. 2.17PCh. 2 - Prob. 2.19PCh. 2 - Prob. 2.23PCh. 2 - Prob. 2.24PCh. 2 - Prob. 2.25PCh. 2 - Prob. 2.26PCh. 2 - Prob. D2.27PCh. 2 - Prob. 2.28PCh. 2 - Prob. 2.32PCh. 2 - Prob. 2.33PCh. 2 - Prob. 2.34PCh. 2 - Prob. D2.35PCh. 2 - Prob. D2.36PCh. 2 - Prob. D2.37PCh. 2 - Prob. 2.39PCh. 2 - Prob. D2.42PCh. 2 - Prob. D2.43PCh. 2 - Prob. 2.44PCh. 2 - Prob. D2.46PCh. 2 - Prob. D2.47PCh. 2 - Prob. D2.48PCh. 2 - Prob. D2.49PCh. 2 - Prob. 2.50PCh. 2 - Prob. 2.51PCh. 2 - Prob. D2.53PCh. 2 - Prob. 2.54PCh. 2 - Prob. D2.59PCh. 2 - Prob. 2.60PCh. 2 - Prob. 2.65PCh. 2 - Prob. 2.66PCh. 2 - Prob. 2.67PCh. 2 - Prob. 2.68PCh. 2 - Prob. D2.69PCh. 2 - Prob. 2.70PCh. 2 - Prob. 2.76PCh. 2 - Prob. 2.77PCh. 2 - Prob. 2.80PCh. 2 - Prob. 2.81PCh. 2 - Prob. 2.89PCh. 2 - Prob. D2.92PCh. 2 - Prob. D2.93PCh. 2 - Prob. 2.94PCh. 2 - Prob. D2.99PCh. 2 - Prob. 2.104PCh. 2 - Prob. 2.106PCh. 2 - Prob. 2.114PCh. 2 - Prob. D2.117PCh. 2 - Prob. 2.119PCh. 2 - Prob. 2.121PCh. 2 - Prob. 2.123PCh. 2 - Prob. 2.124PCh. 2 - Prob. 2.126PCh. 2 - Prob. D2.127P
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, electrical-engineering and related others by exploring similar questions and additional content below.Similar questions
- Q1) Compare the practical results and the theoretical results for the Inverting Op-Amp and also compare it for the non-inverting Op-Amp.arrow_forwardThe ideal op-amps depicted can swing rail-to-rail at output, and Vcc= 13 V. Initially, the output voltage Vo = +13 V and the input voltage is vS = -13 V. The feedback resistors are R1 = 6.4 k0, R2 = 8.5 kQ, and R3 = 1.6 KQ. If the input voltage is gradually increased, at what value of vS (to 1% accuracy) does the output voltage (Vo) change to Vo=-Vcc? VVV vS = + R10 Vcc -Vcc R20 04 O Voarrow_forwardQ1 / Find the range of the output voltage for an inverting op - amp if the implication factor is 0.85 and the input voltage range from (1-6) V.arrow_forward
- Suppose the op amp shown has an fT of 1 MHz. What is the phase margin of the amplifier?arrow_forwardFor an op-amp having a slew rate of SR=3.6 V/us. What is the maximum voltage gain that is used when the input signal varies by 4.4 v in 9 us?arrow_forward11. Design and sketch the schematic diagram for a non-inverting amplifier with a gain of 10 using a 741 op-amp. 12. Estimate the required values of the power supply rails for the op-amp circuit in 11) if the input voltage is a sinusoidal signal v(1) = sin(2mt) V. Sketch the output voltage waveform v.(t). 13. Suppose the positive rail in 12) was mistakenly grounded. Sketch the output voltage waveform in this case. 14. Estimate the energy stored in the 10 uF capacitor below if V1 = 5 v. 8 µF 10 µF 4 µFarrow_forward
- Select true or false for 1 and 21 Op amp component is temperature limited due to maximum output current2 The input offset voltage affects the value of the opamp output and is caused by internal non-idealities in the transistors and resistors. 3 What is the use of an op amp in voltage follower? Select one:a. It is the ideal bridge to couple any stages without affecting the voltage.b. It is ideal for maximum power transferc. Allows a small signal to be amplified with high gaind. voltage attenuation 4. It allows to eliminate the problem of variability in the gain parameter of the circuit:Select one:a. The load RLb. High input impedancec. feedback loopd. decoupling capacitors 5 Complete: The output current is limited due to the _____ that the opamp can handle, while the ______ is limiting due to the maximum bias level supported by the transistor.arrow_forwardFor the ideal op-amp shown, what should be the value of resistor Rf to obtain a gain of 12?Answer should be in kiloOhm.arrow_forwardDiscussion: 1- What kind of restrictions Non- inverting op-amp face compared to inverting op-amp? 2- State 5 different types of op amp. Demonstrate them briefly then draw the circuit diagram for each kind. 3- For an inverting op amp, if the voltage input peak equal to 10.2 V, R=10KQ and RF 2002, find Vo and the voltage gain. Assume the input signal has a sinusoidal behavior. 4- Consider an OP amp connected to the inverting configuration to realize a closed-loop gain of -50 V/V utilizing resistors o f 1 k2 and 50 kQ. A load resistance RL is connected from the output to ground, and a low-frequency sine wave signal of peak amplitude Vp is applied to the input. Let the OP amp be ideal except that its output voltage saturates at +/- 10V and its output current is limited to the range +/-15 mA. For RL = 1 k2, what is the maximum possible value of Vp while an undistorted output sinusoid is obtained?arrow_forward
- For the ideal op-amp shown, what should be the value of resistor Rf to obtain a gain of 15? Answer should be in kOhm.arrow_forwardIf the ideal design for op-Amp circuit generate 200 mV at the output, Then practically with 26 mV offset voltage the output voltage of the circuit will be equal to .. . mVarrow_forward6. For common-source small-signal FETS, the output voltage is 180° phase shifted with respect to the Q 7. The operating cycle of a Class A amplifier is Q 8. The maximum efficiency of a Class B amplifier is Q 9. In analyzing op-amps, when the non-inverting input pin is at ground and the inverting input pin is also at 0 V for an AC signal, the technique is called as Q 10. is an op-amp application circuit which is useful in low pass filter circuits.arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Introductory Circuit Analysis (13th Edition)Electrical EngineeringISBN:9780133923605Author:Robert L. BoylestadPublisher:PEARSONDelmar's Standard Textbook Of ElectricityElectrical EngineeringISBN:9781337900348Author:Stephen L. HermanPublisher:Cengage LearningProgrammable Logic ControllersElectrical EngineeringISBN:9780073373843Author:Frank D. PetruzellaPublisher:McGraw-Hill Education
- Fundamentals of Electric CircuitsElectrical EngineeringISBN:9780078028229Author:Charles K Alexander, Matthew SadikuPublisher:McGraw-Hill EducationElectric Circuits. (11th Edition)Electrical EngineeringISBN:9780134746968Author:James W. Nilsson, Susan RiedelPublisher:PEARSONEngineering ElectromagneticsElectrical EngineeringISBN:9780078028151Author:Hayt, William H. (william Hart), Jr, BUCK, John A.Publisher:Mcgraw-hill Education,
Introductory Circuit Analysis (13th Edition)
Electrical Engineering
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:PEARSON
Delmar's Standard Textbook Of Electricity
Electrical Engineering
ISBN:9781337900348
Author:Stephen L. Herman
Publisher:Cengage Learning
Programmable Logic Controllers
Electrical Engineering
ISBN:9780073373843
Author:Frank D. Petruzella
Publisher:McGraw-Hill Education
Fundamentals of Electric Circuits
Electrical Engineering
ISBN:9780078028229
Author:Charles K Alexander, Matthew Sadiku
Publisher:McGraw-Hill Education
Electric Circuits. (11th Edition)
Electrical Engineering
ISBN:9780134746968
Author:James W. Nilsson, Susan Riedel
Publisher:PEARSON
Engineering Electromagnetics
Electrical Engineering
ISBN:9780078028151
Author:Hayt, William H. (william Hart), Jr, BUCK, John A.
Publisher:Mcgraw-hill Education,
What is a Power Amplifier, And Do I Need One?; Author: Sweetwater;https://www.youtube.com/watch?v=2wkmSm4V00M;License: Standard Youtube License