21st Century Astronomy
6th Edition
ISBN: 9780393428063
Author: Kay
Publisher: NORTON
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Chapter 2, Problem 31QP
To determine
Find the Earth’s equatorial diameter.
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Chapter 2 Solutions
21st Century Astronomy
Ch. 2.1 - Prob. 2.1ACYUCh. 2.1 - Prob. 2.1BCYUCh. 2.2 - Prob. 2.2CYUCh. 2.3 - Prob. 2.3CYUCh. 2.4 - Prob. 2.4CYUCh. 2.5 - Prob. 2.5CYUCh. 2 - Prob. 1QPCh. 2 - Prob. 2QPCh. 2 - Prob. 3QPCh. 2 - Prob. 4QP
Ch. 2 - Prob. 5QPCh. 2 - Prob. 6QPCh. 2 - Prob. 7QPCh. 2 - Prob. 8QPCh. 2 - Prob. 9QPCh. 2 - Prob. 10QPCh. 2 - Prob. 11QPCh. 2 - Prob. 12QPCh. 2 - Prob. 13QPCh. 2 - Prob. 14QPCh. 2 - Prob. 15QPCh. 2 - Prob. 16QPCh. 2 - Prob. 17QPCh. 2 - Prob. 18QPCh. 2 - Prob. 19QPCh. 2 - Prob. 20QPCh. 2 - Prob. 21QPCh. 2 - Prob. 22QPCh. 2 - Prob. 23QPCh. 2 - Prob. 24QPCh. 2 - Prob. 25QPCh. 2 - Prob. 26QPCh. 2 - Prob. 27QPCh. 2 - Prob. 28QPCh. 2 - Prob. 29QPCh. 2 - Prob. 30QPCh. 2 - Prob. 31QPCh. 2 - Prob. 33QPCh. 2 - Prob. 34QPCh. 2 - Prob. 35QPCh. 2 - Prob. 36QPCh. 2 - Prob. 37QPCh. 2 - Prob. 38QPCh. 2 - Prob. 39QPCh. 2 - Prob. 40QPCh. 2 - Prob. 41QPCh. 2 - Prob. 42QPCh. 2 - Prob. 43QPCh. 2 - Prob. 44QPCh. 2 - Prob. 45QP
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- the Earth is spinning along at 1,674 km/h at the equator. Use this fact, along with the length of a day, to calculate Earth’s equatorial diameterarrow_forwardWhat is the angle between the equatorial plane and the orbital plane of: (a) polar satellite (b) geostationary satellite.arrow_forwardHow far will a horizontal line depart from the Earth’s surface in 1 mile compared to 1 km?arrow_forward
- EAn astronaut arrives on the planet Oceania and climbs to the top of a cliff overlooking the sea. The astronaut's eye is 100 m above the sea level and he observes that the horizon in all directions appears to be at angle of 5 mrad below the local horizontal. What is the radius of the planet Oceania at sea level? How far away is the horizon from the astronaut? 6000 km and 50 km 3600 km and 20 km 2000 km and 40 km 8000 km and 40 kmarrow_forwardWhat would be the duration of the year, if the distance between the earth and the sun gets doubled ? (a) 129 days (b) 365 days (c) 556 days (d) 1032 dayşarrow_forwardThe earth is approximately spherical, but a much more accurate description is that an oblate spheroid. How will you describe an oblate spheroid?arrow_forward
- The mass of the moon is 7.35 x 10^22 kg and the mass of a person standing on the moon is 65 kg. If the equatorial radius of the moon is 1.74 x 10^6 m, what is the force of gravity (the weight) of the person?arrow_forwardThinking about the Scale of the Solar System As we discussed, the radius of the Earth is approximately 6370 km. The Sun, on the other hand, is approximately 700,000 km in radius and located, on average, one astronomical unit (1 au=1.5x108 km) from the Earth. Imagine that you stand near Mansueto Library, at the corner of 57th and Ellis. You hold a standard desk globe, which has a diameter of 12 inches, and you want to build a model of the Sun, Earth, and their separation that keeps all sizes and lengths in proportion to one another. a) How big would the Sun be in this scale model? Give your answer in feet and meters. b) The nearest star to the Solar System outside of the Sun is Proxima Centauri, which is approximately 4.2 light years away (a light year is the distance light travels in one year, or approximately 9.5x1012 km). Given the scale model outlined above, how far would a model Proxima Centauri be placed from you? Give your answer in miles and km.arrow_forwardCalculate how many seconds there are in 1.0 Mars year (678 Earth days). Report your answer in scientific notation with the correct number of significant digits.arrow_forward
- The Earth is about 12,000 km in diameter. It is therefore how many orders of magnitude wider than you are tall? (i.e., the Earth’s diameter is how many times larger than your height (give an order-of-magnitude estimate)?)arrow_forwardIf you start at the equator and travel to 10 degrees north approx. how many kilometers (or miles) north of the equator will you be? Take the circumference of earth to be 40,000 kilometers (24,900) miles).arrow_forwardThe value of Gme/re2, where me is the mass of the earth, re is the radius of the earth, and G is the universal gravitational constant is (enter your answer with three significant figures)arrow_forward
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