The number of molecules of NaCl present in 1L of solution of 1.0M NaCl having 58.5g of salt per liter. Introduction: Molarity of a solution is defined as the number of moles of solute present in 1 liter of solution. The unit of molarity is mol/L. The molarity of the solution is used to express the concentration of the solution.

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Answer 1

Question

Chapter 2, Problem 24RQ

(a)

Summary Introduction

To determine: The number of molecules of NaCl present in 1L of solution of 1.0M NaCl having 58.5g of salt per liter.

Introduction: Molarity of a solution is defined as the number of moles of solute present in 1 liter of solution. The unit of molarity is mol/L. The molarity of the solution is used to express the concentration of the solution.

(b)

Summary Introduction

To determine: The number of millimoles of NaCl presents in the solution of 1.0M NaCl containing 58.5g of salt per liter.

Introduction: The mole is the SI unit that measures the amount of a substance. One mole is equal to the 6.022×1023 molecules. Every element has a different molar mass and it depends on the weight of the Avogadro’s number of its atom. One mole is equal to 1000 millimoles.

(c)

Summary Introduction

To determine: The number of equivalents of sodium ions present in the 1.0M solution of NaCl.

Introduction: The concentration of ions present in a solution is expressed as the number of equivalents per liter. One equivalent is equal to the number of charges carried by one molarity of ions.

(d)

Summary Introduction

To determine: The percent solution of 58.5g of NaCl per liter.

Introduction: The concentration of the solute in a solution is expressed by percent solution. It means a 10% solution is 10 parts of solute in 100 parts of solution. The amount of solute in a percent solution is expressed as the percentage of total solution weight or volume.

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Answer 2

Question

Chapter 2, Problem 24RQ

(a)

Summary Introduction

To determine: The number of molecules of NaCl present in 1L of solution of 1.0M NaCl having 58.5g of salt per liter.

Introduction: Molarity of a solution is defined as the number of moles of solute present in 1 liter of solution. The unit of molarity is mol/L. The molarity of the solution is used to express the concentration of the solution.

(b)

Summary Introduction

To determine: The number of millimoles of NaCl presents in the solution of 1.0M NaCl containing 58.5g of salt per liter.

Introduction: The mole is the SI unit that measures the amount of a substance. One mole is equal to the 6.022×1023 molecules. Every element has a different molar mass and it depends on the weight of the Avogadro’s number of its atom. One mole is equal to 1000 millimoles.

(c)

Summary Introduction

To determine: The number of equivalents of sodium ions present in the 1.0M solution of NaCl.

Introduction: The concentration of ions present in a solution is expressed as the number of equivalents per liter. One equivalent is equal to the number of charges carried by one molarity of ions.

(d)

Summary Introduction

To determine: The percent solution of 58.5g of NaCl per liter.

Introduction: The concentration of the solute in a solution is expressed by percent solution. It means a 10% solution is 10 parts of solute in 100 parts of solution. The amount of solute in a percent solution is expressed as the percentage of total solution weight or volume.

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Answer 3

Question

Chapter 2, Problem 24RQ

(a)

Summary Introduction

To determine: The number of molecules of NaCl present in 1L of solution of 1.0M NaCl having 58.5g of salt per liter.

Introduction: Molarity of a solution is defined as the number of moles of solute present in 1 liter of solution. The unit of molarity is mol/L. The molarity of the solution is used to express the concentration of the solution.

(b)

Summary Introduction

To determine: The number of millimoles of NaCl presents in the solution of 1.0M NaCl containing 58.5g of salt per liter.

Introduction: The mole is the SI unit that measures the amount of a substance. One mole is equal to the 6.022×1023 molecules. Every element has a different molar mass and it depends on the weight of the Avogadro’s number of its atom. One mole is equal to 1000 millimoles.

(c)

Summary Introduction

To determine: The number of equivalents of sodium ions present in the 1.0M solution of NaCl.

Introduction: The concentration of ions present in a solution is expressed as the number of equivalents per liter. One equivalent is equal to the number of charges carried by one molarity of ions.

(d)

Summary Introduction

To determine: The percent solution of 58.5g of NaCl per liter.

Introduction: The concentration of the solute in a solution is expressed by percent solution. It means a 10% solution is 10 parts of solute in 100 parts of solution. The amount of solute in a percent solution is expressed as the percentage of total solution weight or volume.

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Answer 4

Question

Chapter 2, Problem 24RQ

(a)

Summary Introduction

To determine: The number of molecules of NaCl present in 1L of solution of 1.0M NaCl having 58.5g of salt per liter.

Introduction: Molarity of a solution is defined as the number of moles of solute present in 1 liter of solution. The unit of molarity is mol/L. The molarity of the solution is used to express the concentration of the solution.

(b)

Summary Introduction

To determine: The number of millimoles of NaCl presents in the solution of 1.0M NaCl containing 58.5g of salt per liter.

Introduction: The mole is the SI unit that measures the amount of a substance. One mole is equal to the 6.022×1023 molecules. Every element has a different molar mass and it depends on the weight of the Avogadro’s number of its atom. One mole is equal to 1000 millimoles.

(c)

Summary Introduction

To determine: The number of equivalents of sodium ions present in the 1.0M solution of NaCl.

Introduction: The concentration of ions present in a solution is expressed as the number of equivalents per liter. One equivalent is equal to the number of charges carried by one molarity of ions.

(d)

Summary Introduction

To determine: The percent solution of 58.5g of NaCl per liter.

Introduction: The concentration of the solute in a solution is expressed by percent solution. It means a 10% solution is 10 parts of solute in 100 parts of solution. The amount of solute in a percent solution is expressed as the percentage of total solution weight or volume.

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Answer 5

Chapter 2, Problem 24RQ

(a)

Summary Introduction

To determine: The number of molecules of NaCl present in 1L of solution of 1.0M NaCl having 58.5g of salt per liter.

Introduction: Molarity of a solution is defined as the number of moles of solute present in 1 liter of solution. The unit of molarity is mol/L. The molarity of the solution is used to express the concentration of the solution.

(b)

Summary Introduction

To determine: The number of millimoles of NaCl presents in the solution of 1.0M NaCl containing 58.5g of salt per liter.

Introduction: The mole is the SI unit that measures the amount of a substance. One mole is equal to the 6.022×1023 molecules. Every element has a different molar mass and it depends on the weight of the Avogadro’s number of its atom. One mole is equal to 1000 millimoles.

(c)

Summary Introduction

To determine: The number of equivalents of sodium ions present in the 1.0M solution of NaCl.

Introduction: The concentration of ions present in a solution is expressed as the number of equivalents per liter. One equivalent is equal to the number of charges carried by one molarity of ions.

(d)

Summary Introduction

To determine: The percent solution of 58.5g of NaCl per liter.

Introduction: The concentration of the solute in a solution is expressed by percent solution. It means a 10% solution is 10 parts of solute in 100 parts of solution. The amount of solute in a percent solution is expressed as the percentage of total solution weight or volume.

Answer 6

Chapter 2, Problem 24RQ

(a)

Summary Introduction

To determine: The number of molecules of NaCl present in 1L of solution of 1.0M NaCl having 58.5g of salt per liter.

Introduction: Molarity of a solution is defined as the number of moles of solute present in 1 liter of solution. The unit of molarity is mol/L. The molarity of the solution is used to express the concentration of the solution.

Answer 7

Chapter 2, Problem 24RQ

(a)

Summary Introduction

To determine: The number of molecules of NaCl present in 1L of solution of 1.0M NaCl having 58.5g of salt per liter.

Introduction: Molarity of a solution is defined as the number of moles of solute present in 1 liter of solution. The unit of molarity is mol/L. The molarity of the solution is used to express the concentration of the solution.

Answer 8

(b)

Summary Introduction

To determine: The number of millimoles of NaCl presents in the solution of 1.0M NaCl containing 58.5g of salt per liter.

Introduction: The mole is the SI unit that measures the amount of a substance. One mole is equal to the 6.022×1023 molecules. Every element has a different molar mass and it depends on the weight of the Avogadro’s number of its atom. One mole is equal to 1000 millimoles.

Answer 9

(b)

Summary Introduction

To determine: The number of millimoles of NaCl presents in the solution of 1.0M NaCl containing 58.5g of salt per liter.

Introduction: The mole is the SI unit that measures the amount of a substance. One mole is equal to the 6.022×1023 molecules. Every element has a different molar mass and it depends on the weight of the Avogadro’s number of its atom. One mole is equal to 1000 millimoles.

Answer 10

(c)

Summary Introduction

To determine: The number of equivalents of sodium ions present in the 1.0M solution of NaCl.

Introduction: The concentration of ions present in a solution is expressed as the number of equivalents per liter. One equivalent is equal to the number of charges carried by one molarity of ions.

Answer 11

(c)

Summary Introduction

To determine: The number of equivalents of sodium ions present in the 1.0M solution of NaCl.

Introduction: The concentration of ions present in a solution is expressed as the number of equivalents per liter. One equivalent is equal to the number of charges carried by one molarity of ions.

Answer 12

(d)

Summary Introduction

To determine: The percent solution of 58.5g of NaCl per liter.

Introduction: The concentration of the solute in a solution is expressed by percent solution. It means a 10% solution is 10 parts of solute in 100 parts of solution. The amount of solute in a percent solution is expressed as the percentage of total solution weight or volume.

Answer 13

(d)

Summary Introduction

To determine: The percent solution of 58.5g of NaCl per liter.

Introduction: The concentration of the solute in a solution is expressed by percent solution. It means a 10% solution is 10 parts of solute in 100 parts of solution. The amount of solute in a percent solution is expressed as the percentage of total solution weight or volume.

Answer 14

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Answer 15

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Answer 16

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Answer 17

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Solution Summary: The author explains the molarity of a solution, which is defined as the number of moles of solute present in 1 liter of solution.

To determine: The number of equivalents of sodium ions present in the 1.0M solution of NaCl.

Introduction: The concentration of ions present in a solution is expressed as the number of equivalents per liter. One equivalent is equal to the number of charges carried by one molarity of ions.

Want to see the full answer?

Chapter 2 Solutions

Solution Summary: The author explains the molarity of a solution, which is defined as the number of moles of solute present in 1 liter of solution.

To determine: The number of equivalents of sodium ions present in the 1.0M solution of NaCl. Introduction: The concentration of ions present in a solution is expressed as the number of equivalents per liter. One equivalent is equal to the number of charges carried by one molarity of ions.

Want to see the full answer?

Chapter 2 Solutions

To determine: The number of equivalents of sodium ions present in the 1.0M solution of NaCl.

Introduction: The concentration of ions present in a solution is expressed as the number of equivalents per liter. One equivalent is equal to the number of charges carried by one molarity of ions.