Chapter 2, Problem 2.12.4E

Explanation of Solution

The result of $t0:

The given is:

$s0 = 0x80000000

$s1 = 0xD0000000

sub $t0, $s0, $s1

The “sub” instruction is used to subtracting the registers “$s0” and “$s1” is same as adding 2’s complement of that number and finally store the result in the “$t0”.

Step1: Convert the hexadecimal value into the binary value

$\begin{array}{l}0\text{x}80000000=10000000000000000000000000000000 \\ 0\text{x}D0000000=11010000000000000000000000000000\end{array}$

Step2: taking 2’s compliment for “$s1”

$\begin{array}{l} 11010000000000000000000000000000\\ \text{interchange given binary number:}\\ 0010\text{ 1111 1111 1111 1111 1111 1111 1111}\\ \\ \text{add "1" to the interchange binary number}\\ 0010\text{ 1111 1111 1111 1111 1111 1111 1111}\\ \text{ \&}\end{array}$