Physics of Everyday Phenomena
Physics of Everyday Phenomena
9th Edition
ISBN: 9781259894008
Author: W. Thomas Griffith, Juliet Brosing Professor
Publisher: McGraw-Hill Education
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Chapter 2, Problem 18E

Starting from rest, a car accelerates at a constant rate of 4.0 m/s2 for a time of 5 seconds.

  1. a. Compute the velocity of the car at 1 s, 2 s, 3 s, 4 s, and 5 s and plot these velocity values against time.
  2. b. Compute the distance traveled by the car for these same times and plot the distance values against time.

(a)

Expert Solution
Check Mark
To determine

The velocity of the car after each second.

Answer to Problem 18E

The velocities after 1s, 2s, 3s, 4s and 5s are 4 m/s, 8 m/s, 12 m/s, 16 m/s and 20 m/s respectively.

Explanation of Solution

Given info: Acceleration is 4m/s2 and time is 5 seconds.

Write the formula for average acceleration.

a=vv0t

Here,

v is the final velocity

v0 is the initial velocity

a is the average acceleration

t is the time

Re-arrange the above equation to get v0.

v=v0+at

For t=1s,

Substitute 0 m/s for v0, 4m/s2 for a and 1 s for t to get v.

v=(0m/s)+(4m/s2)(1s)=4m/s

For t=2s,

Substitute 0 m/s for v0, 4m/s2 for a and 2 s for t to get v.

v=(0m/s)+(4m/s2)(2s)=8m/s

For t=3s,

Substitute 0 m/s for v0, 4m/s2 for a and 3 s for t to get v.

v=(0m/s)+(4m/s2)(3s)=12m/s

For t=4s,

Substitute 0 m/s for v0, 4m/s2 for a and 4 s for t to get v.

v=(0m/s)+(4m/s2)(4s)=16m/s

For t=5s,

Substitute 0 m/s for v0, 4m/s2 for a and 5 s for t to get v.

v=(0m/s)+(4m/s2)(5s)=20m/s

The velocity time graph is given below.

Physics of Everyday Phenomena, Chapter 2, Problem 18E , additional homework tip  1

Conclusion:

The velocities after 1s, 2s, 3s, 4s and 5s are 4 m/s, 8 m/s, 12 m/s, 16 m/s and 20 m/s respectively.

(b)

Expert Solution
Check Mark
To determine

The distance travelled after each second.

Answer to Problem 18E

The distances after 1s, 2s, 3s, 4s and 5s are 2 m, 8 m, 18 m, 32 m and 50 m respectively.

Explanation of Solution

Given info: Acceleration is 4m/s2 and time is 5 seconds.

Write the formula to calculate the distance.

d=v0t+12at2

Here,

d is the distance

For t=1s,

Substitute 0 m/s for v0, 4m/s2 for a and 1 s for t to get d.

d=(0m/s)(1s)+12(4m/s2)(1s)2=2m

For t=2s,

Substitute 0 m/s for v0, 4m/s2 for a and 2 s for t to get d.

d=(0m/s)(2s)+12(4m/s2)(2s)2=8m

For t=3s,

Substitute 0 m/s for v0, 4m/s2 for a and 3 s for t to get d.

d=(0m/s)(3s)+12(4m/s2)(3s)2=18m

For t=4s,

Substitute 0 m/s for v0, 4m/s2 for a and 4 s for t to get d.

d=(0m/s)(4s)+12(4m/s2)(4s)2=32m

For t=5s,

Substitute 0 m/s for v0, 4m/s2 for a and 5 s for t to get d.

d=(0m/s)(5s)+12(4m/s2)(5s)2=50m

The distance time graph is,

Physics of Everyday Phenomena, Chapter 2, Problem 18E , additional homework tip  2

Conclusion:

The distances after 1s, 2s, 3s, 4s and 5s are 2 m, 8 m, 18 m, 32 m and 50 m respectively.

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Chapter 2 Solutions

Physics of Everyday Phenomena

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Position/Velocity/Acceleration Part 1: Definitions; Author: Professor Dave explains;https://www.youtube.com/watch?v=4dCrkp8qgLU;License: Standard YouTube License, CC-BY