World of Chemistry, 3rd edition
World of Chemistry, 3rd edition
3rd Edition
ISBN: 9781133109655
Author: Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCoste
Publisher: Brooks / Cole / Cengage Learning
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Chapter 19, Problem 8STP
Interpretation Introduction

Interpretation: The balanced nuclear equation for the decay of P1530 to produce a positron has to be written.

Concept Introduction: The emission of positron (e+) on decay of a nucleus is called as positron emission. In positron emission, one proton of original nucleus decays to a form positron and a neutron.

The general equation is,

  XZAe+10+Y(Z1)A

Expert Solution & Answer
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Answer to Problem 8STP

The balanced nuclear equation for the decay of P1530 to produce a positron is,

  P1530e+10+S1430i

Explanation of Solution

The decay of a nucleus by emitting a positron (e+) is called as positron emission. In positron emission, one proton of original nucleus decays to a form positron and a neutron. Due to which, the new nucleus formed has Z-1 protons and A-Z+1 neutrons.

The general equation is,

  XZAe+10+Y(Z1)A

Where,

  • Ais the mass number.
  • Z is the atomic number.
  • X is the original isotope.
  • Y is the new isotope.

Positron emission converts a proton into a neutron, the new nucleus formed with have one fewer proton than the original nucleus but the mass of the original and new particle will be the same.

In phosphorus (P1530), the mass number is 30 and the atomic number is 15.

Mass number: Since a positron particle has no mass, the masses of the new and original particle could be the same (30).

Atomic number: Since positron particle converts a proton into a neutron, the new nucleus would have Z-1 protons, 15-1=14. Therefore, the new nucleus has atomic number of 14.

From the periodic table, the element that has atomic number of 14 is identified as silicon.

Phosphorus undergoes positron emission to form silicon (S1430i), whose atomic number will be 14 , the mass number will be 30 and positron would be emitted.

The balanced nuclear equation of P1530 to produce a positron is,

  P1530e+10+S1430i

Conclusion

In position emission, the atomic number of the original nucleus is Z-1and the mass number is A. The balanced nuclear equation of P1530 to produce a positron is,

  P1530e+10+S1430i

Chapter 19 Solutions

World of Chemistry, 3rd edition

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