World of Chemistry, 3rd edition
World of Chemistry, 3rd edition
3rd Edition
ISBN: 9781133109655
Author: Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCoste
Publisher: Brooks / Cole / Cengage Learning
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Chapter 19, Problem 58A
Interpretation Introduction

Interpretation: The number of protons and neutron of each isotopes of aluminium needs to be determined.

Concept introduction: The subscript in symbol of element represents number of protons and superscript represents mass number.

Number of neutron = mass number − number of protons

Expert Solution & Answer
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Answer to Problem 58A

    IsotopesNumber of protonsNumber of neutrons
    A1327l1314
    A1328l1315
    A1329l1316

Explanation of Solution

Protons number of all isotopes will be same (13) but number of neutrons will vary as mass number is different for isotopes.

For A1327l number of neutrons =2713 =14

For A1328l number of neutrons =2813 = 15

For A1329l number of neutrons =2913 = 16

Conclusion
    IsotopesNumber of protonsNumber of neutrons
    A1327l1314
    A1328l1315
    A1329l1316

Chapter 19 Solutions

World of Chemistry, 3rd edition

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