(a) Interpretation: The value of K for the given reaction at 25 ° C should be calculated. Ni(s) + 2 V 3+ (aq) → 2 V 2+ ( aq ) + Ni 2+ (aq) Concept introduction: The E° c e l l value for a redox reaction gives by following equation. E ° c e l l = E ° R e d u c t i o n − E ° O x i d a t i o n When the reactants and products are in their standard states, Δ r G ∘ = − z F E c e l l ∘ Where, z = Electron number F = Faraday constant = 96 , 485 C mol − 1 E c e l l ∘ = Standard Electron cell potential The electron number, z, for a reaction depends on how the reaction is written. Δ r G ∘ = − RT ln K − RT ln K = − z F E c e l l ∘ ∴ ln K = − z F E c e l l ∘ − R T ln K = 11604 C J -1 z E c e l l ∘ T K = e 11604 C J -1 z E c e l l ∘ T

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Answer 1

Question

Chapter 19, Problem 26E

Interpretation Introduction

(a)

Interpretation:

The value of K for the given reaction at 25 ° C should be calculated.

Ni(s)+2V3+(aq)→2V2+(aq)+Ni2+(aq)

Concept introduction:

The E°_c_e_l_l value for a redox reaction gives by following equation.

E°cell=E°Reduction−E°Oxidation

When the reactants and products are in their standard states,

ΔrG∘=−zFEcell∘Where,z= Electron numberF=Faraday constant=96,485 C mol−1Ecell∘=Standard Electron cell potential

The electron number, z, for a reaction depends on how the reaction is written.

ΔrG∘=−RTlnK−RTlnK=−zFEcell∘∴lnK=−zFE cell∘−RTlnK=11604 C J-1zE cell∘TK=e11604 C J -1 z E cell ∘ T

Interpretation Introduction

(b)

Interpretation:

The value of K for the given reaction at 25 ° C should be calculated.

MnO2(s)+4H+(aq)+2Cl-(aq)→Mn2+(aq)+2H2O(l)+Cl2(g)

Concept introduction:

The E°_c_e_l_l value for a redox reaction gives by following equation.

E°cell=E°Reduction−E°Oxidation

When the reactants and products are in their standard states,

ΔrG∘=−zFEcell∘Where,z= Electron numberF=Faraday constant=96,485 C mol−1Ecell∘=Standard Electron cell potential

The electron number, z, for a reaction depends on how the reaction is written.

ΔrG∘=−RTlnK−RTlnK=−zFEcell∘∴lnK=−zFE cell∘−RTlnK=11604 C J-1zE cell∘TK=e11604 C J -1 z E cell ∘ T

Interpretation Introduction

(c)

Interpretation:

The value of K for the given reaction at 25 ° Cshould be calculated.

2OCl-(aq)→2Cl−(aq)+O2(g)

Concept introduction:

The E°_c_e_l_l value for a redox reaction gives by following equation.

E°cell=E°Reduction−E°Oxidation

When the reactants and products are in their standard states,

ΔrG∘=−zFEcell∘Where,z= Electron numberF=Faraday constant=96,485 C mol−1Ecell∘=Standard Electron cell potential

The electron number, z, for a reaction depends on how the reaction is written.

ΔrG∘=−RTlnK−RTlnK=−zFEcell∘∴lnK=−zFE cell∘−RTlnK=11604 C J-1zE cell∘TK=e11604 C J -1 z E cell ∘ T

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Hydrogen gas reduces Ni²+ according to the following reaction: Ni2+ (aq) + H₂(g) → Ni(s) + 2H*(aq); E°cell = -0.25 V; AH = 54 kJ/mol. i) What is K for this redox reaction? ii) Is this reaction likely to occur? iii) Is the reaction more likely to occur at higher or lower pH?

Write the expression for the equilibrium constant for the reaction represented by the equation: AgCl (s) Ag+ (aq) + Cl¯¯ (aq)

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Answer 2

Question

Chapter 19, Problem 26E

Interpretation Introduction

(a)

Interpretation:

The value of K for the given reaction at 25 ° C should be calculated.

Ni(s)+2V3+(aq)→2V2+(aq)+Ni2+(aq)

Concept introduction:

The E°_c_e_l_l value for a redox reaction gives by following equation.

E°cell=E°Reduction−E°Oxidation

When the reactants and products are in their standard states,

ΔrG∘=−zFEcell∘Where,z= Electron numberF=Faraday constant=96,485 C mol−1Ecell∘=Standard Electron cell potential

The electron number, z, for a reaction depends on how the reaction is written.

ΔrG∘=−RTlnK−RTlnK=−zFEcell∘∴lnK=−zFE cell∘−RTlnK=11604 C J-1zE cell∘TK=e11604 C J -1 z E cell ∘ T

Interpretation Introduction

(b)

Interpretation:

The value of K for the given reaction at 25 ° C should be calculated.

MnO2(s)+4H+(aq)+2Cl-(aq)→Mn2+(aq)+2H2O(l)+Cl2(g)

Concept introduction:

The E°_c_e_l_l value for a redox reaction gives by following equation.

E°cell=E°Reduction−E°Oxidation

When the reactants and products are in their standard states,

ΔrG∘=−zFEcell∘Where,z= Electron numberF=Faraday constant=96,485 C mol−1Ecell∘=Standard Electron cell potential

The electron number, z, for a reaction depends on how the reaction is written.

ΔrG∘=−RTlnK−RTlnK=−zFEcell∘∴lnK=−zFE cell∘−RTlnK=11604 C J-1zE cell∘TK=e11604 C J -1 z E cell ∘ T

Interpretation Introduction

(c)

Interpretation:

The value of K for the given reaction at 25 ° Cshould be calculated.

2OCl-(aq)→2Cl−(aq)+O2(g)

Concept introduction:

The E°_c_e_l_l value for a redox reaction gives by following equation.

E°cell=E°Reduction−E°Oxidation

When the reactants and products are in their standard states,

ΔrG∘=−zFEcell∘Where,z= Electron numberF=Faraday constant=96,485 C mol−1Ecell∘=Standard Electron cell potential

The electron number, z, for a reaction depends on how the reaction is written.

ΔrG∘=−RTlnK−RTlnK=−zFEcell∘∴lnK=−zFE cell∘−RTlnK=11604 C J-1zE cell∘TK=e11604 C J -1 z E cell ∘ T

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Check out a sample textbook solution

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Answer 3

Question

Chapter 19, Problem 26E

Interpretation Introduction

(a)

Interpretation:

The value of K for the given reaction at 25 ° C should be calculated.

Ni(s)+2V3+(aq)→2V2+(aq)+Ni2+(aq)

Concept introduction:

The E°_c_e_l_l value for a redox reaction gives by following equation.

E°cell=E°Reduction−E°Oxidation

When the reactants and products are in their standard states,

ΔrG∘=−zFEcell∘Where,z= Electron numberF=Faraday constant=96,485 C mol−1Ecell∘=Standard Electron cell potential

The electron number, z, for a reaction depends on how the reaction is written.

ΔrG∘=−RTlnK−RTlnK=−zFEcell∘∴lnK=−zFE cell∘−RTlnK=11604 C J-1zE cell∘TK=e11604 C J -1 z E cell ∘ T

Interpretation Introduction

(b)

Interpretation:

The value of K for the given reaction at 25 ° C should be calculated.

MnO2(s)+4H+(aq)+2Cl-(aq)→Mn2+(aq)+2H2O(l)+Cl2(g)

Concept introduction:

The E°_c_e_l_l value for a redox reaction gives by following equation.

E°cell=E°Reduction−E°Oxidation

When the reactants and products are in their standard states,

ΔrG∘=−zFEcell∘Where,z= Electron numberF=Faraday constant=96,485 C mol−1Ecell∘=Standard Electron cell potential

The electron number, z, for a reaction depends on how the reaction is written.

ΔrG∘=−RTlnK−RTlnK=−zFEcell∘∴lnK=−zFE cell∘−RTlnK=11604 C J-1zE cell∘TK=e11604 C J -1 z E cell ∘ T

Interpretation Introduction

(c)

Interpretation:

The value of K for the given reaction at 25 ° Cshould be calculated.

2OCl-(aq)→2Cl−(aq)+O2(g)

Concept introduction:

The E°_c_e_l_l value for a redox reaction gives by following equation.

E°cell=E°Reduction−E°Oxidation

When the reactants and products are in their standard states,

ΔrG∘=−zFEcell∘Where,z= Electron numberF=Faraday constant=96,485 C mol−1Ecell∘=Standard Electron cell potential

The electron number, z, for a reaction depends on how the reaction is written.

ΔrG∘=−RTlnK−RTlnK=−zFEcell∘∴lnK=−zFE cell∘−RTlnK=11604 C J-1zE cell∘TK=e11604 C J -1 z E cell ∘ T

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Answer 4

Question

Chapter 19, Problem 26E

Interpretation Introduction

(a)

Interpretation:

The value of K for the given reaction at 25 ° C should be calculated.

Ni(s)+2V3+(aq)→2V2+(aq)+Ni2+(aq)

Concept introduction:

The E°_c_e_l_l value for a redox reaction gives by following equation.

E°cell=E°Reduction−E°Oxidation

When the reactants and products are in their standard states,

ΔrG∘=−zFEcell∘Where,z= Electron numberF=Faraday constant=96,485 C mol−1Ecell∘=Standard Electron cell potential

The electron number, z, for a reaction depends on how the reaction is written.

ΔrG∘=−RTlnK−RTlnK=−zFEcell∘∴lnK=−zFE cell∘−RTlnK=11604 C J-1zE cell∘TK=e11604 C J -1 z E cell ∘ T

Interpretation Introduction

(b)

Interpretation:

The value of K for the given reaction at 25 ° C should be calculated.

MnO2(s)+4H+(aq)+2Cl-(aq)→Mn2+(aq)+2H2O(l)+Cl2(g)

Concept introduction:

The E°_c_e_l_l value for a redox reaction gives by following equation.

E°cell=E°Reduction−E°Oxidation

When the reactants and products are in their standard states,

ΔrG∘=−zFEcell∘Where,z= Electron numberF=Faraday constant=96,485 C mol−1Ecell∘=Standard Electron cell potential

The electron number, z, for a reaction depends on how the reaction is written.

ΔrG∘=−RTlnK−RTlnK=−zFEcell∘∴lnK=−zFE cell∘−RTlnK=11604 C J-1zE cell∘TK=e11604 C J -1 z E cell ∘ T

Interpretation Introduction

(c)

Interpretation:

The value of K for the given reaction at 25 ° Cshould be calculated.

2OCl-(aq)→2Cl−(aq)+O2(g)

Concept introduction:

The E°_c_e_l_l value for a redox reaction gives by following equation.

E°cell=E°Reduction−E°Oxidation

When the reactants and products are in their standard states,

ΔrG∘=−zFEcell∘Where,z= Electron numberF=Faraday constant=96,485 C mol−1Ecell∘=Standard Electron cell potential

The electron number, z, for a reaction depends on how the reaction is written.

ΔrG∘=−RTlnK−RTlnK=−zFEcell∘∴lnK=−zFE cell∘−RTlnK=11604 C J-1zE cell∘TK=e11604 C J -1 z E cell ∘ T

Expert Solution & Answer

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Check out a sample textbook solution

See solution

Answer 5

Chapter 19, Problem 26E

Interpretation Introduction

(a)

Interpretation:

The value of K for the given reaction at 25 ° C should be calculated.

Ni(s)+2V3+(aq)→2V2+(aq)+Ni2+(aq)

Concept introduction:

The E°_c_e_l_l value for a redox reaction gives by following equation.

E°cell=E°Reduction−E°Oxidation

When the reactants and products are in their standard states,

ΔrG∘=−zFEcell∘Where,z= Electron numberF=Faraday constant=96,485 C mol−1Ecell∘=Standard Electron cell potential

The electron number, z, for a reaction depends on how the reaction is written.

ΔrG∘=−RTlnK−RTlnK=−zFEcell∘∴lnK=−zFE cell∘−RTlnK=11604 C J-1zE cell∘TK=e11604 C J -1 z E cell ∘ T

Interpretation Introduction

(b)

Interpretation:

The value of K for the given reaction at 25 ° C should be calculated.

MnO2(s)+4H+(aq)+2Cl-(aq)→Mn2+(aq)+2H2O(l)+Cl2(g)

Concept introduction:

The E°_c_e_l_l value for a redox reaction gives by following equation.

E°cell=E°Reduction−E°Oxidation

When the reactants and products are in their standard states,

ΔrG∘=−zFEcell∘Where,z= Electron numberF=Faraday constant=96,485 C mol−1Ecell∘=Standard Electron cell potential

The electron number, z, for a reaction depends on how the reaction is written.

ΔrG∘=−RTlnK−RTlnK=−zFEcell∘∴lnK=−zFE cell∘−RTlnK=11604 C J-1zE cell∘TK=e11604 C J -1 z E cell ∘ T

Interpretation Introduction

(c)

Interpretation:

The value of K for the given reaction at 25 ° Cshould be calculated.

2OCl-(aq)→2Cl−(aq)+O2(g)

Concept introduction:

The E°_c_e_l_l value for a redox reaction gives by following equation.

E°cell=E°Reduction−E°Oxidation

When the reactants and products are in their standard states,

ΔrG∘=−zFEcell∘Where,z= Electron numberF=Faraday constant=96,485 C mol−1Ecell∘=Standard Electron cell potential

The electron number, z, for a reaction depends on how the reaction is written.

ΔrG∘=−RTlnK−RTlnK=−zFEcell∘∴lnK=−zFE cell∘−RTlnK=11604 C J-1zE cell∘TK=e11604 C J -1 z E cell ∘ T

Answer 6

Chapter 19, Problem 26E

Interpretation Introduction

(a)

Interpretation:

The value of K for the given reaction at 25 ° C should be calculated.

Ni(s)+2V3+(aq)→2V2+(aq)+Ni2+(aq)

Concept introduction:

The E°_c_e_l_l value for a redox reaction gives by following equation.

E°cell=E°Reduction−E°Oxidation

When the reactants and products are in their standard states,

ΔrG∘=−zFEcell∘Where,z= Electron numberF=Faraday constant=96,485 C mol−1Ecell∘=Standard Electron cell potential

The electron number, z, for a reaction depends on how the reaction is written.

ΔrG∘=−RTlnK−RTlnK=−zFEcell∘∴lnK=−zFE cell∘−RTlnK=11604 C J-1zE cell∘TK=e11604 C J -1 z E cell ∘ T

Answer 7

Chapter 19, Problem 26E

Interpretation Introduction

(a)

Interpretation:

The value of K for the given reaction at 25 ° C should be calculated.

Ni(s)+2V3+(aq)→2V2+(aq)+Ni2+(aq)

Concept introduction:

The E°_c_e_l_l value for a redox reaction gives by following equation.

E°cell=E°Reduction−E°Oxidation

When the reactants and products are in their standard states,

ΔrG∘=−zFEcell∘Where,z= Electron numberF=Faraday constant=96,485 C mol−1Ecell∘=Standard Electron cell potential

The electron number, z, for a reaction depends on how the reaction is written.

ΔrG∘=−RTlnK−RTlnK=−zFEcell∘∴lnK=−zFE cell∘−RTlnK=11604 C J-1zE cell∘TK=e11604 C J -1 z E cell ∘ T

Answer 8

Interpretation Introduction

(b)

Interpretation:

The value of K for the given reaction at 25 ° C should be calculated.

MnO2(s)+4H+(aq)+2Cl-(aq)→Mn2+(aq)+2H2O(l)+Cl2(g)

Concept introduction:

The E°_c_e_l_l value for a redox reaction gives by following equation.

E°cell=E°Reduction−E°Oxidation

When the reactants and products are in their standard states,

ΔrG∘=−zFEcell∘Where,z= Electron numberF=Faraday constant=96,485 C mol−1Ecell∘=Standard Electron cell potential

The electron number, z, for a reaction depends on how the reaction is written.

ΔrG∘=−RTlnK−RTlnK=−zFEcell∘∴lnK=−zFE cell∘−RTlnK=11604 C J-1zE cell∘TK=e11604 C J -1 z E cell ∘ T

Answer 9

Interpretation Introduction

(b)

Interpretation:

The value of K for the given reaction at 25 ° C should be calculated.

MnO2(s)+4H+(aq)+2Cl-(aq)→Mn2+(aq)+2H2O(l)+Cl2(g)

Concept introduction:

The E°_c_e_l_l value for a redox reaction gives by following equation.

E°cell=E°Reduction−E°Oxidation

When the reactants and products are in their standard states,

ΔrG∘=−zFEcell∘Where,z= Electron numberF=Faraday constant=96,485 C mol−1Ecell∘=Standard Electron cell potential

The electron number, z, for a reaction depends on how the reaction is written.

ΔrG∘=−RTlnK−RTlnK=−zFEcell∘∴lnK=−zFE cell∘−RTlnK=11604 C J-1zE cell∘TK=e11604 C J -1 z E cell ∘ T

Answer 10

Interpretation Introduction

(c)

Interpretation:

The value of K for the given reaction at 25 ° Cshould be calculated.

2OCl-(aq)→2Cl−(aq)+O2(g)

Concept introduction:

The E°_c_e_l_l value for a redox reaction gives by following equation.

E°cell=E°Reduction−E°Oxidation

When the reactants and products are in their standard states,

ΔrG∘=−zFEcell∘Where,z= Electron numberF=Faraday constant=96,485 C mol−1Ecell∘=Standard Electron cell potential

The electron number, z, for a reaction depends on how the reaction is written.

ΔrG∘=−RTlnK−RTlnK=−zFEcell∘∴lnK=−zFE cell∘−RTlnK=11604 C J-1zE cell∘TK=e11604 C J -1 z E cell ∘ T

Answer 11

Interpretation Introduction

(c)

Interpretation:

The value of K for the given reaction at 25 ° Cshould be calculated.

2OCl-(aq)→2Cl−(aq)+O2(g)

Concept introduction:

The E°_c_e_l_l value for a redox reaction gives by following equation.

E°cell=E°Reduction−E°Oxidation

When the reactants and products are in their standard states,

ΔrG∘=−zFEcell∘Where,z= Electron numberF=Faraday constant=96,485 C mol−1Ecell∘=Standard Electron cell potential

The electron number, z, for a reaction depends on how the reaction is written.

ΔrG∘=−RTlnK−RTlnK=−zFEcell∘∴lnK=−zFE cell∘−RTlnK=11604 C J-1zE cell∘TK=e11604 C J -1 z E cell ∘ T

Answer 12

Expert Solution & Answer

Answer 13

Expert Solution & Answer

Answer 14

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Answer 15

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Solution Summary: The author explains how the value of K for the given reaction at 25 ° C should be calculated.

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