Chapter 19, Problem 19.47QP

Interpretation Introduction

Interpretation:

What must the activation energy be for the rate constant to double as by given information has to be determined.

Concept introduction:

The activation energy from the given information has to be calculated from the modified Arrhenius equation.

$\ln \frac{k_1}{k_2}=\frac{E_a}{R}\left[\frac{1}{T_2}-\frac{1}{T_1}\right]$

Arrhenius equation:

• Arrhenius equation is a formula that represents the temperature dependence of reaction rates
• The Arrhenius equation has to be represented as follows

$k=A{e}^{-E_a/RT}$

• $E_a$ represents the activation energy and it’s unit is kJ/mol
• R represents the universal gas constant and it has the value of 8.314 J/K.mol
• T represents the absolute temperature
• A represents the frequency factor or collision frequency
• e represents the base of natural logarithm
•  Arrhenius equation equation was proposed by Svante Arrhenius in 1889.