Electronics Fundamentals: Circuits, Devices & Applications
8th Edition
ISBN: 9780135072950
Author: Thomas L. Floyd, David Buchla
Publisher: Prentice Hall
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Chapter 18, Problem 4ST
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Chapter 18 Solutions
Electronics Fundamentals: Circuits, Devices & Applications
Ch. 18 - When a diff-amp has identical signals on both...Ch. 18 - A high CMRR for a diff-amp means the common-mode...Ch. 18 - Prob. 3TFQCh. 18 - The open-loop voltage gain of an op-amp is also...Ch. 18 - Prob. 5TFQCh. 18 - Prob. 6TFQCh. 18 - In a voltage-follower, the open-loop and...Ch. 18 - Prob. 8TFQCh. 18 - Prob. 9TFQCh. 18 - If the feedback resistor in an amplifier is open,...
Ch. 18 - Which characteristic docs not necessarily apply to...Ch. 18 - In selecting an op-amp. suppose you have several...Ch. 18 - Prob. 3STCh. 18 - Prob. 4STCh. 18 - Prob. 5STCh. 18 - Prob. 6STCh. 18 - Prob. 7STCh. 18 - Prob. 8STCh. 18 - If you know an op-amp's open-loop gain and nothing...Ch. 18 - Prob. 10STCh. 18 - Prob. 11STCh. 18 - The highest possible input resistance is achieved...Ch. 18 - Compare a practical op-amp to an ideal op-amp.Ch. 18 - Two IC op-amps are available to you. Their...Ch. 18 - Identify the type of input and output...Ch. 18 - Prob. 4PCh. 18 - A certain diff-amp has a differential gain of 60...Ch. 18 - A certain diff-amp has a CMRR of 65 dB. If the...Ch. 18 - Identify the type of input mode for each op-amp in...Ch. 18 - Show the common-mode input in Figure 18-37 in an...Ch. 18 - Determine the bias current, IBIAS, given that the...Ch. 18 - Distinguish between input bias current and input...Ch. 18 - A certain op-amp has a CMRR of 250,000. Convert...Ch. 18 - The open-loop gain of a certain op-amp is 175,000....Ch. 18 - The op-amp data sheet specifies a CMRR of 300,000...Ch. 18 - Figure 18-38 shows the output voltage of an op-amp...Ch. 18 - How long does it take the output voltage of an...Ch. 18 - Identify each of the op-amp configurations in...Ch. 18 - For the amplifier in Figure 18-40. determine the...Ch. 18 - Determine the closed-loop gain of each amplifier...Ch. 18 - Find the value of Rf that will produce the...Ch. 18 - Find the gain of each in amplifier in Figure...Ch. 18 - If a signal voltage of 10 mV applied to each...Ch. 18 - Determine the approximate values for each of the...Ch. 18 - Determine the input and output resistances for...Ch. 18 - Repeat Problem 23 for each circuit in Figure...Ch. 18 - Repeat Problem 23 for each circuit in Figure...Ch. 18 - Prob. 26PCh. 18 - Prob. 28PCh. 18 - Prob. 29PCh. 18 - Prob. 30PCh. 18 - Prob. 31PCh. 18 - Prob. 32P
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- With a PNP circuit, the most positive voltage is probably: O ground VC VBE VCCarrow_forwardIn the following circuit the op-amp is ideal, but it has an input offset voltage of 2 mV. What is the output voltage? 6 k2 1.5 kn 60 mVarrow_forwardA non-inverting comparator circuit has a voltage reference of 500 mV. If the input voltage is varying linearly between 100 mV to 400 mV, the output will saturate to a Vi Vref= 500mV -Vo O positive value all the time O negative value all the time O positive value for the range 100mV to 400mV then goes negative afterwards O negative value for the range 100mV to 400mV then goes positive afterwardsarrow_forward
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- Determine the current iz for the op amp circuit. 6kN iz 8k2 6k2 2V(* 4k2 4k2 6kO 8kΩ 6k2 5.8V*arrow_forwardQuestions: [1] Draw output waveform for the following circuits if input of 4V peak- to-peak with zero offset is applied. C1 D2 4 Vpp 4 Vpp C1 Hilm THI +27 D2 10x >10Karrow_forwardIf I have an input sine wave in a peak detector circuit I know the output the the first op amp (that will feed back into the negative terminal) should be a little larger than the input (this is why you add a second op amp). I'm not understanding it graphically. Splitting up the circuit say you have the first op amp and the diode (no capacitor or second op amp). the output should be only the positive part of sine wave, and the amplitude will be the amplitude input minus .6V from the diode drop, right? Then adding the capacitor it keeps the same amplitude but makes more DC. with the second op amp this makes it so the capacitor doesn't discharge (which is what keeps the voltage proper up I think?) With my logic here, the voltage feeding back into the first op amp negative terminal is the voltage input, minus a diode drop. So Vin > V- (voltage feeding back into the negative terminal). Which I'm pretty sure V- is supposed to be larger. So I think I'm misunderstand something here. Please…arrow_forward
- Consider the following circuit: Vin R1 o Veut R2 R3 If R = R2 = R3, is the output voltage just divided twice, or 1/4 the input voltage? Why or why not? What is the output voltage?arrow_forward5) With reference to the circuit diagram given below describe in detail the operation of the circuit diagram with all the applicable waveforms for output voltage, out put current and voltage across the thyristors with alpha=90 degrees Vs = Vo V„ sin wr (a)arrow_forwardWhat is the total input resistance? What is the dc output voltage? Vcc +5.5 V R1 10 kN C Bac = 100 BDc = 90 10μF oV out R2 4.7 kN RE 1.0 kNarrow_forward
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