Stats: Modeling the World Nasta Edition Grades 9-12
Stats: Modeling the World Nasta Edition Grades 9-12
3rd Edition
ISBN: 9780131359581
Author: David E. Bock, Paul F. Velleman, Richard D. De Veaux
Publisher: PEARSON
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Question
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Chapter 18, Problem 4E

(a)

To determine

To explain what should the theoretical mean and standard deviations be for these sample sizes, according to the central limit theorem.

(a)

Expert Solution
Check Mark

Answer to Problem 4E

The theoretical mean for all the sample sizes be 0.85 . And the theoretical standard deviation is:

  0.0799,0.0505,0.0412,0.0357 respectively for the sample sizes.

Explanation of Solution

It is given in the question, the estimation of what might happen when the automatic recognition character device reads a stack of application is given. Thus, the four different sample sizes as of size 20,50,75,100 are also given. Thus, as given in the question the theoretical mean for all the sample sizes be 0.85 . And the theoretical standard deviation can be calculated as:

  S.D.=pqn

Thus, for all the sample sizes it can be calculated as:

  Stats: Modeling the World Nasta Edition Grades 9-12, Chapter 18, Problem 4E , additional homework tip  1

(b)

To determine

To explain how close are those theoretical values to what was observed in these simulations.

(b)

Expert Solution
Check Mark

Answer to Problem 4E

They look very similar in values.

Explanation of Solution

It is given in the question, the estimation of what might happen when the automatic recognition character device reads a stack of application is given. Thus, the four different sample sizes as of size 20,50,75,100 are also given. As we see at the table for the observed means and the standard deviation and the theoretical means and the standard deviation as follows:

  Stats: Modeling the World Nasta Edition Grades 9-12, Chapter 18, Problem 4E , additional homework tip  2

Thus, by comparing the theoretical vales with the observed values we can see that they seems very similar in values.

(c)

To determine

To find out at what sample size would you be comfortable using the Normal model as an approximation for the sampling distribution, by looking at the histogram in previous exercise.

(c)

Expert Solution
Check Mark

Answer to Problem 4E

The sample size would you be comfortable using the Normal model as an approximation for the sampling distribution is the sample size of 100 .

Explanation of Solution

It is given in the question, the estimation of what might happen when the automatic recognition character device reads a stack of application is given. Thus, the four different sample sizes as of size 20,50,75,100 are also given. As we see at the table for the observed means and the standard deviation and the theoretical means and the standard deviation as follows:

  Stats: Modeling the World Nasta Edition Grades 9-12, Chapter 18, Problem 4E , additional homework tip  3

Thus, the sample size would you be comfortable using the Normal model as an approximation for the sampling distribution, by looking at the histogram in previous exercise is the sample size of 100 as the histogram of this sample size is uni-modal and symmetric in nature and it is very similar to normal graph than compared to other graphs of the other sample sizes.

(d)

To determine

To explain what does the success or failure condition say about the choice you made in part (c).

(d)

Expert Solution
Check Mark

Explanation of Solution

It is given in the question, the estimation of what might happen when the automatic recognition character device reads a stack of application is given. Thus, the four different sample sizes as of size 20,50,75,100 are also given. As we see at the table for the observed means and the standard deviation and the theoretical means and the standard deviation as follows

  Stats: Modeling the World Nasta Edition Grades 9-12, Chapter 18, Problem 4E , additional homework tip  4

Thus, the sample size would you be comfortable using the Normal model as an approximation for the sampling distribution, by looking at the histogram in previous exercise is the sample size of 100 . Thus, the success and the failure can be calculated for this sample size as:

  np=100(0.85)=85n(1p)=100(10.85)=100(0.15)=15

Thus, it is viable because there are at least ten people for both the successes and failures.

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