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The trapeze/lanyard air drop
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Vector Mechanics For Engineers
- A 35 g steel ball is held by a ceiling-mounted electromagnet 3.4 m above the floor. A compressed-air cannon sits on the floor, 5.0 m to one side of the point directly under the ball. When a button is pressed, the ball drops and, simultaneously, the cannon fires a 25 g plastic ball. The two balls collide 1.2 m above the floor. What was the launch speed of the plastic ball?arrow_forwardStarting from a standstill, Abi (mass = 55.00 kg) performs a vertical jump. c.) If the duration of the take-off phase is 1.50 seconds, what is the impulse exerted on Abi during this jump? Uploadarrow_forward1.A person is to be released from rest on a swing pulled away from the vertical by an angle of 20.0°. The two frayed ropes of the swing are 2.75 m long, and will break if the tension in either of them exceeds 355 N. (a) What is the maximum weight the person can have and not break the ropes? (b)If the person is released at an angle greater than 20.0°, does the maximum weight increase, decrease, or stay the same? (c)Solve in Newton Law, Conversation Law, and Work-Kinetic Theorem.arrow_forward
- Oblique Impact To analyze an oblique impact using the conservation of momentum and coefficient of restitution. When an oblique impact occurs between two smooth particles, the particles move away from each other with velocity vectors that have unknown directions and unknown magnitudes. If the y axis is within the plane of contact and the x axis is the line of impact, the impulsive forces of deformation and restitution act only along the line of impact (the x axis). Momentum of the system is conserved along the line of impact (the x axis): ∑m(vx)1=∑m(vx)2 The coefficient of restitution, e, relates the relative-velocity components of the particles along the line of impact (the x axis): e=(vBx)2−(vAx)2(vAx)1−(vBx)1 The momenta of both particles A and B are conserved in the plane of contact (the y axis) because no impulse acts on either particle in this plane. Therefore, the y component of the velocities before and after the collisions remains unchanged: (vy)1=(vy)2 As shown,…arrow_forwardOblique Impact To analyze an oblique impact using the conservation of momentum and coefficient of restitution. When an oblique impact occurs between two smooth particles, the particles move away from each other with velocity vectors that have unknown directions and unknown magnitudes. If the y axis is within the plane of contact and the x axis is the line of impact, the impulsive forces of deformation and restitution act only along the line of impact (the x axis). Momentum of the system is conserved along the line of impact (the x axis): ∑m(vx)1=∑m(vx)2 The coefficient of restitution, e, relates the relative-velocity components of the particles along the line of impact (the x axis): e=(vBx)2−(vAx)2(vAx)1−(vBx)1 The momenta of both particles A and B are conserved in the plane of contact (the y axis) because no impulse acts on either particle in this plane. Therefore, the y component of the velocities before and after the collisions remains unchanged: Immediately after the collision,…arrow_forwardA small block (block 1) of mass m, attached to an ideal string of length L, is initially held so that the string is taut and horizontal at height Labove a frictionless table, as shown in Fig.2. A second small block (block 2) of mass 3mis placed on the table right under the point of attachment of the string holding block 1. The tabletop is at height 2L above the floor. Block 1 is then released from rest and collides elastically with block 2 at time t=0. The acceleration due to gravity has magnitude g and air resistance is negligible. a) Determine the horizontal distance traveled by block 2as a projectile. b)Determine the speed and direction of motion of block 1 right after the collision. c) Determine the maximum angular displacement (measured from the vertical direction) of block 1 after the collision.arrow_forward
- A small block (block 1) of mass m, attached to an ideal string of length L, is initially held so that the string is taut and horizontal at height Labove a frictionless table, as shown in Fig.2. A second small block (block 2) of mass 3mis placed on the table right under the point of attachment of the string holding block 1. The tabletop is at height 2L above the floor. Block 1 is then released from rest and collides elastically with block 2 at time t=0. The acceleration due to gravity has magnitude g and air resistance is negligible. a)Determine the time t2at which block 2 hits the floor. b) Determine the horizontal distance traveled by block 2as a projectile. c)Determine the speed and direction of motion of block 1 right after the collision.arrow_forwardIf either a simple or a compound pendulum is used to determine experimentally the acceleration of gravity g, difficulties are encountered. In the case of the simple pendulum, the string is not truly weightless, while in the case of the compound pendulum, the exact location of the mass center is difficult to establish. In the case of a compound pendulum, the difficulty can be eliminated by using a reversible, or Kater, pendulum. Two knife edges A and B are placed so that they are obviously not at the same distance from the mass center G, and the distance l is measured with great precision. The position of a counterweight D is then adjusted so that the period of oscillation τ obtained is equal to that of a true simple pendulum of length l and that g 4π2 l/τ.arrow_forward4. When only conservative forces are acting on a system, we can use the conservation of energy theorem to solve a problem. Recall from particle kinetics: T₁ + V₁ = T2 + V2, where V is potential energy (due to both gravitational and elastic forces: V₂ = Wyc and Ve= + ½ ks², respectively). The 30-kg rod is released from rest when 0 = 45°. The spring is unstretched when 0 = 45°. Using conservation of energy theorem, determine the angular velocity of the rod when 0 = 0°. B 1.5 m k = 300 N/m Aarrow_forward
- Choose the correct answer of the following questions: 1. If no external impressed force acts on the system, the total momentum (G) of a system ... c. remains constant a. increases b. decreases d. none of the these 2. Which of the following cases momentum is conserved? (1 M) a. Perfectly elastic impact d. Momentum is always conserved c. Perfectly inelastic impact b. plastic impact with 0arrow_forwardPart 3 A lift cage in a mining operation has a mass of 1000kg when empty. When a fully laden with a mass of 700kg it is lowered with uniform acceleration such that after 200m its velocity is 25m/s. By constructing free body diagrams and using D'Alembert's principle determine: (a) the tension in the cable of the lift. (b) the reaction force exerted by the load in the lift.arrow_forwardShow the complete solution. Put notes on steps. The wooden block (mass m = 0.6165 kg) is released from rest at A by a compressed spring (compressed length 0.6 m, undeformed length 1 m, spring constant k = 150 N/m). The block is allowed to slide through the rough horizontal surface (A to B), then along the smooth circular ramp (B to C, central angle 0 = 45°, until the block is released after point C. Calculate the speed of the block at points B and C. Also, what is the magnitude of the normal force exerted to the block just before the block leaves the ramp? Neglect the geometry of the block.NOTE: Use Work-Energy Method to solve for the speeds; use Force-Mass-Acceleration (FMA) Method to compute for the normal force.arrow_forwardarrow_back_iosSEE MORE QUESTIONSarrow_forward_ios
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