For the given cycloheptatrienone and cyclopentadienone, the more partial negative character on the oxygen atom of cycloheptatrienone should be explained. Concept introduction: A five membered ring will be aromatic if it contains six π electrons. In order to have six π electrons, one of the carbon atoms must possess two electrons. It should be a carbanion. A seven membered ring will be aromatic if it contains six π electrons. In order to have six π electrons in a seven membered ring one of the carbon atom must possess an empty p orbital. This carbocation exhibits a continuous system of overlapping and p orbitals and has six π electrons . Aromatic compounds are more stable than non-aromatic compound Cycloheptatrienone reveals resonance structures with aromatic character Cyclopentadienone reveals resonance structures with anti-aromatic character

Question

Want to see the full answer?

Answer 1

Question

Chapter 17, Problem 55IP

Interpretation Introduction

Interpretation: For the given cycloheptatrienone and cyclopentadienone, the more partial negative character on the oxygen atom of cycloheptatrienone should be explained.

Concept introduction:

A five membered ring will be aromatic if it contains six π electrons. In order to have six π electrons, one of the carbon atoms must possess two electrons. It should be a carbanion.

A seven membered ring will be aromatic if it contains six π electrons. In order to have six π electrons in a seven membered ring one of the carbon atom must possess an empty p orbital. This carbocation exhibits a continuous system of overlapping and p orbitals and has six π electrons.

Aromatic compounds are more stable than non-aromatic compound

Cycloheptatrienone reveals resonance structures with aromatic character

Cyclopentadienone reveals resonance structures with anti-aromatic character

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 2

Question

Chapter 17, Problem 55IP

Interpretation Introduction

Interpretation: For the given cycloheptatrienone and cyclopentadienone, the more partial negative character on the oxygen atom of cycloheptatrienone should be explained.

Concept introduction:

A five membered ring will be aromatic if it contains six π electrons. In order to have six π electrons, one of the carbon atoms must possess two electrons. It should be a carbanion.

A seven membered ring will be aromatic if it contains six π electrons. In order to have six π electrons in a seven membered ring one of the carbon atom must possess an empty p orbital. This carbocation exhibits a continuous system of overlapping and p orbitals and has six π electrons.

Aromatic compounds are more stable than non-aromatic compound

Cycloheptatrienone reveals resonance structures with aromatic character

Cyclopentadienone reveals resonance structures with anti-aromatic character

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 3

Question

Chapter 17, Problem 55IP

Interpretation Introduction

Interpretation: For the given cycloheptatrienone and cyclopentadienone, the more partial negative character on the oxygen atom of cycloheptatrienone should be explained.

Concept introduction:

A five membered ring will be aromatic if it contains six π electrons. In order to have six π electrons, one of the carbon atoms must possess two electrons. It should be a carbanion.

A seven membered ring will be aromatic if it contains six π electrons. In order to have six π electrons in a seven membered ring one of the carbon atom must possess an empty p orbital. This carbocation exhibits a continuous system of overlapping and p orbitals and has six π electrons.

Aromatic compounds are more stable than non-aromatic compound

Cycloheptatrienone reveals resonance structures with aromatic character

Cyclopentadienone reveals resonance structures with anti-aromatic character

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 4

Question

Chapter 17, Problem 55IP

Interpretation Introduction

Interpretation: For the given cycloheptatrienone and cyclopentadienone, the more partial negative character on the oxygen atom of cycloheptatrienone should be explained.

Concept introduction:

A five membered ring will be aromatic if it contains six π electrons. In order to have six π electrons, one of the carbon atoms must possess two electrons. It should be a carbanion.

A seven membered ring will be aromatic if it contains six π electrons. In order to have six π electrons in a seven membered ring one of the carbon atom must possess an empty p orbital. This carbocation exhibits a continuous system of overlapping and p orbitals and has six π electrons.

Aromatic compounds are more stable than non-aromatic compound

Cycloheptatrienone reveals resonance structures with aromatic character

Cyclopentadienone reveals resonance structures with anti-aromatic character

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 5

Chapter 17, Problem 55IP

Interpretation Introduction

Interpretation: For the given cycloheptatrienone and cyclopentadienone, the more partial negative character on the oxygen atom of cycloheptatrienone should be explained.

Concept introduction:

A five membered ring will be aromatic if it contains six π electrons. In order to have six π electrons, one of the carbon atoms must possess two electrons. It should be a carbanion.

A seven membered ring will be aromatic if it contains six π electrons. In order to have six π electrons in a seven membered ring one of the carbon atom must possess an empty p orbital. This carbocation exhibits a continuous system of overlapping and p orbitals and has six π electrons.

Aromatic compounds are more stable than non-aromatic compound

Cycloheptatrienone reveals resonance structures with aromatic character

Cyclopentadienone reveals resonance structures with anti-aromatic character

Answer 6

Chapter 17, Problem 55IP

Interpretation Introduction

Interpretation: For the given cycloheptatrienone and cyclopentadienone, the more partial negative character on the oxygen atom of cycloheptatrienone should be explained.

Concept introduction:

A five membered ring will be aromatic if it contains six π electrons. In order to have six π electrons, one of the carbon atoms must possess two electrons. It should be a carbanion.

A seven membered ring will be aromatic if it contains six π electrons. In order to have six π electrons in a seven membered ring one of the carbon atom must possess an empty p orbital. This carbocation exhibits a continuous system of overlapping and p orbitals and has six π electrons.

Aromatic compounds are more stable than non-aromatic compound

Cycloheptatrienone reveals resonance structures with aromatic character

Cyclopentadienone reveals resonance structures with anti-aromatic character

Answer 7

Chapter 17, Problem 55IP

Interpretation Introduction

Interpretation: For the given cycloheptatrienone and cyclopentadienone, the more partial negative character on the oxygen atom of cycloheptatrienone should be explained.

Concept introduction:

A five membered ring will be aromatic if it contains six π electrons. In order to have six π electrons, one of the carbon atoms must possess two electrons. It should be a carbanion.

A seven membered ring will be aromatic if it contains six π electrons. In order to have six π electrons in a seven membered ring one of the carbon atom must possess an empty p orbital. This carbocation exhibits a continuous system of overlapping and p orbitals and has six π electrons.

Aromatic compounds are more stable than non-aromatic compound

Cycloheptatrienone reveals resonance structures with aromatic character

Cyclopentadienone reveals resonance structures with anti-aromatic character

Answer 8

Expert Solution & Answer

Answer 9

Expert Solution & Answer

Answer 10

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 11

Ch. 17.2 - Prob. 1LTS Ch. 17.2 - Prob. 1PTS Ch. 17.2 - Prob. 2PTS Ch. 17.2 - Prob. 3PTS Ch. 17.2 - Prob. 4PTS Ch. 17.4 - Prob. 6CC Ch. 17.4 - Prob. 8CC Ch. 17.4 - Prob. 9CC Ch. 17.5 - Prob. 10CC Ch. 17.5 - Prob. 2LTS

Want to see the full answer?

Chapter 17 Solutions