Chapter 17, Problem 44P

To determine

The value of charge flow from the battery will be calculated.

Answer to Problem 44P

The answer is $4.6\times {10}^{-7}C$ .

Explanation of Solution

Given data:

Capacitor $C_{initial}=3.5\times {10}^{-9}F$

Voltage of battery $V=22V$

Formula used:

It is known that: $\Delta Q=\left(K-1\right)CV$

Where,

  $Q$ is the charge.

  $K$ is the dielectric constant.

  $\text{C}$ is the capacitance of capacitor.

  $V$ is the potential.

Calculation:

When mica is inserted the capacitance $Q_{initial}=K{C}_{initial}$ changes to $C_{final}=K{C}_{initial}$ and voltage remains unchanged as capacitor is connected to the same battery. Hence charge will be

  $\Delta Q=\left(K-1\right)CV$

  $\Delta Q=\left(7-1\right)\left(3.5\times {10}^{-9}F\right)\left(22V\right)$

  $\Delta Q=4.6\times {10}^{-7}C$

Conclusion: The value of charge flow from the battery will be $4.6\times {10}^{-7}C$ .