Chapter 17, Problem 33P

To determine

Capacitance of two wires.

Answer to Problem 33P

The answer is $7.9\times {10}^{-13}F$ .

Explanation of Solution

Given:

Charge is $95pC=95\times {10}^{-12}C$

Potential difference is $120V$

Formula used:

It is known that $Q=CV$ , here the amount of charge $Q$ acquired by each plate is proportional to the magnitudes of potential difference $V$ b/w them.

Calculation:

The capacitance is found from $Q=CV\to C=\frac{Q}{V}$

  $=\frac{95\times {10}^{-12}C}{120V}=7.9\times {10}^{-13}F$

Conclusion:

The required value is $7.9\times {10}^{-13}F$ .