Concept explainers
Interpretation:
Most abundant element in Earth’s crust and universe as a whole has to be chosen from the given options.
Concept Introduction:
Element is a pure substance and it cannot be broken down into simpler pure substance by chemical means like
Elements that are laboratory synthesized are radioactive in nature and they convert back into the original naturally occurring element by emission of radiation. All the elements that occur naturally are not evenly distributed on earth and universe.
Radiations that are emitted from stars can be used to estimate the elemental composition of universe. This indicates that hydrogen and helium are mostly dominant. On Earth’s crust oxygen and silicon are the two elements that account for about
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General, Organic, and Biological Chemistry
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- Attempt 1 What is the chemical formula for the compound formed between vanadium(III) and iodine? 13V chemical formula: Incorrect What is the chemical formula for the compound formed between vanadium(III) and sulfur? V2(SO4)3 chemical formula: Incorrectarrow_forwardProblem 5: Lithium has two isotopes: lithium-6 with an atomic mass of 6.0151 amu (atomic mass unit) and lithium-7 with an atomic mass of 7.0160 amu. If the average atomic mass of lithium is 6.941 amu, calculate the natural abundances (in %) of the two isotopes. (10 points)arrow_forwardFree radicals are dangerous because a. they are found incorporated in any radioisotope, including those than can enter the body through the lungs as does radon b. they can be taken into the body in the food eaten if that food has been grown in radioactive soil c. they are substances that are missing some electrons and are extremely active chemically d. all of these responses are correct e. no correct responsearrow_forward
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- Which of the following is heteroatomic and hepta-atomic? O a. P205 Ob. N2H4 OC SF6 More Than One Correct Respońsearrow_forwardExercise 3: Name the following compounds using the preferred IUPAC nomenclature. a. XeF4 b. CuCl с. Mg(CN) d. Au(OH)з e. PC13 f. Cs;N g. CrCl; h. CaO2 i. Cus j. SO2 k. N2O4 1. Ag:0 m. MnO2 n. SnCl2 o. Hg:0arrow_forwardM Tue Jan 5 atoms S1 exercise Exercise 3 B- Calcium Ca belongs to the 4" period and is found just below Mg(Z 12). 1- Find the atomic number of Ca. 2- Calculate its number of neutrons, knowing that it contains 40 nucleons. exercice 4arrow_forward
- General, Organic, and Biological ChemistryChemistryISBN:9781285853918Author:H. Stephen StokerPublisher:Cengage LearningGeneral Chemistry - Standalone book (MindTap Cour...ChemistryISBN:9781305580343Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; DarrellPublisher:Cengage Learning