Physics: Principles with Applications
7th Edition
ISBN: 9780321625922
Author: Douglas C. Giancoli
Publisher: Addison-Wesley
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Textbook Question
Chapter 17, Problem 2P
How much work does the electric field do in moving a proton from a point at a potential of +125 V to a point at -45 V? Express your answer both in joules and electronvolts.
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Physics: Principles with Applications
Ch. 17 - Prob. 1OQCh. 17 - Prob. 1QCh. 17 - If a negative charge is initially at rest in an...Ch. 17 - State clearly the difference (a) between electric...Ch. 17 - An electron is accelerated from rest by a...Ch. 17 - Is there a point along the line joining two equal...Ch. 17 - Prob. 6QCh. 17 - Prob. 7QCh. 17 - Can two equipotential lines cross? ExplainCh. 17 - Prob. 9Q
Ch. 17 - When a battery is connected to a capacitor, why do...Ch. 17 - Prob. 11QCh. 17 - The parallel plates of an isolated capacitor carry...Ch. 17 - Prob. 13QCh. 17 - Prob. 14QCh. 17 - Prob. 15QCh. 17 - Prob. 16QCh. 17 - Prob. 17QCh. 17 - Prob. 18QCh. 17 - Prob. 1MCQCh. 17 - Two identical positive charges are placed near...Ch. 17 - Four identical point charges are arranged at the...Ch. 17 - Prob. 4MCQCh. 17 - Prob. 5MCQCh. 17 - Prob. 6MCQCh. 17 - Prob. 7MCQCh. 17 - Prob. 8MCQCh. 17 - Prob. 9MCQCh. 17 - Prob. 10MCQCh. 17 - Prob. 11MCQCh. 17 - How much work does the electric field do in moving...Ch. 17 - How much work does the electric field do in moving...Ch. 17 - What potential difference is needed to stop an...Ch. 17 - How much kinetic energy will an electron gain (in...Ch. 17 - An electron acquires 6.4510-16 J of kinetic energy...Ch. 17 - How strong is the electric field between two...Ch. 17 - An electric field of 525 V/m is desired between...Ch. 17 - The electric field between two parallel plates...Ch. 17 - What potential difference is needed to give a...Ch. 17 - Two parallel plates, connected to a 45-V power...Ch. 17 - The work done by an external force to move a -6.50...Ch. 17 - What is the speed of an electron with kinetic...Ch. 17 - Prob. 13PCh. 17 - Prob. 14PCh. 17 - An electric field greater than about 3 x 106 V/m...Ch. 17 - 16. (II) An electron starting from rest acquires...Ch. 17 - Prob. 17PCh. 17 - Prob. 18PCh. 17 - Prob. 19PCh. 17 - Prob. 20PCh. 17 - (a) What is the electric potential 2.51015m away...Ch. 17 - Prob. 22PCh. 17 - Prob. 23PCh. 17 - Prob. 24PCh. 17 - Prob. 25PCh. 17 - How much work must be done to bring three...Ch. 17 - Prob. 27PCh. 17 - Prob. 28PCh. 17 - Prob. 29PCh. 17 - Prob. 30PCh. 17 - Prob. 31PCh. 17 - Prob. 32PCh. 17 - Calculate the electric potential due to a dipole...Ch. 17 - The dipole moment, considered as a vector, points...Ch. 17 - Prob. 35PCh. 17 - Prob. 36PCh. 17 - Prob. 37PCh. 17 - Prob. 38PCh. 17 - The charge on a capacitor increases by 15 C when...Ch. 17 - Prob. 40PCh. 17 - If a capacitor has opposite 4.2 µC charges on the...Ch. 17 - Prob. 42PCh. 17 - Prob. 43PCh. 17 - Prob. 44PCh. 17 - Prob. 45PCh. 17 - Prob. 46PCh. 17 - Prob. 47PCh. 17 - What is the capacitance of a pair of circular...Ch. 17 - Prob. 49PCh. 17 - Prob. 50PCh. 17 - Prob. 51PCh. 17 - Prob. 52PCh. 17 - Prob. 53PCh. 17 - Prob. 54PCh. 17 - A homemade capacitor is assembled by placing two...Ch. 17 - Prob. 56PCh. 17 - Prob. 57PCh. 17 - Prob. 58PCh. 17 - Prob. 59PCh. 17 - Prob. 60PCh. 17 - Write the binary number 1010101010101010 as a...Ch. 17 - Prob. 62PCh. 17 - Prob. 63PCh. 17 - Prob. 64PCh. 17 - Prob. 65PCh. 17 - Prob. 66PCh. 17 - Prob. 67PCh. 17 - Prob. 68GPCh. 17 - Prob. 69GPCh. 17 - Prob. 70GPCh. 17 - Prob. 71GPCh. 17 - Prob. 72GPCh. 17 - Prob. 73GPCh. 17 - Dry air will break down if theelectric field...Ch. 17 - Prob. 75GPCh. 17 - Prob. 76GPCh. 17 - Prob. 77GPCh. 17 - Prob. 78GPCh. 17 - Prob. 79GPCh. 17 - Prob. 80GPCh. 17 - Prob. 81GPCh. 17 - Prob. 82GPCh. 17 - Prob. 83GPCh. 17 - Prob. 84GPCh. 17 - Prob. 85GPCh. 17 - Prob. 86GPCh. 17 - Prob. 87GPCh. 17 - Prob. 88GPCh. 17 - Prob. 89GPCh. 17 - Prob. 90GPCh. 17 - Prob. 91GPCh. 17 - Prob. 92GPCh. 17 - Prob. 93GPCh. 17 - In the dynamic random access memory (DRAM)of a...Ch. 17 - Prob. 95GPCh. 17 - Prob. 96GP
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- A small spherical pith ball of radius 0.50 cm is painted with a silver paint and then -10 C of charge is placed on it. The charged pith ball is put at the center of a gold spherical shell of inner radius 2.0 cm and outer radius 2.2 cm. (a) Find the electric potential of the gold shell with respect to zero potential at infinity, (b) How much charge should you put on the gold shell if you want to make its potential 100 V?arrow_forwardThe three charged particles in Figure P20.11 are at the vertices of an isosceles triangle (where d = 2.00 cm). Taking q = 7.00 C, calculate the electric potential at point A, the midpoint of the base. Figure P20.11arrow_forwardIf a proton is released from rest in an electric field, will it move in the direction of increasing or decreasing potential? Also answer this question for an electron and a neutron. Explain why.arrow_forward
- Three particles with equal positive charges q are at the corners of an equilateral triangle of side a as shown in Figure P20.10. (a) At what point, if any, in the plane of the particles is the electric potential zero? (b) What is the electric potential at the position of one of the particles due to the other two particles in the triangle? Figure P20.10arrow_forwardTwo large charged plates of charge density 30C/m2 face each other at a separation of 5.0 mm. (a) Find the electric potential everywhere, (b) An electron is released from rest at the negative plate; with what speed will it strike the positive plate?arrow_forwardWhen a potential difference of 150. V is applied to the plates of an air-filled parallel-plate capacitor, the plates carry a surface charge density of 3.00 1010 C/cm2. What is the spacing between the plates?arrow_forward
- (a) Find the potential difference VB required to stop an electron (called a slopping potential) moving with an initial speed of 2.85 107 m/s. (b) Would a proton traveling at the same speed require a greater or lesser magnitude potential difference? Explain. (c) Find a symbolic expression for the ratio of the proton stopping potential and the electron stopping potential, Vp/Ve. The answer should be in terms of the proton mass mp and electron mass me.arrow_forwardThe two charges in Figure P16.12 are separated by d = 2.00 cm. Find the electric potential at (a) point A and (b) point B, which is hallway between the charges. Figure P16.12arrow_forwardAt a certain distance from a charged particle, the magnitude of the electric field is 500 V/m and the electric potential is 3.00 kV. (a) What is the distance to the particle? (b) What is the magnitude of the charge?arrow_forward
- A filament running along the x axis from the origin to x = 80.0 cm carries electric charge with uniform density. At the point P with coordinates (x = 80.0 cm, y = 80.0 cm), this filament creates electric potential 100 V. Now we add another filament along the y axis, running from the origin to y = 80.0 cm, carrying the same amount of charge with the same uniform density. At the same point P, is the electric potential created by the pair of filaments (a) greater than 200 V, (b) 200 V, (c) 100 V, (d) between 0 and 200 V, or (e) 0?arrow_forwardAn infinite number of charges with q = 2.0 C are placed along the x axis at x = 1.0 m, x = 2.0 m, x = 4.0 m, x = 8.0 m, and so on, as shown in Figure P26.78. Determine the electric potential at the point x = 0 due to this set of charges. Hint: Use the mathematical formula for a geometric series, 1+r+r2+r3+r4+=11r FIGURE P26.78arrow_forwardFigure P26.80 shows a wire with uniform charge per unit length = 2.25 nC/m comprised of two straight sections of length d = 75.0 cm and a semicircle with radius r = 25.0 cm. What is the electric potential at point P, the center of the semicircular portion of the wire? FIGURE P26.80arrow_forward
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Electric Fields: Crash Course Physics #26; Author: CrashCourse;https://www.youtube.com/watch?v=mdulzEfQXDE;License: Standard YouTube License, CC-BY