Physics: Principles with Applications
7th Edition
ISBN: 9780321625922
Author: Douglas C. Giancoli
Publisher: Addison-Wesley
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Chapter 17, Problem 12P
What is the speed of an electron with kinetic energy (a) 850 eV. and (b) 0.50 keV?
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What is the speed of an electron after being accelerated from rest through a 2.5×107 V potential difference?
Express your answer as a fraction of cc.
Suppose an electron (q= -e = -1.6 x 10^-19 C, m = 9.1 x 10^-31 kg) is accelerated from rest through a potential difference of Vab = +5000 V. Solve for the final speed of the electron. Express numerical answer in two significant figures. Use the template in the attached photo to solve for the problem.
Suppose an electron (q = -e = -1.6 x 10¬9 C,m=9.1 x 10¬3' kg) is accelerated from rest through a potential difference of Vab = +5000 V. Solve for
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the final speed of the electron. Express numerical answer in two significant figures.
The potential energy U is related to the electron charge (-e) and potential Vab is related by the equation:
U =
Assuming all potential energy U is converted to kinetic energy K,
K+U = 0
K = -U
1
Since K
mv and using the formula for potential energy above, we arrive at an equation for speed:
2
v = (
1/2
Plugging in values, the value of the electron's speed is:
x 107 m/s
V=
Chapter 17 Solutions
Physics: Principles with Applications
Ch. 17 - Prob. 1OQCh. 17 - Prob. 1QCh. 17 - If a negative charge is initially at rest in an...Ch. 17 - State clearly the difference (a) between electric...Ch. 17 - An electron is accelerated from rest by a...Ch. 17 - Is there a point along the line joining two equal...Ch. 17 - Prob. 6QCh. 17 - Prob. 7QCh. 17 - Can two equipotential lines cross? ExplainCh. 17 - Prob. 9Q
Ch. 17 - When a battery is connected to a capacitor, why do...Ch. 17 - Prob. 11QCh. 17 - The parallel plates of an isolated capacitor carry...Ch. 17 - Prob. 13QCh. 17 - Prob. 14QCh. 17 - Prob. 15QCh. 17 - Prob. 16QCh. 17 - Prob. 17QCh. 17 - Prob. 18QCh. 17 - Prob. 1MCQCh. 17 - Two identical positive charges are placed near...Ch. 17 - Four identical point charges are arranged at the...Ch. 17 - Prob. 4MCQCh. 17 - Prob. 5MCQCh. 17 - Prob. 6MCQCh. 17 - Prob. 7MCQCh. 17 - Prob. 8MCQCh. 17 - Prob. 9MCQCh. 17 - Prob. 10MCQCh. 17 - Prob. 11MCQCh. 17 - How much work does the electric field do in moving...Ch. 17 - How much work does the electric field do in moving...Ch. 17 - What potential difference is needed to stop an...Ch. 17 - How much kinetic energy will an electron gain (in...Ch. 17 - An electron acquires 6.4510-16 J of kinetic energy...Ch. 17 - How strong is the electric field between two...Ch. 17 - An electric field of 525 V/m is desired between...Ch. 17 - The electric field between two parallel plates...Ch. 17 - What potential difference is needed to give a...Ch. 17 - Two parallel plates, connected to a 45-V power...Ch. 17 - The work done by an external force to move a -6.50...Ch. 17 - What is the speed of an electron with kinetic...Ch. 17 - Prob. 13PCh. 17 - Prob. 14PCh. 17 - An electric field greater than about 3 x 106 V/m...Ch. 17 - 16. (II) An electron starting from rest acquires...Ch. 17 - Prob. 17PCh. 17 - Prob. 18PCh. 17 - Prob. 19PCh. 17 - Prob. 20PCh. 17 - (a) What is the electric potential 2.51015m away...Ch. 17 - Prob. 22PCh. 17 - Prob. 23PCh. 17 - Prob. 24PCh. 17 - Prob. 25PCh. 17 - How much work must be done to bring three...Ch. 17 - Prob. 27PCh. 17 - Prob. 28PCh. 17 - Prob. 29PCh. 17 - Prob. 30PCh. 17 - Prob. 31PCh. 17 - Prob. 32PCh. 17 - Calculate the electric potential due to a dipole...Ch. 17 - The dipole moment, considered as a vector, points...Ch. 17 - Prob. 35PCh. 17 - Prob. 36PCh. 17 - Prob. 37PCh. 17 - Prob. 38PCh. 17 - The charge on a capacitor increases by 15 C when...Ch. 17 - Prob. 40PCh. 17 - If a capacitor has opposite 4.2 µC charges on the...Ch. 17 - Prob. 42PCh. 17 - Prob. 43PCh. 17 - Prob. 44PCh. 17 - Prob. 45PCh. 17 - Prob. 46PCh. 17 - Prob. 47PCh. 17 - What is the capacitance of a pair of circular...Ch. 17 - Prob. 49PCh. 17 - Prob. 50PCh. 17 - Prob. 51PCh. 17 - Prob. 52PCh. 17 - Prob. 53PCh. 17 - Prob. 54PCh. 17 - A homemade capacitor is assembled by placing two...Ch. 17 - Prob. 56PCh. 17 - Prob. 57PCh. 17 - Prob. 58PCh. 17 - Prob. 59PCh. 17 - Prob. 60PCh. 17 - Write the binary number 1010101010101010 as a...Ch. 17 - Prob. 62PCh. 17 - Prob. 63PCh. 17 - Prob. 64PCh. 17 - Prob. 65PCh. 17 - Prob. 66PCh. 17 - Prob. 67PCh. 17 - Prob. 68GPCh. 17 - Prob. 69GPCh. 17 - Prob. 70GPCh. 17 - Prob. 71GPCh. 17 - Prob. 72GPCh. 17 - Prob. 73GPCh. 17 - Dry air will break down if theelectric field...Ch. 17 - Prob. 75GPCh. 17 - Prob. 76GPCh. 17 - Prob. 77GPCh. 17 - Prob. 78GPCh. 17 - Prob. 79GPCh. 17 - Prob. 80GPCh. 17 - Prob. 81GPCh. 17 - Prob. 82GPCh. 17 - Prob. 83GPCh. 17 - Prob. 84GPCh. 17 - Prob. 85GPCh. 17 - Prob. 86GPCh. 17 - Prob. 87GPCh. 17 - Prob. 88GPCh. 17 - Prob. 89GPCh. 17 - Prob. 90GPCh. 17 - Prob. 91GPCh. 17 - Prob. 92GPCh. 17 - Prob. 93GPCh. 17 - In the dynamic random access memory (DRAM)of a...Ch. 17 - Prob. 95GPCh. 17 - Prob. 96GP
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- Protons in an accelerator at the Fermi National Laboratory near Chicago are accelerated to an energy of 400 times their rest energy. (a) What is the speed of these protons? (b) What is their kinetic energy in MeV?arrow_forwardAnswers: a) 3.3 C c/m² 6. Two electrons are fixed 2.00 cm apart. Another electron is shot from infinity and comes to rest midway between the two. What was its initial speed? Answer: 318 m/sarrow_forwardThrough what potential difference does an electron have to be accelerated, starting from rest, to achieve a speed of 0.980c? (a) What is the kinetic energy of the electron at this speed? Express your answer in joules and in electron volts.arrow_forward
- A 10V battery is connected to two parallel metal plates placed in a vacuum. An electron is accelerated from rest to the negative plate toward the positive plate. (A) What kinetic energy does the electron have just as it reaches the positive plate? (B) What is the speed of the electron as it reaches the plate?arrow_forwardSuppose an electron (q = - e = - 1.6 x 10¬19 C,m=9.1 × 10¬3' kg) is accelerated from rest through a potential difference of Vab = +5000 V. Solve for the final speed of the electron. Express numerical answer in two significant figures. The potential energy U is related to the electron charge (-e) and potential Vab is related by the equation: U = Assuming all potential energy U is converted to kinetic energy K, K + U = 0 K = -U mv and using the formula for potential energy above, we arrive at an equation for speed: 2 Since K= v = ( 1/2 Plugging in values, the value of the electron's speed is: x 107 m/s V=arrow_forwardAn electron is accelerated from rest through a potential difference of 181 V. What is the electron's final speed? (e = 1.60×10-¹9 C, Melectron 9.11x10-31 kg) =arrow_forward
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