General Chemistry
General Chemistry
4th Edition
ISBN: 9781891389603
Author: Donald A. McQuarrie, Peter A. Rock, Ethan B. Gallogly
Publisher: University Science Books
Question
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Chapter 17, Problem 17.65P
Interpretation Introduction

Interpretation:

The rate law for the reaction described by following equation at 300k is rateofreaction=(5.0×10-3M-1s-1)[C2H4Br2][I-].  The missing entries in the given table has to be filled.

Concept Introduction:

Rate law:  The mathematical equation that relates the concentrations of the reactants to

the rate of reaction is called the rate law of a reaction.  An example of rate law of thermal decomposition of N2O5 is given by

    rate of reaction = k[N2O5]x

The proportionality constant, k, in a rate law is called the rate constant of the reaction.

Expert Solution & Answer
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Explanation of Solution

Given, rateofreaction=(5.0×10-3M-1s-1)[C2H4Br2][I-].

For run-1:

  [C2H4Br2]=0.20M [I-]=0.20MRate=k[C2H4Br2][I-]=5.0×10-3M-1s-1×0.20M×0.20M=2.0×10-4Ms-1

For run-2:

  [C2H4Br2]=0.20M [I-]=?Rate=4.0×10-4Ms-1Rate=k[C2H4Br2][I-][I-]=Ratek[C2H4Br2]=4.0×10-4Ms-15.0×10-3M-1s-1×0.20M=0.4M

For run-3:

  [C2H4Br2]=? [I-]=0.20MRate=8.0×10-4Ms-1Rate=k[C2H4Br2][I-][C2H4Br2]=Ratek[I-]=8.0×10-4Ms-15.0×10-3M-1s-1×0.20M=0.8M

The given table is filled as follows:

Run[C2H4Br2]0/M[I-]0/MInitialrateofformationofC2H4(g)/Ms-1
10.200.202.0×10-4
20.200.44.0×10-4
30.80.208.0×10-4

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Chapter 17 Solutions

General Chemistry

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