Chapter 16.5, Problem 16.10AFP

Interpretation Introduction

Interpretation : The rate constant at $\text{490 K}$ should be calculated for the given reaction if the $E_{\text{a}}$ is $\text{1}\text{.00 }\times {\text{10}}^{\text{2}}\text{ kJ/mol}$ and rate constant is $\text{0}\text{.286 L/mol}\text{.s}$ at $\text{500K}$ .

Concept Introduction : A catalyst is a substance that increases the rate of reaction without consuming overall during the reaction. It decreases the activation energy of the reaction, so the reaction will complete in less time. The activation energy is the minimum amount of energy that is needed to change the reactant molecule to product molecules. The relation between activation energy, rate constant, and temperature can be written as:

  $k=A{e}^{-E_a/RT}$

Here:

• $k$ = rate constant
• $A$ = Frequency constant
• $R$ = gas constant
• $T$ = Temperature