Glencoe Chemistry: Matter and Change, Student Edition
Glencoe Chemistry: Matter and Change, Student Edition
1st Edition
ISBN: 9780076774609
Author: McGraw-Hill Education
Publisher: MCGRAW-HILL HIGHER EDUCATION
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Chapter 16, Problem 94A
Interpretation Introduction

(a)

Interpretation:

The given chemical equation needs to be balanced.

Sn(s)+NaOH(aq)Na2SnO2+H2

Concept introduction:

In a chemical reaction, the reactants are written on the left side of the equation and the product is written on the right side. The product and the reactants contain an arrow between them showing the proceeding of the reaction from the reactants to the products.

Expert Solution
Check Mark

Answer to Problem 94A

The balanced chemical equation is,

Sn(s)+2NaOH(aq)Na2SnO2+H2

Explanation of Solution

The given skeletal equation is,

Sn(s)+NaOH(aq)Na2SnO2+H2

To balance a chemical equation, the number of each element on the right-hand side and on the left-hand side of the equation must be equal.

In this reaction, in order to balance the number of elements we will add a coefficient 2 with NaOH. The number of H atom, Sn, O and Na will hence be balanced.

Therefore, the balanced chemical equation is,

Sn(s)+2NaOH(aq)Na2SnO2+H2

(b)

Interpretation Introduction

Interpretation:

The given chemical equation needs to be balanced.

C8H18(l)+O2(g)CO2(g)+H2O

Concept introduction:

In a chemical reaction, the reactants are written on the left side of the equation and the product is written on the right side. The product and the reactants contain an arrow between them showing the proceeding of the reaction from the reactants to the products.

(b)

Expert Solution
Check Mark

Answer to Problem 94A

The balanced chemical equation is,

C8H18(l)+O2(g)8CO2(g)+H2O(l)

Explanation of Solution

The given skeletal equation is,

C8H18(l)+O2(g)CO2(g)+H2O(l)

To balance a chemical equation, the number of each element on the right-hand side and on the left-hand side of the equation must be equal.

In this reaction, in order to balance the number of elements we will add a coefficient 2 with C8H18, 25 with O2, 16 with CO2 and 18 with H2O. The number of C, O, H will hence be balanced.

Therefore, the balanced chemical equation is,

2C8H18(l)+25O2(g)16CO2(g)+18H2O(l)

(c)

Interpretation Introduction

Interpretation:

The given chemical equation needs to be balanced.

Al(s)+H2SO4(aq)Al2(SO4)3(aq)+H2(g)

Concept introduction:

In a chemical reaction, the reactants are written on the left side of the equation and the product is written on the right side. The product and the reactants contain an arrow between them showing the proceeding of the reaction from the reactants to the products.

(c)

Expert Solution
Check Mark

Answer to Problem 94A

The balanced chemical equation is,

2Al(s)+3H2SO4(aq)Al2(SO4)3(aq)+3H2(g)

Explanation of Solution

The given skeletal equation is,

Al(s)+H2SO4(aq)Al2(SO4)3(aq)+H2(g)

To balance a chemical equation, the number of each element on the right-hand side and on the left-hand side of the equation must be equal.

In this reaction, in order to balance the number of elements we will add a coefficient 2 with Al, 3 H2SO4 on the right side. The number of Al, H, S and O will hence be balanced.

Therefore, the balanced chemical equation is,

2Al(s)+3H2SO4(aq)Al2(SO4)3(aq)+3H2(g)

Chapter 16 Solutions

Glencoe Chemistry: Matter and Change, Student Edition

Ch. 16.1 - Prob. 11SSCCh. 16.1 - Prob. 12SSCCh. 16.2 - Prob. 13SSCCh. 16.2 - Prob. 14SSCCh. 16.2 - Prob. 15SSCCh. 16.2 - Prob. 16SSCCh. 16.2 - Prob. 17SSCCh. 16.2 - Prob. 18SSCCh. 16.3 - Prob. 19PPCh. 16.3 - Prob. 20PPCh. 16.3 - Prob. 21PPCh. 16.3 - Prob. 22PPCh. 16.3 - Prob. 23SSCCh. 16.3 - Prob. 24SSCCh. 16.3 - Prob. 25SSCCh. 16.3 - Prob. 26SSCCh. 16.3 - Prob. 27SSCCh. 16.3 - Prob. 28SSCCh. 16.3 - Prob. 29SSCCh. 16.3 - Prob. 30SSCCh. 16.4 - Prob. 31PPCh. 16.4 - Prob. 32PPCh. 16.4 - Prob. 33PPCh. 16.4 - Prob. 34SSCCh. 16.4 - Prob. 35SSCCh. 16.4 - Prob. 36SSCCh. 16.4 - Prob. 37SSCCh. 16.4 - Prob. 38SSCCh. 16.4 - Prob. 39SSCCh. 16 - Prob. 40ACh. 16 - Explain what is meant by the average rate of a...Ch. 16 - How would you express the rate of the chemical...Ch. 16 - What is the role of the activated complex in a...Ch. 16 - Suppose two molecules that can react collide....Ch. 16 - Prob. 45ACh. 16 - If AB is exothermic, how does the activation...Ch. 16 - In the gas-phase reaction, I2+Cl22ICl,[I2]...Ch. 16 - Prob. 48ACh. 16 - Prob. 49ACh. 16 - Prob. 50ACh. 16 - In general, what is the relationship between...Ch. 16 - Apply collision theory to explain why increasing...Ch. 16 - Prob. 53ACh. 16 - Prob. 54ACh. 16 - Apply collision theory to explain why powdered...Ch. 16 - Hydrogen peroxide decomposes to water and oxygen...Ch. 16 - Prob. 57ACh. 16 - Prob. 58ACh. 16 - Prob. 59ACh. 16 - Prob. 60ACh. 16 - Prob. 61ACh. 16 - Prob. 62ACh. 16 - Prob. 63ACh. 16 - Prob. 64ACh. 16 - Prob. 65ACh. 16 - Prob. 66ACh. 16 - Prob. 67ACh. 16 - Prob. 68ACh. 16 - Prob. 69ACh. 16 - Prob. 70ACh. 16 - Prob. 71ACh. 16 - Prob. 72ACh. 16 - Prob. 73ACh. 16 - Prob. 74ACh. 16 - Prob. 75ACh. 16 - Prob. 76ACh. 16 - Prob. 77ACh. 16 - Prob. 78ACh. 16 - Prob. 79ACh. 16 - Prob. 80ACh. 16 - Prob. 81ACh. 16 - Prob. 82ACh. 16 - Prob. 83ACh. 16 - Differentiate between the shaded areas in Figure...Ch. 16 - Apply the method of initial rates to determine the...Ch. 16 - Prob. 86ACh. 16 - Prob. 87ACh. 16 - Prob. 88ACh. 16 - Create a table of concentrations, starting with...Ch. 16 - Prob. 90ACh. 16 - Prob. 91ACh. 16 - Prob. 92ACh. 16 - Prob. 93ACh. 16 - Prob. 94ACh. 16 - Prob. 95ACh. 16 - Prob. 96ACh. 16 - Prob. 97ACh. 16 - Prob. 99ACh. 16 - Prob. 100ACh. 16 - Prob. 101ACh. 16 - Prob. 102ACh. 16 - Prob. 1STPCh. 16 - Prob. 2STPCh. 16 - Prob. 3STPCh. 16 - Prob. 4STPCh. 16 - Prob. 5STPCh. 16 - Prob. 6STPCh. 16 - Prob. 7STPCh. 16 - Prob. 8STPCh. 16 - Use the diagram below to answer Questions 8 and 9....Ch. 16 - Prob. 10STPCh. 16 - Prob. 11STPCh. 16 - Prob. 12STPCh. 16 - Prob. 13STPCh. 16 - Prob. 14STPCh. 16 - Prob. 15STPCh. 16 - Prob. 16STPCh. 16 - Prob. 17STPCh. 16 - Prob. 18STPCh. 16 - Prob. 19STP
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