Introductory Chemistry: Concepts and Critical Thinking (8th Edition)
8th Edition
ISBN: 9780134421377
Author: Charles H Corwin
Publisher: PEARSON
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Question
Chapter 16, Problem 8KT
Interpretation Introduction
Interpretation:
The key term corresponding to the definition “a substance that speeds up a reaction by lowering the energy of activation” is to be stated.
Concept introduction:
A catalyst is a substance which increases the speed of the reaction to occur by lowering the energy of activation. It itself is not consumed in the reaction. It has no effect on the heat of reaction.
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Introductory Chemistry: Concepts and Critical Thinking (8th Edition)
Ch. 16 - Prob. 1CECh. 16 - Prob. 2CECh. 16 - Prob. 3CECh. 16 - Prob. 4CECh. 16 - Prob. 5CECh. 16 - Prob. 6CECh. 16 - Prob. 7CECh. 16 - Prob. 8CECh. 16 - Prob. 9CECh. 16 - Prob. 10CE
Ch. 16 - Prob. 1KTCh. 16 - Prob. 2KTCh. 16 - Prob. 3KTCh. 16 - Prob. 4KTCh. 16 - Prob. 5KTCh. 16 - Prob. 6KTCh. 16 - Prob. 7KTCh. 16 - Prob. 8KTCh. 16 - Prob. 9KTCh. 16 - Prob. 10KTCh. 16 - Prob. 11KTCh. 16 - Prob. 12KTCh. 16 - Prob. 13KTCh. 16 - Prob. 14KTCh. 16 - Prob. 15KTCh. 16 - Prob. 16KTCh. 16 - Prob. 17KTCh. 16 - Prob. 18KTCh. 16 - Prob. 1ECh. 16 - Prob. 2ECh. 16 - Prob. 3ECh. 16 - Prob. 4ECh. 16 - Prob. 5ECh. 16 - Prob. 6ECh. 16 - Prob. 7ECh. 16 - Prob. 8ECh. 16 - Prob. 9ECh. 16 - Prob. 10ECh. 16 - Prob. 11ECh. 16 - Prob. 12ECh. 16 - Prob. 13ECh. 16 - Prob. 14ECh. 16 - Prob. 15ECh. 16 - Prob. 16ECh. 16 - Prob. 17ECh. 16 - Prob. 18ECh. 16 - Prob. 19ECh. 16 - Prob. 20ECh. 16 - Prob. 21ECh. 16 - Prob. 22ECh. 16 - Prob. 23ECh. 16 - Prob. 24ECh. 16 - Prob. 25ECh. 16 - Prob. 26ECh. 16 - Prob. 27ECh. 16 - Prob. 28ECh. 16 - Prob. 29ECh. 16 - Prob. 30ECh. 16 - Prob. 31ECh. 16 - Prob. 32ECh. 16 - Prob. 33ECh. 16 - Prob. 34ECh. 16 - Prob. 35ECh. 16 - Prob. 36ECh. 16 - Prob. 37ECh. 16 - Prob. 38ECh. 16 - Prob. 39ECh. 16 - Prob. 40ECh. 16 - Prob. 41ECh. 16 - Prob. 42ECh. 16 - Prob. 43ECh. 16 - Prob. 44ECh. 16 - Prob. 45ECh. 16 - Prob. 46ECh. 16 - Prob. 47ECh. 16 - Prob. 48ECh. 16 - Prob. 1STCh. 16 - Prob. 2STCh. 16 - Prob. 3STCh. 16 - Prob. 4STCh. 16 - Prob. 5STCh. 16 - Prob. 6STCh. 16 - Prob. 7STCh. 16 - Prob. 8STCh. 16 - Prob. 9STCh. 16 - Prob. 10STCh. 16 - Prob. 11STCh. 16 - Prob. 12STCh. 16 - Prob. 13STCh. 16 - Prob. 14STCh. 16 - Prob. 15ST
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- Consider the following equilibrium system. N2(g)+O2(g)2NO(g) a. Write the chemical equation for the forward reaction. b. Write the chemical equation for the reverse reaction.arrow_forwardWhat happens to the reactants in an ineffective molecular collision?arrow_forwardSketch an energy diagram graph representing an exothermic reaction, and label the following. a. Average energy of reactants b. Average energy of products c. Activation energy d. Amount of energy liberated during the reactionarrow_forward
- . When the volume of a vessel containing a gaseous equilibrium system is decreased, the _________ of the gaseous substances present is initially increased.arrow_forwardClassify each of the following statements as true or false. aSome equilibria depend on a steady supply of a reactant in order to maintain the equilibrium. bBoth forward and reverse reactions continue after equilibrium is reached. cEvery time reactant molecules collide, there is a reaction. dPotential energy during a collision is greater than potential energy before or after the collision. eThe properties of a transition state are between those of the reactants and products. fActivation energy is positive for both the forward and reverse reactions. gKinetic energy is changed to potential energy during a collision. hAn increase in temperature speeds the forward reaction but slows the reverse reaction. iA catalyst changes the steps by which a reaction is completed. jAn increase in concentration of a substance on the right-hand side of an equation speeds the reverse reaction rate. kAn increase in the concentration of a substance in an equilibrium increases the reaction rate in which the substance is a product. lReducing the volume of a gaseous equilibrium shifts the equilibrium in the direction of fewer gaseous molecules. mRaising temperature results in a shift in the forward direction of an endothermic equilibrium. nThe value of an equilibrium constant depends on temperature. oA large K indicates that an equilibrium is favored in the reverse direction.arrow_forwardConsider the following equilibrium system. N2(g)+3H2(g)2NH3(g) a. Write the chemical equation for the forward reaction. b. Write the chemical equation for the reverse reaction.arrow_forward
- The equilibrium constant expression for a given reaction depends on how the equilibrium equation is written. Explain the meaning of that statement. You may, if you wish, use the equilibrium equation N2(g)+3H2(g)2NH3(g) to illustrate your explanation.arrow_forwardDraw an energy diagram graph for an endothermic reaction where no catalyst is present. Then draw an energy diagram graph for the same reaction when a catalyst is present. Indicate the similarities and differences between the two diagrams.arrow_forward. Consider the exothermic reaction CO(g)+2H2(g)CH3OH(l)Predict three changes that could be made to the system that would decrease the yield of product over that produced by a system in which no change was made.arrow_forward
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