Consider a double-paned window consisting of two panes of glass, each with a thickness of 0.500 cm and an area of 0.725 m 2 , separated by a layer of air with a thickness of 1.75 cm. The temperature on one side of the window is 0.00 °C; the temperature on the other side is 20.0°C. In addition, note that the thermal conductivity of glass is roughly 36 times greater than that of air. (a) Approximate the heat transfer through this window by ignoring the glass. That is, calculate the heat flow per second through 1.75 cm of air with a temperature difference of 20.0 C°. (The exact result for the complete window is 19.1 J/s.) (b) Use the approximate heat flow found in part (a) to find an approximate temperature difference across each pane of glass. (The exact result is 0 .157C°.)
Consider a double-paned window consisting of two panes of glass, each with a thickness of 0.500 cm and an area of 0.725 m 2 , separated by a layer of air with a thickness of 1.75 cm. The temperature on one side of the window is 0.00 °C; the temperature on the other side is 20.0°C. In addition, note that the thermal conductivity of glass is roughly 36 times greater than that of air. (a) Approximate the heat transfer through this window by ignoring the glass. That is, calculate the heat flow per second through 1.75 cm of air with a temperature difference of 20.0 C°. (The exact result for the complete window is 19.1 J/s.) (b) Use the approximate heat flow found in part (a) to find an approximate temperature difference across each pane of glass. (The exact result is 0 .157C°.)
Consider a double-paned window consisting of two panes of glass, each with a thickness of 0.500 cm and an area of 0.725 m2, separated by a layer of air with a thickness of 1.75 cm. The temperature on one side of the window is 0.00 °C; the temperature on the other side is 20.0°C. In addition, note that the thermal conductivity of glass is roughly 36 times greater than that of air. (a) Approximate the heat transfer through this window by ignoring the glass. That is, calculate the heat flow per second through 1.75 cm of air with a temperature difference of 20.0 C°. (The exact result for the complete window is 19.1 J/s.) (b) Use the approximate heat flow found in part (a) to find an approximate temperature difference across each pane of glass. (The exact result is 0 .157C°.)
A glass windowpane in a home is 0.0058 m thick and has dimensions of 1.1 m x 2.3 m. On a certain day,
the indoor temperature is 22°C and the outdoor temperature is 0°C (Thermal conductivity for glass is 0.840
J/s-m-°C.)
(a) 7020 J/s
(b) 3510 J/s
(c) 4180 J/s
(d) 8061 J/s
Consider a double-paned window consisting of two panes ofglass, each with a thickness of 0.500 cm and an area of 0.725 m2,separated by a layer of air with a thickness of 1.75 cm. The temperature on one side of the window is 0.00 °C; the temperature on theother side is 20.0 °C. In addition, note that the thermal conductivity of glass is roughly 36 times greater than that of air. (a) Approximate the heat transfer through this window by ignoring the glass.That is, calculate the heat flow per second through 1.75 cm of airwith a temperature difference of 20.0 C°. (The exact result for thecomplete window is 19.1 J>s.) (b) Use the approximate heat flowfound in part (a) to find an approximate temperature differenceacross each pane of glass. (The exact result is 0.157 C°.)
A 50 cm thick block of copper is placed against a 30 cm block of iron. Let
the dimensions of the faces of each block be 1 m by 2 m. Also, the conductivity of copper
is 200 and the conductivity of iron is 300 . If the left face of the copper block is
100°C and the right face of the iron block is at 10°C, calculate:
(a) the temperature between the blocks (the interface).
(b) the heat transfer rate through the system of blocks.
Essential University Physics: Volume 2 (3rd Edition)
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.