Basic Chemistry
Basic Chemistry
6th Edition
ISBN: 9780134878119
Author: Timberlake, Karen C. , William
Publisher: Pearson,
bartleby

Concept explainers

bartleby

Videos

Question
Book Icon
Chapter 16, Problem 34CI

(a)

Interpretation Introduction

Interpretation: A strip of magnesium metal dissolves rapidly in 6.00 mL of a 0.150 M HCl solution, producing hydrogen gas and magnesium chloride.

  Mg(s) + HCl(aq)H2(g) + MgCl2(aq)

Assign oxidation numbers to all of the elements in the reactants and products.

Concept Introduction:Here are the rules for assigning oxidation number to elements:

  • For an element in its free state it is assigned an oxidation number of zero.
  • Monatomic ions have oxidation number that is equal to charge of the monatomic ion.
  • Alkali metals have +1 oxidation number, alkaline earth metals have +2 oxidation number and halogens are assigned -1 oxidation number.
  • In most compounds H is assigned a +1 oxidation number and O is assigned a -2 oxidation number.
  • For a neutral compound the summation of oxidation numbers of all elements in the compound is zero.

If the oxidation number of an element increases then it undergoes oxidation and if the oxidation number of the element decreases then it undergoes reduction.

(b)

Interpretation Introduction

Interpretation: Mg(s) + HCl(aq)H2(g) + MgCl2(aq)

To write the balanced chemical equation for the reaction.

Concept Introduction:In a balanced chemical equation for a reaction the number of atoms of each element is equal on both side of the reaction.

(c)

Interpretation Introduction

Interpretation: Mg(s) + HCl(aq)H2(g) + MgCl2(aq)

To find the oxidizing agent.

Concept Introduction:An oxidizing agent itself gets reduced as it oxidizes other substances. An oxidizing agent accepts electrons.

(d)

Interpretation Introduction

Interpretation: Mg(s) + HCl(aq)H2(g) + MgCl2(aq)

To find the reducing agent.

Concept Introduction:A reducing agent itself gets oxidized as it reduces other substances. A reducing agent losses electrons.

(e)

Interpretation Introduction

Interpretation: To find the pH of the 0.150 M HCl solution.

Concept Introduction: pH = - log[H+]

(f)

Interpretation Introduction

Interpretation: To find the grams of magnesium that can dissolve in the HCl solution.

Concept Introduction: Molarity = moles of soluteLiter of solution

  Moles = massmolar mass  

Blurred answer
Students have asked these similar questions
8) What is the pH of a solution containing 0.280 M weak base, B', with a K, of 3.9 X 107? (10.51) в (ад) + H-0 (1) ВН (аq) + ОН (ад)
A slightly soluble salt has the formula A B1 and a Ksp of 6.1E-25. What is pB in a solution of this salt?   Answer:     (12.11)
10.109 A 0.204 M NaOH solution is used to titrate 50.0 mL of an H,PO, solution. (10.7) a. Write the balanced chemical equation. b. What is the molarity of the H;PO4 solution if 16.4 mL of the NaOH solution is required?

Chapter 16 Solutions

Basic Chemistry

Ch. 16.1 - Prob. 11PPCh. 16.1 - Prob. 12PPCh. 16.2 - Prob. 13PPCh. 16.2 - Prob. 14PPCh. 16.2 - Prob. 15PPCh. 16.2 - Prob. 16PPCh. 16.2 - Prob. 17PPCh. 16.2 - Prob. 18PPCh. 16.2 - Prob. 19PPCh. 16.2 - Prob. 20PPCh. 16.2 - Prob. 21PPCh. 16.2 - Prob. 22PPCh. 16.3 - Prob. 23PPCh. 16.3 - Prob. 24PPCh. 16.3 - Prob. 25PPCh. 16.3 - Prob. 26PPCh. 16.3 - Prob. 27PPCh. 16.3 - Prob. 28PPCh. 16.4 - Prob. 29PPCh. 16.4 - Prob. 30PPCh. 16.4 - Prob. 31PPCh. 16.4 - Prob. 32PPCh. 16.4 - Prob. 33PPCh. 16.4 - Prob. 34PPCh. 16.5 - Prob. 35PPCh. 16.5 - Prob. 36PPCh. 16.5 - Prob. 37PPCh. 16.5 - Prob. 38PPCh. 16.5 - Prob. 39PPCh. 16.5 - Prob. 40PPCh. 16.6 - Prob. 41PPCh. 16.6 - Prob. 42PPCh. 16.6 - Prob. 43PPCh. 16.6 - Prob. 44PPCh. 16.6 - Prob. 45PPCh. 16.6 - Prob. 46PPCh. 16.6 - Prob. 47PPCh. 16.6 - Prob. 48PPCh. 16.6 - Prob. 49PPCh. 16.6 - Prob. 50PPCh. 16 - Prob. 51UTCCh. 16 - Prob. 52UTCCh. 16 - The chapter sections to review are shown in...Ch. 16 - Prob. 54UTCCh. 16 - Prob. 55UTCCh. 16 - Prob. 56UTCCh. 16 - Prob. 57APPCh. 16 - Prob. 58APPCh. 16 - Prob. 59APPCh. 16 - Prob. 60APPCh. 16 - Prob. 61APPCh. 16 - Prob. 62APPCh. 16 - Prob. 63APPCh. 16 - Prob. 64APPCh. 16 - Prob. 65APPCh. 16 - Prob. 66APPCh. 16 - Prob. 67APPCh. 16 - Prob. 68APPCh. 16 - Prob. 69APPCh. 16 - Prob. 70APPCh. 16 - Prob. 71APPCh. 16 - Prob. 72APPCh. 16 - Prob. 73APPCh. 16 - Prob. 74APPCh. 16 - Prob. 75APPCh. 16 - Prob. 76APPCh. 16 - Prob. 77APPCh. 16 - Prob. 78APPCh. 16 - Prob. 79CPCh. 16 - Prob. 80CPCh. 16 - Prob. 81CPCh. 16 - Prob. 82CPCh. 16 - Prob. 83CPCh. 16 - Prob. 84CPCh. 16 - Prob. 85CPCh. 16 - Prob. 86CPCh. 16 - Prob. 87CPCh. 16 - Prob. 88CPCh. 16 - Prob. 89CPCh. 16 - Prob. 90CPCh. 16 - Consider the reaction of sodium oxalate (Na2C2O4)...Ch. 16 - Prob. 34CICh. 16 - Prob. 35CICh. 16 - Prob. 36CICh. 16 - Prob. 37CICh. 16 - Prob. 38CICh. 16 - Prob. 39CICh. 16 - Prob. 40CI
Knowledge Booster
Background pattern image
Chemistry
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Similar questions
SEE MORE QUESTIONS
Recommended textbooks for you
Text book image
Chemistry
Chemistry
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Cengage Learning
Text book image
Chemistry
Chemistry
ISBN:9781259911156
Author:Raymond Chang Dr., Jason Overby Professor
Publisher:McGraw-Hill Education
Text book image
Principles of Instrumental Analysis
Chemistry
ISBN:9781305577213
Author:Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:Cengage Learning
Text book image
Organic Chemistry
Chemistry
ISBN:9780078021558
Author:Janice Gorzynski Smith Dr.
Publisher:McGraw-Hill Education
Text book image
Chemistry: Principles and Reactions
Chemistry
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:Cengage Learning
Text book image
Elementary Principles of Chemical Processes, Bind...
Chemistry
ISBN:9781118431221
Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. Bullard
Publisher:WILEY
Bonding (Ionic, Covalent & Metallic) - GCSE Chemistry; Author: Science Shorts;https://www.youtube.com/watch?v=p9MA6Od-zBA;License: Standard YouTube License, CC-BY
Stoichiometry - Chemistry for Massive Creatures: Crash Course Chemistry #6; Author: Crash Course;https://www.youtube.com/watch?v=UL1jmJaUkaQ;License: Standard YouTube License, CC-BY