EBK OM
6th Edition
ISBN: 9781305888210
Author: Collier
Publisher: YUZU
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Chapter 16, Problem 2PA
Summary Introduction
Interpretation: The number of responses at each level (1 through 10) is to be counted, and the number and percentage of customers at the promoter, passive, and detractor levels are to be determined and the net promoter score (NPS) is to be calculated.
Concept Introduction: NPS (Net Promoter Score) is one of the measurement tools to growth of the company. It is calculated by the percentage of the promoters and detractors.
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As part of case-study research based in a textile company with over 800 customers, you have been given access to an internal market research report. This was undertaken by the company’s marketing department. The report presents the results of a recent customer survey as percentages. The section in the report that describes how the data were collected and analyzed is reproduced below:
“Data were collected from a sample of current customers selected from our customer database. The data were collected using an Internet-mediated questionnaire designed and administered via the google forms. Thirty-nine customers responded, resulting in an 18.7 per cent response rate. These data were analyzed using the SPSS computer software. Additional qualitative data based on in-depth interviews with customers were also included. Do you consider these data are likely to be reliable? Give reasons for your answer.
Which best describes the null hypothesis associated with an Analysis of Variance (ANOVA)?
Group of answer choices
a. Ho: Variance 1 = Variance 2 = Variance 3
b. Ho: Standard Deviation 1 = Standard Deviation 2 = Standard Deviation 3
c. Ho: Proportion 1 = Proportion 2 = Proportion 3
d. Ho: Median 1 = Median 2 = Median 3
e. Ho: Mean 1 = Mean 2 = Mean 3
Global Bikes Inc. (a bicylce manufacturing firm) collected the following data during a study of consumer buying patterns.
Observation
1
2
3
4
5
6
7
y=
X
y
15
70
28
79
38
89
35
86
49 97
42
97
30 82
y =
Observation
0.721 +
1890123
a. Create a linear regression line (equation) for the data.(Round your Intermediate calculations and final answers to 3 decimal
places.)
X
14
16
14
24
21
29
63.229 X
y
82
70
68
84
83
91
b. Use the equation determined in part b to predict the expected value of y for x = 49. (Round your Intermediate calculations and
final answers to 3 decimal places.)
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