Chapter 16, Problem 24E

Interpretation Introduction

Interpretation:

The $\text{pH}$ of the given solutions, with and without adding $0.010\text{mol}$ $\text{NaOH}$ is to be calculated.

Concept introduction: The pH of the base solution is the $\log$ of the concentration of the hydroxide ions released by the solution upon dissociation.

Henderson-Hasselbalch equation provides an expression by which the pH of a buffer solution by initial concentrations of the components of the buffer solution can be calculated.

To determine: The pH of the solutions, $250\text{ml}$ of pure water, $250\text{ml}$ of a buffer solution with $0.195\text{M}$ in ${\text{HCHO}}_{\text{2}}$ and $0.275\text{M}$ in ${\text{KCHO}}_{\text{2}}$ , $250\text{ml}$ of a buffer solution with $0.255\text{M}$ in ${\text{CH}}_3{\text{CH}}_2{\text{NH}}_{\text{2}}$ and $0.235\text{M}$ in ${\text{CH}}_3{\text{CH}}_2{\text{NH}}_3\text{Cl}$ , with and without adding $0.010\text{mol}$$\text{NaOH}$ .