Concept explainers
a.
To determine: The possible method to handle the scenario in which an individual should contact the proband beforehand to explain the results and the implications of the results.
Introduction: A couple has undergone a prenatal test in which the young woman (proband) is found to have the sickle cell trait (Ss), and her partner does not have the sickle cell anemia (SS). The woman’s family has a family history of sickle cell anemia. Their prenatal tests indicate that the fetus is affected with sickle cell anemia (ss) and the only way it is possible is when the woman’s partner is not the father of the fetus.
b.
To determine: Whether it is appropriate to keep the information from the partner as he believes he is the father of the baby and the other problems related to this case.
Introduction: A couple has undergone a prenatal test in which the young woman (proband) is found to have the sickle cell trait (Ss), and her partner does not have the sickle cell anemia (SS). The woman’s family has a family history of sickle cell anemia. Their prenatal tests indicate that the fetus is affected with sickle cell anemia (ss) and the only way it is possible is when the woman’s partner is not the father of the fetus.
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Chapter 16 Solutions
Human Heredity: Principles and Issues (MindTap Course List)
- Another couple is concerned their child will be born with sickle cell anemia. The woman does not have sickle cell anemia. The woman’s mother had sickle cell anemia and her father was a carrier of the sickle cell gene. The man knows that he is not a carrier of the sickle cell gene. What is the probability that the child will be a carrier of sickle cell anemia?arrow_forwardAs a genetic counselor, you inform Susan and John that a blood test for cystic fibrosis is available. would you recommend generic testing for Susan and John?arrow_forwardThe gene for polydactyly (P) is autosomal and dominant to normal fingers (p). Hemophilia is sex-linked and recessive (X h ). A man and his wife both of whom are polydactylous and have normal red blood cells have a child who is non-polydactylous and with hemophilia. What are their genotypes?arrow_forward
- Another couple is concerned their child will be born with sickle cell anemia. The woman does not have sickle cell anemia. The woman’s mother had sickle cell anemia and her father was a carrier of the sickle cell gene. The man knows that he is not a carrier of the sickle cell gene. What is the probability that the child will be a carrier of sickle cell anemia? please include a punnett squarearrow_forwardThe mother of a family with 10 children has blood typeRh+. She also has a very rare condition (elliptocytosis,phenotype E) that causes red blood cells to be oval rather than round in shape but that produces no adverseclinical effects. The father is Rh− (lacks the Rh+ antigen)and has normal red blood cells (phenotype e). The children are 1 Rh+ e, 4 Rh+ E, and 5 Rh− e. Information isavailable on the mother’s parents, who are Rh+ E andRh− e. One of the 10 children (who is Rh+ E) marriessomeone who is Rh+ e, and they have an Rh+ E child.a. Draw the pedigree of this whole family.b. Is the pedigree in agreement with the hypothesisthat the Rh+ allele is dominant and Rh− is recessive?c. What is the mechanism of transmission ofelliptocytosis?d. Could the genes governing the E and Rh phenotypesbe on the same chromosome? If so, estimate the mapdistance between them, and comment on your resultarrow_forwardO. 2 Hemophilia A is an X-linked trait where blood clotting is affected due to a mutation in a clotting factor protein. Georgio has hemophilia and attends a support group where he meets Gbenga, who does not have the disease, but whose father has hemophilia. Her mother is not affected. A) If they marry, what percentage % of all their children will have hemophilia? % B) Georgio meets another woman, Maria, at the hemophilia support group. Maria also lacks the trait, but her mother has hemophilia while her father is unaffected. # 3 Would a Georgio-Maria mating provide a larger chance of having afflicted children compared to a Georgio-Gbenga mating? C) Show how you came up with your answer to B. Edit View Insert Format Tools Table 12pt ✓ 80 F3 V Paragraph ✓ $ 4 Yes or No 000 000 F4 DO LO % 5 BIUAV T² | F5 ^ MacBook Air 6 2 F6 V & 7 F7 * 8 DII F8 ( 9 DD F9 1 0 S Farrow_forward
- In man, muscular dystrophy is a condition in which the muscles waste away during early life and may result in a shorter life expectancy. It is due to a sex-linked, recessive gene. A certain couple has five children – three boys (ages 1yr, 3yrs, and 10yrs old) and two girls (ages 5yrs and 7yrs old). The oldest boy shows the symptoms of this disease. You are their family physician and they come to you for advice. What would you tell them about the chances of their other children developing the disease?arrow_forwardPlease help me with the following question: Von Willebrand disease is an inherited bleeding disorder. People with von Willebrand disease take a much longer period for blood to clot/stop than others. von Willebrand disease is either inherited in an autosomal dominant pattern or in an autosomal recessive pattern. Question: what is the genotype of the disorder? what are the phenotypic effects of the disorder? What is happening with the DNA to cause the phenotypic effects?arrow_forwardThere are six types of agglutinogen named C,D, E and c,d,e.the first three are dominant and last three are recessive.discussarrow_forward
- A young lady requested pre-marital genetic counselling because her sister had died in infancy of gangliosidosis, an autosomal recessive disease. What is the risk that this young lady has similarly affected offspring? What advice should be given?arrow_forwardA genetic counsellor is working with a couple who have just had a child who has a debilitating autosomal recessive form of a disease termed epidemolysis bullosa (which causes severe external and internal skin fragility resulting in blistering etc). Neither parent has epidemolysis bullosa, nor does anyone in their families. What should the counsellor say to this couple? OA. "Because no one in either of your families has epidemolysis bullosa, you are not likely to have another baby with epidemolysis bullosa. You can safely have another child." OB. "Because you have had one child with epidemolysis bullosa, you must each carry the allele. Any child you have has a 50% chance of having the disease." OC. "Because you have had one child with epidemolysis bullosa, you must each carry the allele. Any child you have has a 25% chance of having the disease." OD. "Because you have had one child with epidemolysis bullosa, you must both carry the allele. However, since the chance of having an affected…arrow_forwardAs a genetic counselor, you inform Susan and John that a blood test for cystic fibrosis is available. Would you recommend genetic testing for Susan and John? Explain.arrow_forward
- Human Heredity: Principles and Issues (MindTap Co...BiologyISBN:9781305251052Author:Michael CummingsPublisher:Cengage Learning