Chemistry for Today: General, Organic, and Biochemistry
Chemistry for Today: General, Organic, and Biochemistry
9th Edition
ISBN: 9781305960060
Author: Spencer L. Seager, Michael R. Slabaugh, Maren S. Hansen
Publisher: Cengage Learning
Question
Book Icon
Chapter 16, Problem 16.18E
Interpretation Introduction

Interpretation:

The reason as to why the boiling points of tertiary amines are lower than those of corresponding primary and secondary amines is to be stated.

Concept introduction:

Amines are a class of organic compounds which are derived from ammonia. They are formed by replacing one or more hydrogen in ammonia by organic molecules. Amines usually show hydrogen bonding. Hydrogen bonding forms between a hydrogen atom covalently bonded to a highly electronegative element and another electronegative atom. It is usually shown by the hydrogen covalently bonded to oxygen, nitrogen or fluorine.

Blurred answer
Students have asked these similar questions
N-Methylpyrrolidine has a boiling point of 81 °C, and piperidine has a boiling point of 106 °C. Tetrahydropyran has a boiling point of 88 °C, and cyclopentanone has a boiling point of 141 °C. These two isomershave a boiling point difference of 53 °C. Explain why the two oxygen-containing isomers have a much larger boilingpoint difference than the two amine isomers
Complete this table for different amine compounds. Chemical propylamine quaternary ammonium ion methylphenylamine Molecular formula C3H9N C₂H7N C5H13N C4H10N Structural formula (CH3)3N (CH3)2NH CH 3 I (CH₂) 11 | H3C(CH2) 11 -N-(CH₂)11CH3 NHCH3 (CH₂)11 CH3 CH3CH2CH2-NH-CH3 + Classification Tertiary Quaternary Tertiary Secondary
What time of intermolecular interactions occur when the tertiary amine of Tapentadol binds to its drug target?

Chapter 16 Solutions

Chemistry for Today: General, Organic, and Biochemistry

Ch. 16 - Prob. 16.11ECh. 16 - Prob. 16.12ECh. 16 - Prob. 16.13ECh. 16 - Prob. 16.14ECh. 16 - Prob. 16.15ECh. 16 - Prob. 16.16ECh. 16 - Prob. 16.17ECh. 16 - Prob. 16.18ECh. 16 - Prob. 16.19ECh. 16 - Draw diagrams similar to Figure 16.1 to illustrate...Ch. 16 - Prob. 16.21ECh. 16 - Prob. 16.22ECh. 16 - Prob. 16.23ECh. 16 - Prob. 16.24ECh. 16 - Prob. 16.25ECh. 16 - Prob. 16.26ECh. 16 - Prob. 16.27ECh. 16 - Prob. 16.28ECh. 16 - Prob. 16.29ECh. 16 - Prob. 16.30ECh. 16 - Prob. 16.31ECh. 16 - Prob. 16.32ECh. 16 - Prob. 16.33ECh. 16 - Describe the general structure of a neuron.Ch. 16 - Name the two amino acids that are starting...Ch. 16 - Prob. 16.36ECh. 16 - Prob. 16.37ECh. 16 - Prob. 16.38ECh. 16 - Prob. 16.39ECh. 16 - Prob. 16.40ECh. 16 - Prob. 16.41ECh. 16 - Prob. 16.42ECh. 16 - Why are alkaloids weakly basic?Ch. 16 - Prob. 16.44ECh. 16 - Prob. 16.45ECh. 16 - Prob. 16.46ECh. 16 - Prob. 16.47ECh. 16 - Prob. 16.48ECh. 16 - Prob. 16.49ECh. 16 - Prob. 16.50ECh. 16 - Prob. 16.51ECh. 16 - Complete the following reactions: a. b.Ch. 16 - Complete the following reactions: a. b.Ch. 16 - Prob. 16.54ECh. 16 - What are the products of the acid hydrolysis of...Ch. 16 - Prob. 16.56ECh. 16 - Prob. 16.57ECh. 16 - Prob. 16.58ECh. 16 - Prob. 16.59ECh. 16 - Prob. 16.60ECh. 16 - Prob. 16.61ECh. 16 - Prob. 16.62ECh. 16 - Prob. 16.63ECh. 16 - Prob. 16.64ECh. 16 - Prob. 16.65ECh. 16 - Prob. 16.66ECh. 16 - Prob. 16.67ECh. 16 - Prob. 16.68ECh. 16 - Prob. 16.69ECh. 16 - Prob. 16.70ECh. 16 - Prob. 16.71ECh. 16 - The stimulant in coffee is: a. tannic acid b....Ch. 16 - What are the most likely products of a reaction...
Knowledge Booster
Background pattern image
Recommended textbooks for you
Text book image
Chemistry for Today: General, Organic, and Bioche...
Chemistry
ISBN:9781305960060
Author:Spencer L. Seager, Michael R. Slabaugh, Maren S. Hansen
Publisher:Cengage Learning
Text book image
Organic Chemistry
Chemistry
ISBN:9781305580350
Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote
Publisher:Cengage Learning
Text book image
Macroscale and Microscale Organic Experiments
Chemistry
ISBN:9781305577190
Author:Kenneth L. Williamson, Katherine M. Masters
Publisher:Brooks Cole