Concept explainers
a.
The expression for the frequency of the oscillation.
a.
Answer to Problem D15.38P
The oscillation frequency is
Explanation of Solution
Given:
The circuit for the Hartley oscillator is given as:
Forward biased junction diffusion resistance is
Drawing the small signal equivalent of the Harley oscillato:
The output resistance
Applying the nodal analysis at the output node (
And the result by the voltage divider:
Solving equation (2) and equation (1):
Substituting s=
The condition for the oscillation indicates that the real and the imaginary components of the equation 4.
should be zero.
From the imaginary component, the oscillation frequency:
Hence, the oscillation frequency is
b.
To show: The condition for the oscillation is
b.
Explanation of Solution
Given:
The circuit for the Hartley oscillator is given as:
The real component of the equation 4 should be zero:
Therefore,
c.
To design: The circuit for oscillation at the given frequency.
c.
Explanation of Solution
Given:
The circuit for the Hartley oscillator is given as:
Frequency of oscillation is
Inductors is
The condition for oscillation:
Substituting
Hence,
The frequency of oscillation:
Hence,
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Chapter 15 Solutions
MICROELECT. CIRCUIT ANALYSIS&DESIGN (LL)
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