(a) Interpretation: The normality of the given solution is to be calculated. 0.250 M HCl . Concept Introduction: The atomic mass of an element is defined as the sum of number of protons and number of neutrons. Molar mass of an element is determined from atomic mass of an element. The number of moles is calculated by the formula, Moles = Mass g Molar mass The molarity is calculated by the formula, Molarity = Number of moles of solute Volume of solution L The normality of the solution is calculated by the formula, Normality = Molarity × Number of H + or OH − ions .

Question

Which molecule is the most stable? Please explain.

Answer 1

Question

Chapter 15, Problem 81QAP

Interpretation Introduction

(a)

Interpretation:

The normality of the given solution is to be calculated.

$0.250 M$

$HCl$ .

Concept Introduction:

The atomic mass of an element is defined as the sum of number of protons and number of neutrons. Molar mass of an element is determined from atomic mass of an element.

The number of moles is calculated by the formula,

$Moles=MassgMolar mass$

The molarity is calculated by the formula,

$Molarity=Number of moles of soluteVolume of solution L$

The normality of the solution is calculated by the formula,

$Normality=Molarity×Number of H+ or OH− ions$ .

Interpretation Introduction

(b)

Interpretation:

The normality of the given solution is to be calculated.

$0.105 M$

$H2SO4$ .

Concept Introduction:

The atomic mass of an element is defined as the sum of number of protons and number of neutrons. Molar mass of an element is determined from atomic mass of an element.

The number of moles is calculated by the formula,

$Moles=MassgMolar mass$

The molarity is calculated by the formula,

$Molarity=Number of moles of soluteVolume of solution L$

The normality of the solution is calculated by the formula,

$Normality=Molarity×Number of H+ or OH− ions$ .

Interpretation Introduction

(c)

Interpretation:

The normality of the given solution is to be calculated.

$5.3×10−2 M$

$H3PO4$ .

Concept Introduction:

The atomic mass of an element is defined as the sum of number of protons and number of neutrons. Molar mass of an element is determined from atomic mass of an element.

The number of moles is calculated by the formula,

$Moles=MassgMolar mass$

The molarity is calculated by the formula,

$Molarity=Number of moles of soluteVolume of solution L$

The normality of the solution is calculated by the formula,

$Normality=Molarity×Number of H+ or OH− ions$ .

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Answer 2

Question

Chapter 15, Problem 81QAP

Interpretation Introduction

(a)

Interpretation:

The normality of the given solution is to be calculated.

$0.250 M$

$HCl$ .

Concept Introduction:

The atomic mass of an element is defined as the sum of number of protons and number of neutrons. Molar mass of an element is determined from atomic mass of an element.

The number of moles is calculated by the formula,

$Moles=MassgMolar mass$

The molarity is calculated by the formula,

$Molarity=Number of moles of soluteVolume of solution L$

The normality of the solution is calculated by the formula,

$Normality=Molarity×Number of H+ or OH− ions$ .

Interpretation Introduction

(b)

Interpretation:

The normality of the given solution is to be calculated.

$0.105 M$

$H2SO4$ .

Concept Introduction:

The atomic mass of an element is defined as the sum of number of protons and number of neutrons. Molar mass of an element is determined from atomic mass of an element.

The number of moles is calculated by the formula,

$Moles=MassgMolar mass$

The molarity is calculated by the formula,

$Molarity=Number of moles of soluteVolume of solution L$

The normality of the solution is calculated by the formula,

$Normality=Molarity×Number of H+ or OH− ions$ .

Interpretation Introduction

(c)

Interpretation:

The normality of the given solution is to be calculated.

$5.3×10−2 M$

$H3PO4$ .

Concept Introduction:

The atomic mass of an element is defined as the sum of number of protons and number of neutrons. Molar mass of an element is determined from atomic mass of an element.

The number of moles is calculated by the formula,

$Moles=MassgMolar mass$

The molarity is calculated by the formula,

$Molarity=Number of moles of soluteVolume of solution L$

The normality of the solution is calculated by the formula,

$Normality=Molarity×Number of H+ or OH− ions$ .

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Answer 3

Question

Chapter 15, Problem 81QAP

Interpretation Introduction

(a)

Interpretation:

The normality of the given solution is to be calculated.

$0.250 M$

$HCl$ .

Concept Introduction:

The atomic mass of an element is defined as the sum of number of protons and number of neutrons. Molar mass of an element is determined from atomic mass of an element.

The number of moles is calculated by the formula,

$Moles=MassgMolar mass$

The molarity is calculated by the formula,

$Molarity=Number of moles of soluteVolume of solution L$

The normality of the solution is calculated by the formula,

$Normality=Molarity×Number of H+ or OH− ions$ .

Interpretation Introduction

(b)

Interpretation:

The normality of the given solution is to be calculated.

$0.105 M$

$H2SO4$ .

Concept Introduction:

The atomic mass of an element is defined as the sum of number of protons and number of neutrons. Molar mass of an element is determined from atomic mass of an element.

The number of moles is calculated by the formula,

$Moles=MassgMolar mass$

The molarity is calculated by the formula,

$Molarity=Number of moles of soluteVolume of solution L$

The normality of the solution is calculated by the formula,

$Normality=Molarity×Number of H+ or OH− ions$ .

Interpretation Introduction

(c)

Interpretation:

The normality of the given solution is to be calculated.

$5.3×10−2 M$

$H3PO4$ .

Concept Introduction:

The atomic mass of an element is defined as the sum of number of protons and number of neutrons. Molar mass of an element is determined from atomic mass of an element.

The number of moles is calculated by the formula,

$Moles=MassgMolar mass$

The molarity is calculated by the formula,

$Molarity=Number of moles of soluteVolume of solution L$

The normality of the solution is calculated by the formula,

$Normality=Molarity×Number of H+ or OH− ions$ .

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Answer 4

Question

Chapter 15, Problem 81QAP

Interpretation Introduction

(a)

Interpretation:

The normality of the given solution is to be calculated.

$0.250 M$

$HCl$ .

Concept Introduction:

The atomic mass of an element is defined as the sum of number of protons and number of neutrons. Molar mass of an element is determined from atomic mass of an element.

The number of moles is calculated by the formula,

$Moles=MassgMolar mass$

The molarity is calculated by the formula,

$Molarity=Number of moles of soluteVolume of solution L$

The normality of the solution is calculated by the formula,

$Normality=Molarity×Number of H+ or OH− ions$ .

Interpretation Introduction

(b)

Interpretation:

The normality of the given solution is to be calculated.

$0.105 M$

$H2SO4$ .

Concept Introduction:

The atomic mass of an element is defined as the sum of number of protons and number of neutrons. Molar mass of an element is determined from atomic mass of an element.

The number of moles is calculated by the formula,

$Moles=MassgMolar mass$

The molarity is calculated by the formula,

$Molarity=Number of moles of soluteVolume of solution L$

The normality of the solution is calculated by the formula,

$Normality=Molarity×Number of H+ or OH− ions$ .

Interpretation Introduction

(c)

Interpretation:

The normality of the given solution is to be calculated.

$5.3×10−2 M$

$H3PO4$ .

Concept Introduction:

The atomic mass of an element is defined as the sum of number of protons and number of neutrons. Molar mass of an element is determined from atomic mass of an element.

The number of moles is calculated by the formula,

$Moles=MassgMolar mass$

The molarity is calculated by the formula,

$Molarity=Number of moles of soluteVolume of solution L$

The normality of the solution is calculated by the formula,

$Normality=Molarity×Number of H+ or OH− ions$ .

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Answer 5

Chapter 15, Problem 81QAP

Interpretation Introduction

(a)

Interpretation:

The normality of the given solution is to be calculated.

$0.250 M$

$HCl$ .

Concept Introduction:

The atomic mass of an element is defined as the sum of number of protons and number of neutrons. Molar mass of an element is determined from atomic mass of an element.

The number of moles is calculated by the formula,

$Moles=MassgMolar mass$

The molarity is calculated by the formula,

$Molarity=Number of moles of soluteVolume of solution L$

The normality of the solution is calculated by the formula,

$Normality=Molarity×Number of H+ or OH− ions$ .

Interpretation Introduction

(b)

Interpretation:

The normality of the given solution is to be calculated.

$0.105 M$

$H2SO4$ .

Concept Introduction:

The atomic mass of an element is defined as the sum of number of protons and number of neutrons. Molar mass of an element is determined from atomic mass of an element.

The number of moles is calculated by the formula,

$Moles=MassgMolar mass$

The molarity is calculated by the formula,

$Molarity=Number of moles of soluteVolume of solution L$

The normality of the solution is calculated by the formula,

$Normality=Molarity×Number of H+ or OH− ions$ .

Interpretation Introduction

(c)

Interpretation:

The normality of the given solution is to be calculated.

$5.3×10−2 M$

$H3PO4$ .

Concept Introduction:

The atomic mass of an element is defined as the sum of number of protons and number of neutrons. Molar mass of an element is determined from atomic mass of an element.

The number of moles is calculated by the formula,

$Moles=MassgMolar mass$

The molarity is calculated by the formula,

$Molarity=Number of moles of soluteVolume of solution L$

The normality of the solution is calculated by the formula,

$Normality=Molarity×Number of H+ or OH− ions$ .

Answer 6

Chapter 15, Problem 81QAP

Interpretation Introduction

(a)

Interpretation:

The normality of the given solution is to be calculated.

$0.250 M$

$HCl$ .

Concept Introduction:

The atomic mass of an element is defined as the sum of number of protons and number of neutrons. Molar mass of an element is determined from atomic mass of an element.

The number of moles is calculated by the formula,

$Moles=MassgMolar mass$

The molarity is calculated by the formula,

$Molarity=Number of moles of soluteVolume of solution L$

The normality of the solution is calculated by the formula,

$Normality=Molarity×Number of H+ or OH− ions$ .

Answer 7

Chapter 15, Problem 81QAP

Interpretation Introduction

(a)

Interpretation:

The normality of the given solution is to be calculated.

$0.250 M$

$HCl$ .

Concept Introduction:

The atomic mass of an element is defined as the sum of number of protons and number of neutrons. Molar mass of an element is determined from atomic mass of an element.

The number of moles is calculated by the formula,

$Moles=MassgMolar mass$

The molarity is calculated by the formula,

$Molarity=Number of moles of soluteVolume of solution L$

The normality of the solution is calculated by the formula,

$Normality=Molarity×Number of H+ or OH− ions$ .

Answer 8

Interpretation Introduction

(b)

Interpretation:

The normality of the given solution is to be calculated.

$0.105 M$

$H2SO4$ .

Concept Introduction:

The atomic mass of an element is defined as the sum of number of protons and number of neutrons. Molar mass of an element is determined from atomic mass of an element.

The number of moles is calculated by the formula,

$Moles=MassgMolar mass$

The molarity is calculated by the formula,

$Molarity=Number of moles of soluteVolume of solution L$

The normality of the solution is calculated by the formula,

$Normality=Molarity×Number of H+ or OH− ions$ .

Answer 9

Interpretation Introduction

(b)

Interpretation:

The normality of the given solution is to be calculated.

$0.105 M$

$H2SO4$ .

Concept Introduction:

The atomic mass of an element is defined as the sum of number of protons and number of neutrons. Molar mass of an element is determined from atomic mass of an element.

The number of moles is calculated by the formula,

$Moles=MassgMolar mass$

The molarity is calculated by the formula,

$Molarity=Number of moles of soluteVolume of solution L$

The normality of the solution is calculated by the formula,

$Normality=Molarity×Number of H+ or OH− ions$ .

Answer 10

Interpretation Introduction

(c)

Interpretation:

The normality of the given solution is to be calculated.

$5.3×10−2 M$

$H3PO4$ .

Concept Introduction:

The atomic mass of an element is defined as the sum of number of protons and number of neutrons. Molar mass of an element is determined from atomic mass of an element.

The number of moles is calculated by the formula,

$Moles=MassgMolar mass$

The molarity is calculated by the formula,

$Molarity=Number of moles of soluteVolume of solution L$

The normality of the solution is calculated by the formula,

$Normality=Molarity×Number of H+ or OH− ions$ .

Answer 11

Interpretation Introduction

(c)

Interpretation:

The normality of the given solution is to be calculated.

$5.3×10−2 M$

$H3PO4$ .

Concept Introduction:

The atomic mass of an element is defined as the sum of number of protons and number of neutrons. Molar mass of an element is determined from atomic mass of an element.

The number of moles is calculated by the formula,

$Moles=MassgMolar mass$

The molarity is calculated by the formula,

$Molarity=Number of moles of soluteVolume of solution L$

The normality of the solution is calculated by the formula,

$Normality=Molarity×Number of H+ or OH− ions$ .

Answer 12

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Answer 23

Ch. 15.3 - ercise 15.1 A 1 35-g sample of seawater is...Ch. 15.3 - Prob. 15.2SC Ch. 15.4 - ercise 15.3 Calculate the molarity of a solution...Ch. 15.4 - ercise 15.4 Give the concentrations of the ions in...Ch. 15.4 - ercise 15.5 Calculate the number of moles of Cl...Ch. 15.4 - ercise 15.6 Formalin is an aqueous solution of...Ch. 15.5 - ercise 15.7 What volume of 12 M HCI must be taken...Ch. 15.6 - at if all ionic solids were soluble in water? How...Ch. 15.6 - Exercise 15.8 When aqueous solutions of Na2SO3 and...Ch. 15.7 - ercise 15.9 Calculate the volume of 0.10 M HNO3...

Solution Summary: The author explains that the atomic mass of an element is defined as the sum of protons and neutrons. The molarity of HCl solution is calculated by the formula.

Chapter 15 Solutions